Introduction to Linear Relations
Theory
A linear relation links two variables so that equal steps in one give equal steps in the other, and its points lie on a straight line. This Year 9 maths page revises the number plane, builds a table of values from a rule, finds the rule from a table, and plots the points to draw the line.
The number plane (Cartesian plane) has a horizontal \(x\)-axis and a vertical \(y\)-axis that cross at the origin \((0, 0)\). The axes split the plane into four quadrants.
A point is written as \((x, y)\). The \(x\)-coordinate comes first and says how far across (right is positive, left is negative). The \(y\)-coordinate says how far up or down (up is positive).
A rule is an equation that links two variables, such as \(y = 2x + 1\). Each \(x\)-value you put in gives one \(y\)-value out. A table of values lists some of these pairs; each pair is a point to plot.
A relation is linear when \(y\) changes by the same amount every time \(x\) goes up by \(1\). Then all its points lie on a straight line. In the rule \(y = mx + c\), that change is \(m\), the number multiplying \(x\), and \(c\) is the value of \(y\) when \(x = 0\).
Every point on the line fits the rule, including points between and beyond the ones in the table. That is why you can extend the line to read off new values.
When the \(x\)-values go up in steps of \(1\):
where \(m\) is the change in \(y\) for each step of \(1\) in \(x\), and \(c\) is the value of \(y\) when \(x = 0\).
| Pattern in the table | Rule |
|---|---|
| \(y\) goes up \(3\) each step; \(y = 1\) when \(x = 0\) | \(y = 3x + 1\) |
| \(y\) goes down \(4\) each step; \(y = 9\) when \(x = 0\) | \(y = 9 - 4x\) |
| \(y\) is always \(4\) more than \(x\) | \(y = x + 4\) |
How to complete a table of values
- Substitute each \(x\)-value into the rule, using brackets for negatives.
- Work out \(y\) and write it under its \(x\)-value.
- Check that the \(y\)-values change by the same amount each step.
How to find the rule from a table
- Find the step: how much \(y\) changes when \(x\) goes up by \(1\). This is the number multiplying \(x\) (negative if \(y\) goes down).
- Find the start: the value of \(y\) when \(x = 0\). Work backwards one step if the table does not show \(x = 0\).
- Write \(y = (\text{step})\,x + (\text{start})\) and test it on another pair.
How to graph the relation
- Plot each pair as a point \((x, y)\), across first.
- Rule a straight line through the points and extend it past both ends.
| \(x\) | \(-2\) | \(-1\) | \(0\) | \(1\) | \(3\) |
|---|---|---|---|---|---|
| \(y\) | \(a\) | \(b\) | \(c\) | \(d\) | \(e\) |
Substitute each \(x\)-value. Put the negative values in brackets.
| \(a\) | \(=\) | \(3 \times (-2) - 4 = -10\) |
| \(b\) | \(=\) | \(3 \times (-1) - 4 = -7\) |
| \(c\) | \(=\) | \(3 \times 0 - 4 = -4\) |
| \(d\) | \(=\) | \(3 \times 1 - 4 = -1\) |
| \(e\) | \(=\) | \(3 \times 3 - 4 = 5\) |
| \(x\) | \(-2\) | \(-1\) | \(0\) | \(1\) | \(3\) |
|---|---|---|---|---|---|
| \(y\) | \(-10\) | \(-7\) | \(-4\) | \(-1\) | \(5\) |
From \(x = -2\) to \(x = 1\) the \(y\)-values go up \(3\) each step, as the rule says. The jump from \(x = 1\) to \(x = 3\) is two steps, so \(y\) goes up \(6\).
| \(x\) | \(0\) | \(1\) | \(2\) | \(3\) | \(4\) |
|---|---|---|---|---|---|
| \(y\) | \(7\) | \(4\) | \(1\) | \(-2\) | \(-5\) |
(i) Find the rule linking \(x\) and \(y\).
(ii) Find \(y\) when \(x = 10\).
(i) Each time \(x\) goes up \(1\), \(y\) goes down \(3\), so the number multiplying \(x\) is \(-3\). When \(x = 0\), \(y = 7\).
| \(y\) | \(=\) | \(-3x + 7\) |
| \(\) | \(=\) | \(\boldsymbol{7 - 3x}\) |
Test it on another pair: \(x = 3\) gives \(7 - 9\) \(= -2\ \checkmark\)
(ii) Substitute \(x = 10\).
| \(y\) | \(=\) | \(7 - 3 \times 10\) |
| \(\) | \(=\) | \(\mathbf{-23}\) |
(i) Complete a table of values for \(y = 4 - x\) for \(x = 0\) to \(5\), and graph the line.
(ii) Where does the line cross each axis?
(iii) Does the point \((6, -2)\) lie on the line?
(i) Substitute each \(x\)-value: \(4 - 0 = 4\), \(4 - 1 = 3\), and so on.
| \(x\) | \(0\) | \(1\) | \(2\) | \(3\) | \(4\) | \(5\) |
|---|---|---|---|---|---|---|
| \(y\) | \(4\) | \(3\) | \(2\) | \(1\) | \(0\) | \(-1\) |
(ii) The line crosses the \(y\)-axis at \(\mathbf{(0, 4)}\) and the \(x\)-axis at \(\mathbf{(4, 0)}\). Both points are in the table.
(iii) Substitute \(x = 6\).
| \(y\) | \(=\) | \(4 - 6 = -2\ \checkmark\) |
The rule gives \(-2\), the \(y\)-coordinate of the point, so \((6, -2)\) is on the line. Extending the graph shows the same thing.
(i) Make a table for \(w = 0\) to \(4\) and write a rule for \(S\).
(ii) After how many weeks will he have $95?
(i) Start at \(15\) and add \(10\) each week.
| \(w\) | \(0\) | \(1\) | \(2\) | \(3\) | \(4\) |
|---|---|---|---|---|---|
| \(S\) | \(15\) | \(25\) | \(35\) | \(45\) | \(55\) |
\(S\) goes up \(10\) each week and starts at \(15\), so the rule is \(\boldsymbol{S = 10w + 15}\).
(ii) Put \(S = 95\) and solve.
| \(10w + 15\) | \(=\) | \(95\) |
| \(10w\) | \(=\) | \(80\) |
| \(w\) | \(=\) | \(\mathbf{8}\) |
Jai has $95 after \(8\) weeks. The graph gives the same answer: across from $95 to the line, then down to week \(8\).
Common pitfalls
Frequently asked questions
What is a linear relation?
A relation between two variables where \(y\) changes by the same amount each time \(x\) goes up by \(1\). Its points lie on a straight line, and its rule can be written as \(y = mx + c\).
How do you find the rule from a table of values?
Find how much \(y\) changes when \(x\) goes up by \(1\); that is the number multiplying \(x\). Then find \(y\) when \(x = 0\); that is the number added on. Test the rule on another pair.
How do you plot the point (x, y)?
Start at the origin. Move across by the \(x\)-coordinate (right if positive, left if negative), then up or down by the \(y\)-coordinate.
How can you tell if a table gives a straight line?
Check that the \(x\)-values go up in equal steps and the \(y\)-values change by the same amount each step. If they do, the points lie on a straight line.
How many points do you need to draw a straight line?
Two points fix a straight line. Plot a third as a check: if it is not in line with the other two, there is a mistake.