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Year 9 Maths Geometry

Similar Triangles

20 practice questions 4 video lessons Theory + worked examples
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  • Similar Triangles - Video - Tests For Similar Triangles SSS Watch
  • Similar Triangles - Video - Tests For Similar Triangles SAS Watch
  • Similar Triangles - Video - Tests For Similar Triangles AAA Watch
  • Similar Triangles - Video - Tests For Similar Triangles RHS Watch
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Theory

Two triangles are similar if they pass one of four tests for similar triangles: SSS, SAS, AA or RHS. This Year 9 maths page shows how to choose the right test from what is marked, find equal angles hidden in a figure, and then use the scale factor to find an unknown length, including heights found from shadows and ladders.

To prove two triangles are similar, you do not need to check every angle and every side. One of four tests is enough.

SSS: all three pairs of sides are in the same ratio.

SAS: two pairs of sides are in the same ratio, and the included angles (the angles between those sides) are equal.

AA: two pairs of angles are equal. The third pair must then be equal too, because the angles in a triangle add to \(180^\circ\). Such triangles are called equiangular.

RHS: both triangles are right-angled, and the hypotenuses and one other pair of sides are in the same ratio.

Once two triangles are proved similar, write a similarity statement with the vertices in matching order, find the scale factor, and use it to find unknown sides.

The four tests for similar trianglesFour small triangles. SSS: all three sides marked, in the same ratio. SAS: two sides marked with the angle between them. AA: two angles marked. RHS: a right angle, the hypotenuse in red and one other side marked. SSS 3 sides in the same ratio SAS 2 sides in ratio, included angle equal AA 2 angles equal (equiangular) RHS hypotenuse and a side in ratio
Choose the test from what is marked: three sides (SSS), two sides and the angle between them (SAS), two angles (AA), or a right angle with the hypotenuse and one side (RHS).
Where equal angles come fromLeft: a triangle cut by a line parallel to its base; the angle at the top is shared and the parallel line makes equal corresponding angles. Right: two triangles meeting at a point with parallel outer sides; the angles at the meeting point are vertically opposite and the angles at the outer ends are alternate. shared angle vertically opposite
Equal angles usually come from a shared angle, parallel lines (corresponding or alternate angles), vertically opposite angles, or two right angles.
TestWhat you need to show
SSS\(\dfrac{a'}{a} = \dfrac{b'}{b} = \dfrac{c'}{c}\)
SAStwo side ratios equal, and the angles between those sides equal
AAtwo pairs of equal angles
RHSa right angle in each, and \(\dfrac{\text{hyp}'}{\text{hyp}} = \dfrac{\text{side}'}{\text{side}}\)
Finding the equal angles. In a figure, equal angles usually come from: an angle shared by both triangles; parallel lines (corresponding or alternate angles); vertically opposite angles where two lines cross; or two right angles. Always give the reason.
AA with numbers. If one triangle has angles of \(54^\circ\) and \(71^\circ\), its third angle is \(180^\circ - 54^\circ - 71^\circ = 55^\circ\). Any other triangle with two of these angles has the same three angles, so the two are similar by AA.
Harder figures. In a right-angled triangle the two other angles add to \(90^\circ\), so a line from the right angle perpendicular to the hypotenuse makes two smaller triangles that share those angles and are similar to the whole. A ratio of parts can give a ratio of pieces: if \(PT : PR = 2 : 5\), then \(PT : TR = 2 : 3\). If the unknown appears twice, as in \(\dfrac{x}{2} = \dfrac{8}{x}\), multiply out: \(x^2 = 16\), so \(x = 4\).
An unknown in a side. For SAS with sides written in \(x\), set the two ratios equal and cross-multiply. For example, \(\dfrac{x + 2}{x} = \dfrac{3}{2}\) gives \(2x + 4 = 3x\), so \(x = 4\).

How to prove triangles similar and find a length

  1. Look at what is marked or given: sides, angles, right angles, parallel lines.
  2. Choose the test: three sides (SSS), two sides and the angle between them (SAS), two angles (AA), or a right angle with the hypotenuse and a side (RHS).
  3. Show the test holds: divide matching sides (matched by size), or state each pair of equal angles with a reason.
  4. Write the similarity statement with the vertices in matching order.
  5. Use the scale factor to find the unknown side.

Real problems

  1. Shadows: at the same moment the sun makes the same angle for every object, and both stand at right angles to the ground, so the triangles are similar (AA). Height matches height and shadow matches shadow.
  2. Ladders, cables and ramps at the same angle to the ground make similar right-angled triangles with the wall or pole.
  3. Write the unknown on top: \(\dfrac{h}{\text{its match}} = \dfrac{\text{known}}{\text{its match}}\). A \(1.2\) m post with a \(0.9\) m shadow and a building with a \(15\) m shadow give \(\dfrac{h}{1.2} = \dfrac{15}{0.9}\), so \(h = 20\) m.
  4. Not similar? One ratio that differs is enough to show it. Two equal ratios are not enough for SSS: check the third pair too.
Example 1 — Three sides (SSS)
One triangle has sides \(6, 7\) and \(9\). Another has sides \(12, 14\) and \(18\). Are they similar? Which test proves it?
Solution
Triangles with sides 6, 7, 9 and 12, 14, 18A navy triangle with sides 6, 7 and 9 and a larger red triangle with sides 12, 14 and 18, drawn to the same shape. 9 6 7 18 12 14

Put both sets in order, pair smallest with smallest, and divide.

