Equation Problems
Every question with a fully worked solution.
- Equation Problems - Video - Solving Word Problem Using Equations Watch
Theory
To solve a word problem, turn the words into an equation, solve the equation, then answer the question in words. This Year 7 maths page sets out five steps for every problem and works through number puzzles, money, formulas, shapes, ages and sharing problems.
1. Define the pronumeral. Say what it stands for, with units: \(n\) = the number of tickets, \(l\) = the length in cm.
2. Write the equation. Turn the words into algebra one piece at a time. Words like is, gives, leaves and costs become \(=\).
3. Solve it. Use inverse operations on both sides, one step per line.
4. Answer in words, with units. “\(g = 12\)” becomes “She played \(12\) games.”
5. Check the answer in the words of the question, not just in your equation.
Formulas: write the formula, substitute the values you know, then solve for the one that is left. Two unknowns: write both with one pronumeral. If Sam is \(4\) years older than Ava, use \(x\) for Ava and \(x + 4\) for Sam.
Words to equations:
| Words | Equation |
|---|---|
| A number is doubled, then \(5\) is added. The result is \(19\). | \(2n + 5 = 19\) |
| \(7\) is taken away from a number tripled, leaving \(20\). | \(3n - 7 = 20\) |
| A number tripled is subtracted from \(50\), giving \(14\). | \(50 - 3n = 14\) |
| A \(\$5\) booking fee plus \(\$3\) per hour costs \(\$26\). | \(5 + 3h = 26\) |
| A rectangle with width \(6\) cm has a perimeter of \(40\) cm. | \(2l + 2 \times 6 = 40\) |
| A rectangle \(4\) cm wide and \((x + 3)\) cm long has an area of \(28\) cm². | \(4(x + 3) = 28\) |
Five steps for every problem
- Define the pronumeral, with units.
- Write the equation from the words.
- Solve it, one step per line.
- Answer in words, with units.
- Check in the words of the question.
Let \(n\) be the number.
| \(4n - 9\) | \(=\) | \(23\) |
| \(4n\) | \(=\) | \(32\) |
| \(n\) | \(=\) | \(8\) |
The number is \(8\). Check: \(4 \times 8 - 9 = 23\).
“Subtracted from \(30\)” means start with \(30\): \(30 - 4y = 18\).
| \(-4y\) | \(=\) | \(18 - 30 = -12\) |
| \(y\) | \(=\) | \(\dfrac{-12}{-4} = 3\) |
\(y = 3\). Check: \(30 - 4 \times 3 = 18\).
Let \(p\) be the number of pizzas.
| \(14p + 8\) | \(=\) | \(120\) |
| \(14p\) | \(=\) | \(112\) |
| \(p\) | \(=\) | \(8\) |
She ordered \(8\) pizzas. Check: \(14 \times 8 + 8 = 120\).
(ii) When \(t\) tables are joined in a row, the number of seats is \(S = 4t + 2\). How many tables seat \(42\) people?
| \(12\) | \(=\) | \(\dfrac{1}{2} \times 3 \times h\) |
| \(3h\) | \(=\) | \(24\) |
| \(h\) | \(=\) | \(8\) |
| \(4t + 2\) | \(=\) | \(42\) |
| \(t\) | \(=\) | \(40 \div 4 = 10\) |
(i) The height is \(8\) cm.
(ii) \(10\) tables
Let \(x\) be Mia’s cards; Tom has \(3x\).
| \(x + 3x\) | \(=\) | \(48\) |
| \(4x\) | \(=\) | \(48\) |
| \(x\) | \(=\) | \(12\) |
Mia has \(12\) cards and Tom has \(3 \times 12 = 36\). Check: \(12 + 36 = 48\).
(ii) A rectangle \(4\) cm wide and \((x + 3)\) cm long has an area of \(28\) cm². Find \(x\).
| \(2l + 2 \times 6\) | \(=\) | \(40\) |
| \(2l\) | \(=\) | \(28\) |
| \(l\) | \(=\) | \(14\) |
| \(4(x + 3)\) | \(=\) | \(28\) |
| \(x + 3\) | \(=\) | \(7\) |
| \(x\) | \(=\) | \(4\) |
(i) \(14\) cm
(ii) \(x = 4\), so the rectangle is \(7\) cm long.
(ii) A \(1.5\) L jug holds \(400\) mL of juice and the rest is water. How much water is in it?
| \(x + 18\) | \(=\) | \(4x\) |
| \(18\) | \(=\) | \(3x\) |
| \(x\) | \(=\) | \(6\) |
| \(400 + w\) | \(=\) | \(1500\) |
| \(w\) | \(=\) | \(1100\) |
(i) Sam is \(6\) (in \(18\) years he will be \(24 = 4 \times 6\)).
(ii) Change \(1.5\) L to \(1500\) mL first: \(1100\) mL of water.
Common pitfalls
Frequently asked questions
How do you turn a word problem into an equation?
Define a pronumeral, then turn the words into algebra piece by piece. Words like is and costs become \(=\).
What does subtracted from mean?
Start with the second number. \(4y\) subtracted from \(30\) is \(30 - 4y\).
How do you use a formula to find an unknown?
Substitute the values you know, then solve the equation for the one that is left.
How do you handle two unknowns?
Write both with one pronumeral, such as \(x\) and \(3x\).
Why should you check in the words of the question?
Your equation might be wrong; checking in the story catches that.