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Year 12 Maths - Methods (Unit 3 & Unit 4) Polynomial functions

Polynomials of higher degree

20 practice questions 0 video lessons Theory + worked examples
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Theory

A polynomial of degree \(n\), such as a quartic \(y=ax^{4}+\dots\), is sketched from its factored form: each real zero gives an \(x\)-intercept, and the multiplicity of a factor fixes the shape there — a single factor crosses, a double factor touches, and a triple factor flattens through. The end behaviour follows from the parity of the degree and the sign of the leading coefficient, and a degree-\(n\) polynomial has at most \(n\) \(x\)-intercepts and at most \(n-1\) turning points.

A polynomial is a sum of terms \(P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\dots+a_{1}x+a_{0}\) with whole-number powers. The degree \(n\) is the highest power and \(a_{n}\) (with \(a_{n}\neq 0\)) is the leading coefficient. Degree \(4\) is a quartic and degree \(5\) a quintic; the graph is always a single smooth, continuous curve with no breaks or corners.

The end behaviour — where the two arms of the curve point — is set by the leading term \(a_{n}x^{n}\), because it dominates for large \(|x|\). An even degree sends both ends the same way (both up if \(a_{n}>0\), both down if \(a_{n}<0\)); an odd degree sends the ends in opposite directions.

A repeated factor changes the shape at its \(x\)-intercept. The power of the factor is its multiplicity: a single factor \((x-r)\) crosses straight through, a double factor \((x-r)^{2}\) touches the axis and turns back like a parabola vertex, and a triple factor \((x-r)^{3}\) flattens and passes through as a stationary point of inflection. In total the graph has at most \(n\) \(x\)-intercepts and at most \(n-1\) turning points.

Key idea. Multiplicity decides the shape at a zero: odd multiplicity crosses the axis (a triple factor crosses but flattens first), while even multiplicity touches and turns back.
Quartic showing single, double and single factorsThe quartic y=0.35(x+2)(x-1)^2(x-3): it crosses the x-axis at x=-2, touches the axis at the double root x=1, and crosses again at x=3, with both ends pointing up. x y -2 1 3 cross touch cross
\(y=0.35(x+2)(x-1)^{2}(x-3)\): single roots cross at \(x=-2,3\); the double root touches at \(x=1\)
End behaviour of a quartic and its negativeA positive-leading quartic (both ends up) drawn in navy and the negative-leading quartic of the same shape (both ends down) in red. x y a > 0 a < 0
Even-degree end behaviour: with \(a>0\) both ends rise; with \(a<0\) both ends fall

General form — degree \(n\), leading coefficient \(a_{n}\neq 0\):

\[P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\dots+a_{1}x+a_{0}\]
P(x)=anxn+an1xn1++a1x+a0

Factored form — each factor gives a zero, its power is the multiplicity (the multiplicities sum to at most \(n\)):

\[P(x)=a(x-r_{1})^{m_{1}}(x-r_{2})^{m_{2}}\cdots(x-r_{k})^{m_{k}}\]
P(x)=a(xr1)m1(xrk)mk

End behaviour — the leading term dominates, so for large \(|x|\):

\[P(x)\approx a_{n}x^{n} \qquad \#\text{intercepts}\le n,\quad \#\text{turning points}\le n-1\]
P(x)anxn
Multiplicity rule. At a zero of multiplicity \(m\): \(m=1\) crosses, \(m=2\) touches and turns back, \(m=3\) flattens and crosses (a stationary point of inflection). Odd \(m\) crosses; even \(m\) touches.