\(\dfrac{12}{6}\)\(=\)\(2\)
\(\dfrac{14}{7}\)\(=\)\(2\)
\(\dfrac{18}{9}\)\(=\)\(2\)
126=147=189=2

All three ratios are equal, so the triangles are similar by SSS. No angle was needed.

Example 2 — Two sides and the included angle (SAS)
One triangle has sides \(6\) cm and \(10\) cm with a \(70^\circ\) angle between them. Another has sides \(9\) cm and \(15\) cm with a \(70^\circ\) angle between them. Are they similar?
Solution
Two triangles with an included angle of 70 degreesA navy triangle with sides 6 cm and 10 cm meeting at a 70 degree angle, and a red triangle with sides 9 cm and 15 cm meeting at a 70 degree angle. 10 cm 6 cm 15 cm 9 cm 70° 70°

Pair the sides by size and divide. Then check the angle is the one between the two sides in both triangles.

\(\dfrac{9}{6}\)\(=\)\(1.5\)
\(\dfrac{15}{10}\)\(=\)\(1.5\)
96=1510=1.5

Two pairs of sides are in the same ratio and the included angles are both \(70^\circ\). The triangles are similar by SAS.

Example 3 — Right-angled triangles (RHS)
Two right-angled triangles have hypotenuses \(30\) and \(18\), and a second pair of sides \(25\) and \(15\). Which test proves them similar?
Solution
Two right-angled trianglesA navy right-angled triangle with hypotenuse 30 and a side of 25, and a smaller red right-angled triangle with hypotenuse 18 and a side of 15. 30 25 18 15

Compare hypotenuse with hypotenuse, then the second pair of sides.

\(\dfrac{18}{30}\)\(=\)\(\dfrac{3}{5}\)
\(\dfrac{15}{25}\)\(=\)\(\dfrac{3}{5}\)
1830=1525=35

Both triangles have a right angle, and the two ratios agree. The test is RHS.

Example 4 — Prove, then find a length
\(AE\) and \(BD\) cross at \(C\), with \(AB \parallel DE\). \(AC = 4\), \(CE = 10\) and \(AB = 6\). Show that \(\triangle ABC \sim \triangle EDC\), then find \(DE\).
Solution
Two triangles meeting at CSegments AE and BD cross at C, with AB parallel to DE. Triangle ABC has AC = 4 and AB = 6. Triangle EDC has CE = 10 and DE unknown. The angles at C and the angles at A and E are marked equal. Drawn to scale. A B C E D 4 6 10 ?

Find two pairs of equal angles, giving a reason for each.

\(\angle ACB\)\(=\)\(\angle ECD\) (vertically opposite)
\(\angle BAC\)\(=\)\(\angle DEC\) (alternate, \(AB \parallel DE\))

So \(\triangle ABC \sim \triangle EDC\) by AA. \(AC\) matches \(EC\), and \(AB\) matches \(ED\).

\(k\)\(=\)\(\dfrac{CE}{CA} = \dfrac{10}{4} = 2.5\)
\(DE\)\(=\)\(6 \times 2.5\)
\(\)\(=\)\(\mathbf{15}\)
DE=6×2.5=15

Common pitfalls

SAS needs the included angle. The equal angle must sit between the two sides you compared. An angle elsewhere does not prove similarity.
Match sides by size. Pair shortest with shortest and longest with longest before dividing, whichever way the triangles are drawn.
Give a reason for every angle. Write “vertically opposite”, “alternate angles, \(AB \parallel DE\)” or “shared angle”, not just “equal”.
Write the letters in matching order. If \(A\) matches \(E\), then \(A\) and \(E\) must be in the same position in the statement.

Frequently asked questions

What are the four tests for similar triangles?

SSS: three pairs of sides in the same ratio. SAS: two pairs of sides in the same ratio with equal included angles. AA: two pairs of equal angles. RHS: right-angled triangles with the hypotenuses and one other pair of sides in the same ratio.

What is the AA similarity test?

If two angles of one triangle equal two angles of another, the triangles are similar. The third angles are then equal too, because each triangle's angles add to \(180^\circ\).

What is the difference between SAS for similar and congruent triangles?

For congruent triangles the two pairs of sides must be equal. For similar triangles they only need to be in the same ratio. In both, the angle between the sides must be equal.

How do you know which similarity test to use?

Use what the diagram gives you. Three sides: SSS. Two sides and the angle between them: SAS. Two angles: AA. A right angle with the hypotenuse and another side: RHS.

How do you find a missing side once triangles are similar?

Write the similarity statement in matching order, find the scale factor from a pair of matching sides you know, and multiply the matching side by it.