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Year 7 Maths Area and Volume

Volume of Rectangular Prism

20 practice questions 1 video lesson Theory + worked examples
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Theory

The volume of a solid is the amount of space it takes up, measured in cubic units. A rectangular prism holds \(l \times w\) unit cubes in each layer and has \(h\) layers, so \(V = l \times w \times h\). This Year 7 maths page shows counting in layers, the formula, base area times height and working backwards.

A cube with \(1\) cm edges has a volume of one cubic centimetre, \(1~\text{cm}^3\). The volume of a solid is the number of these unit cubes that fill it.

Count in layers. Find the number of cubes in the bottom layer, then multiply by the number of layers.

The formula. A rectangular prism \(l\) long and \(w\) wide has \(l \times w\) cubes in each layer and is \(h\) layers high, so \(V = l \times w \times h\).

Base area times height. \(l \times w\) is the area of the base, \(A\), so \(V = A \times h\) (written \(V = Ah\)). This works for any prism, because a prism has the same cross-section all the way up.

A cube has every edge the same length \(s\), so \(V = s \times s \times s\).

Working backwards. Substitute what you know, then divide: \(180 = 6 \times 5 \times h\) gives \(h = 180 \div 30 = 6\). For the edge of a cube, find the number that multiplies by itself three times to give \(V\).

Packing bigger cubes. Count how many fit along each edge, then multiply. A box \(12\) cm by \(8\) cm by \(6\) cm holds \(6 \times 4 \times 3 = 72\) cubes with \(2\) cm edges.

One layer of 12 unit cubes A layer of unit cubes 4 long and 3 deep: 12 cubes. 4 long 3 deep
One layer: \(4 \times 3 = 12\) cubes. Two layers like this make \(V = 12 \times 2 = 24~\text{cm}^3\).
Rectangular prism with base area A A rectangular prism with length l, width w and height h; the top face is shaded and marked A = l × w. l h w A = l × w
The top and the base have the same area \(A = l \times w\), so \(V = l \times w \times h = A \times h\).

Formulas:

\[ V = l \times w \times h \]
V = l × w × h
\[ V = A \times h \]
V = A × h ( base area times height )
\[ V = s \times s \times s \]
V = s × s × s ( cube )
Use one unit. For a box \(1.5\) m by \(40\) cm by \(20\) cm, change \(1.5\) m to \(150\) cm before you multiply.
Doubling every edge does not double the volume. Length, width and height all double, so the volume is \(2 \times 2 \times 2 = 8\) times bigger.

How to find the volume of a rectangular prism

  1. Change all three lengths to the same unit.
  2. Multiply length \(\times\) width \(\times\) height (or base area \(\times\) height).
  3. Write the answer in cubic units.

How to find a missing length

  1. Substitute into \(V = l \times w \times h\).
  2. Multiply the known lengths.
  3. Divide the volume by that product.
Example 1 — Counting cubes
This prism is built from \(1~\text{cm}^3\) cubes. Some cubes are hidden at the back. Find its volume.
Prism of unit cubes 5 long, 2 deep, 3 high A rectangular prism made of 1 cm cubes: 5 long, 2 deep and 3 layers high.
Solution
\(5 \times 2\)\(=\)\(10\)
\(10 \times 3\)\(=\)\(30\)
5×2=10 cubes in a layer ,10×3=30

\(30~\text{cm}^3\)

Example 2 — Using the formula
Find the volume of a rectangular prism \(9\) cm long, \(4\) cm wide and \(2.5\) cm high.
Rectangular prism 9 by 4 by 2.5 cm A rectangular prism 9 cm long, 4 cm wide and 2.5 cm high. 9 cm 2.5 cm 4 cm
Solution
\(9 \times 4 \times 2.5\)\(=\)\(36 \times 2.5\)
\(\)\(=\)\(90\)
9×4×2.5=36×2.5=90

\(90~\text{cm}^3\)

Example 3 — A sandpit
A sandpit is \(2\) m long and \(1.5\) m wide. It is filled with sand \(30\) cm deep. Sand costs \(\$60\) per cubic metre.
(i) Find the volume of sand in m\(^3\).
(ii) Find the cost of the sand.
Solution
\(30 \div 100\)\(=\)\(0.3\)
\(2 \times 1.5 \times 0.3\)\(=\)\(0.9\)
\(0.9 \times 60\)\(=\)\(54\)
30 cm =0.3 m ,2×1.5×0.3=0.9,0.9×60=54

(i) \(0.9~\text{m}^3\)
(ii) \(\$54\)

Example 4 — Working backwards
(i) A box has a volume of \(4200~\text{cm}^3\). It is \(20\) cm long and \(15\) cm wide. Find its height.
(ii) A cube has a volume of \(512~\text{cm}^3\). Find the length of one edge.
Solution
\(20 \times 15\)\(=\)\(300\)
\(4200 \div 300\)\(=\)\(14\)
\(8 \times 8 \times 8\)\(=\)\(512\)
20×15=300,4200÷300=148×8×8=512

(i) \(14\) cm (check: \(20 \times 15 \times 14 = 4200\))
(ii) \(8\) cm (\(9 \times 9 \times 9 = 729\) is too big)

Example 5 — Base area times height
The base of a rectangular prism has an area of \(35~\text{cm}^2\). The prism is \(6\) cm high. Find its volume.
Solution
\(35 \times 6\)\(=\)\(210\)
35×6=210

\(210~\text{cm}^3\)

Example 6 — Packing cubes
How many cubes with \(3\) cm edges fit exactly in a box \(12\) cm by \(9\) cm by \(6\) cm?
Solution
\(12 \div 3\)\(=\)\(4\)
\(9 \div 3\)\(=\)\(3\)
\(6 \div 3\)\(=\)\(2\)
\(4 \times 3 \times 2\)\(=\)\(24\)
4×3×2=24

\(24\) cubes. (Not \(648 \div 3\): each cube is \(27~\text{cm}^3\), and \(648 \div 27 = 24\).)

Example 7 — Mixed units
A storage tub is \(0.8\) m long, \(45\) cm wide and \(30\) cm high. Find its volume in cm\(^3\).
Solution
\(0.8 \times 100\)\(=\)\(80\)
\(80 \times 45 \times 30\)\(=\)\(108\,000\)
0.8 m =80 cm ,80×45×30=108000

\(108\,000~\text{cm}^3\)

Common pitfalls

Mixed units. Change every length to the same unit before multiplying.
Square units. Three lengths multiplied give cubic units: cm\(^3\), not cm\(^2\).
Forgetting hidden cubes. Count whole layers, not just the cubes you can see.
Dividing by the edge for packing. Count how many fit along each edge, then multiply.

Frequently asked questions

What is the formula for the volume of a rectangular prism?

\(V = l \times w \times h\).

What does V = Ah mean?

Volume equals the area of the base times the height.

How do you find the volume of a cube?

\(V = s \times s \times s\).

How do you find the height from the volume?

Divide the volume by length times width.

What happens to the volume if every edge doubles?

It becomes \(8\) times bigger.