Sketching a polynomial from its factored form

  1. End behaviour. Read off the degree \(n\) and the leading coefficient. Even degree → both ends the same way; odd degree → opposite ways; the sign of the leading coefficient sets up or down.
  2. \(x\)-intercepts. Set each factor to zero. Note the multiplicity of each zero from the power of its factor.
  3. Shape at each zero. Apply the multiplicity rule: single → cross, double → touch, triple → flatten through.
  4. \(y\)-intercept. Evaluate \(P(0)\) (multiply the constants) to fix where the curve meets the \(y\)-axis.
  5. Join smoothly. Draw one continuous curve that matches the ends and each intercept shape, using at most \(n-1\) turning points.
Sign-check tip. Between two consecutive distinct real zeros the value of \(P(x)\) keeps one sign, so the curve stays entirely above or below the axis there — a quick way to catch a mis-drawn arm.
Example 1 — end behaviour and parity
Describe the end behaviour of (a) \(y=x^{4}-4x^{2}\) and (b) \(y=-x^{5}+x\).
Solution
(a) \(y=x^{4}-4x^{2}\)
Leading term \(x^{4}\): degree \(4\) is even, coefficient \(+1>0\).
degree\(=\)\(4\ (\text{even})\)
leading coeff.\(=\)\(+1\)
\(\therefore\) both ends point up (as \(x\to\pm\infty,\ y\to+\infty\))
(b) \(y=-x^{5}+x\)
Leading term \(-x^{5}\): degree \(5\) is odd, coefficient \(-1<0\).
degree\(=\)\(5\ (\text{odd})\)
leading coeff.\(=\)\(-1\)
\(\therefore\) ends oppose: as \(x\to-\infty,\ y\to+\infty\); as \(x\to+\infty,\ y\to-\infty\)
y=x5+x
Example 2 — intercepts and their shapes
For \(y=(x+3)(x-1)^{2}(x-2)\), give the degree, the \(x\)-intercepts with the shape at each, and the \(y\)-intercept.
Solution
Degree — add the multiplicities \(1+2+1\):
degree\(=\)\(4\), leading coeff. \(+1\)
Zeros and multiplicities — set each factor to \(0\):
\(x=-3\)\(\to\)single \(\Rightarrow\) cross
\(x=1\)\(\to\)double \(\Rightarrow\) touch
\(x=2\)\(\to\)single \(\Rightarrow\) cross
\(y\)-intercept — put \(x=0\):
\(P(0)\)\(=\)\((3)(-1)^{2}(-2)=-6\)
\(\therefore\) quartic, ends both up; crosses at \(x=-3,2\), touches at \(x=1\); \(y\)-intercept \(-6\)
y=(x+3)(x1)2(x2)
Example 3 — sketch with a triple factor
Sketch \(y=(x+1)(x-2)^{3}\), showing the intercepts and their shapes.
Solution
End behaviour — degree \(1+3=4\) (even), leading coeff. \(+1\):
ends\(\to\)both up
Zeros — apply the multiplicity rule:
\(x=-1\)\(\to\)single \(\Rightarrow\) cross
\(x=2\)\(\to\)triple \(\Rightarrow\) flatten through
\(y\)-intercept — \(P(0)=(1)(-2)^{3}=-8\).
\(\therefore\) crosses at \(x=-1\), flattens through at \(x=2\), \(y\)-intercept \(-8\)
Quartic with a single and a triple factorThe quartic y=0.2(x+1)(x-2)^3 crosses the x-axis at x=-1 and flattens as it passes through the triple root at x=2. x y -1 2 cross triple
y=(x+1)(x2)3
Example 4 — two even factors
Sketch \(y=-(x+2)^{2}(x-3)^{2}\), and state where the graph lies relative to the \(x\)-axis.
Solution
End behaviour — degree \(2+2=4\) (even), leading coeff. \(-1<0\):
ends\(\to\)both down
Zeros — both factors are squared, so both are double:
\(x=-2\)\(\to\)double \(\Rightarrow\) touch
\(x=3\)\(\to\)double \(\Rightarrow\) touch
Sign — write \(y=-\big[(x+2)(x-3)\big]^{2}\); the bracket is squared, so:
\(\big[(x+2)(x-3)\big]^{2}\)\(\ge\)\(0\)
\(y=-\big[\,\cdots\,\big]^{2}\)\(\le\)\(0\)
\(\therefore\) the graph lies on or below the \(x\)-axis, touching at \(x=-2\) and \(x=3\); \(y\)-intercept \(P(0)=-(2)^{2}(-3)^{2}=-36\)
y=(x+2)2(x3)2

Common pitfalls

A double factor touches — it does not cross. At \((x-r)^{2}\) the curve meets the axis and turns back, like a parabola vertex. Even multiplicity touches; odd multiplicity crosses.
Even degree does not mean both ends up. The direction of the ends also depends on the sign of the leading coefficient: with \(a_{n}<0\) an even-degree graph has both ends pointing down.
A triple factor still crosses. \((x-r)^{3}\) flattens at \(x=r\) as a stationary point of inflection, but the curve does pass through the axis — do not draw it as a touch.

Frequently asked questions

What is a polynomial of higher degree?

A polynomial of higher degree is one whose highest power of \(x\) is four or more — a quartic has degree \(4\) and a quintic has degree \(5\). Its graph is a single smooth, continuous curve, and the degree sets the maximum number of \(x\)-intercepts and turning points.

How do you find the end behaviour of a polynomial?

Look at the leading term, since it dominates for large \(|x|\). The parity of the degree and the sign of the leading coefficient decide the ends: an even degree sends both ends the same way (up if the leading coefficient is positive, down if negative), while an odd degree sends the two ends opposite ways.

What does a repeated factor do to the graph of a polynomial?

The multiplicity of a factor fixes the shape at that \(x\)-intercept. A single factor gives a straight crossing, a double factor makes the curve touch and turn back like a parabola vertex, and a triple factor makes it flatten and pass through as a stationary point of inflection.

How many turning points can a polynomial have?

A polynomial of degree \(n\) has at most \(n-1\) turning points and at most \(n\) \(x\)-intercepts. For example a quartic (degree \(4\)) has at most \(3\) turning points and at most \(4\) \(x\)-intercepts, but it may have fewer of each.

How do you sketch a quartic from its factored form?

Fix the end behaviour from the even degree and the sign of the leading coefficient, set each factor to zero for the \(x\)-intercepts, apply the multiplicity rule at each one, mark the \(y\)-intercept by evaluating at \(x=0\), then join everything with a smooth curve having at most three turning points.

What is the difference between a double and a triple factor?

A double factor has even multiplicity, so the curve touches the axis and turns back without crossing. A triple factor has odd multiplicity, so the curve crosses, but it flattens as it does so, forming a stationary point of inflection.