Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 7 Maths Decimals

Multiplying with Decimals

20 practice questions 1 video lesson Theory + worked examples
Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 1 video(s)
  • Multiplying with Decimals - Video - Multiply a Decimal by a Decimal Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

To multiply decimals, multiply the numbers without the decimal points, then count the decimal places in the question to put the point back in. The total number of decimal places in the question equals the number in the answer. This Year 7 maths page shows why this works and how to use it for money, areas and longer products.

Step 1. Multiply without the decimal points. For \(0.6 \times 0.04\), work out \(6 \times 4 = 24\).

Step 2. Count the decimal places in both numbers: \(0.6\) has \(1\) and \(0.04\) has \(2\), so the answer has \(1 + 2 = 3\).

Step 3. Put the point in: \(3\) places means \(\div 1000\), so \(24 \div 1000 = 0.024\). Write zeros in front when there are not enough digits.

Why it works: tenths times tenths make hundredths. \(0.6 \times 0.4\) is \(6 \times 4 = 24\) hundredths, which is \(0.24\).

Area model for 0.6 times 0.4 A unit square split into 100 small squares. A strip 0.6 wide is shaded orange and a strip 0.4 tall is shaded blue. They overlap in a red rectangle of 6 by 4, which is 24 small squares. 0.60.4
Each small square is \(0.01\). The overlap is \(6 \times 4 = 24\) squares, so \(0.6 \times 0.4 = 0.24\).

Places in the question \(=\) places in the answer:

QuestionDigits, placesAnswer
\(0.32 \times 0.02\)\(64\), \(2 + 2 = 4\)\(0.0064\)
\(1.1 \times 0.05\)\(55\), \(1 + 2 = 3\)\(0.055\)
\(1.23 \times 0.2\)\(246\), \(2 + 1 = 3\)\(0.246\)

Multiplying by a number between \(0\) and \(1\) makes a positive number smaller:

\[ 20 \times 1.5 = 30, \quad 20 \times 0.5 = 10 \]
20×1.5=30,20×0.5=10
\[ 20 \times 0.1 = 2 \]
20×0.1=2
Estimate first. \(4.8 \times 2.1 \approx 5 \times 2 = 10\), and the exact answer \(10.08\) is close.
Count before dropping end zeros. \(2.5 \times 0.4\): \(25 \times 4 = 100\) with \(2\) places is \(1.00 = 1\), not \(0.1\).

How to multiply decimals

  1. Estimate the answer.
  2. Multiply the numbers as if there were no decimal points.
  3. Count the decimal places in both numbers and add them.
  4. Place the point that many places from the right, writing zeros in front if needed. Check with the estimate.
Example 1 — Counting places
Calculate
(i) \(0.32 \times 0.02\)
(ii) \(1.1 \times 0.05\)
Solution

(i) \(32 \times 2 = 64\); places \(2 + 2 = 4\).
(ii) \(11 \times 5 = 55\); places \(1 + 2 = 3\).

\(0.32 \times 0.02\)\(=\)\(0.0064\)
\(1.1 \times 0.05\)\(=\)\(0.055\)
0.32×0.02=0.0064,1.1×0.05=0.055

(i) \(0.0064\)
(ii) \(0.055\)

Example 2 — Decimal times whole number
Calculate
(i) \(0.6 \times 7\)
(ii) \(2.35 \times 4\)
Solution
\(0.6 \times 7\)\(=\)\(4.2\)
\(2.35 \times 4\)\(=\)\(9.40 = 9.4\)
0.6×7=4.2,2.35×4=9.4

(i) \(6\) tenths \(\times 7 = 42\) tenths \(= 4.2\)
(ii) \(235 \times 4 = 940\), \(2\) places: \(9.40 = 9.4\)

Example 3 — Zeros in front
Calculate
(i) \(1.6 \times 0.3\)
(ii) \(0.8 \times 0.07\)
Solution
\(1.6 \times 0.3\)\(=\)\(48 \div 100 = 0.48\)
\(0.8 \times 0.07\)\(=\)\(56 \div 1000 = 0.056\)
1.6×0.3=0.48,0.8×0.07=0.056

(ii) needs \(3\) places, so write a zero in front of \(56\).

Example 4 — Buying cheese
Cheese costs \(\$14.50\) per kilogram. How much do \(0.6\) kg cost?
Solution
\(6 \times 145\)\(=\)\(870\)
\(0.6 \times 14.5\)\(=\)\(870 \div 100 = 8.7\)
6×145=870,0.6×14.5=8.7

Estimate \(0.6 \times 15 = 9\). The cheese costs \(\$8.70\).

Example 5 — Long multiplication
Oscar buys \(3.8\) m of timber at \(\$6.45\) per metre. What does it cost?
Solution
\(645 \times 38\)\(=\)\(645 \times 30 + 645 \times 8\)
\(\)\(=\)\(19\,350 + 5160\)
\(\)\(=\)\(24\,510\)
645×38=19350+5160=24510

Places \(1 + 2 = 3\), so \(3.8 \times 6.45 = 24.510\). Estimate \(4 \times 6.5 = 26\). It costs \(\$24.51\).

Example 6 — Area of a rectangle
A rectangular sign is \(1.5\) m long and \(0.6\) m wide. Find its area.
Solution
\(15 \times 6\)\(=\)\(90\)
\(1.5 \times 0.6\)\(=\)\(90 \div 100 = 0.9\)
15×6=90,1.5×0.6=0.9

The area is \(0.9\) m\(^2\). Count the places before dropping the end zero.

Common pitfalls

Counting the places in only one number. \(0.2 \times 0.9 = 0.18\), not \(1.8\): the answer needs \(1 + 1 = 2\) places.
Forgetting zeros in front. \(0.03 \times 0.2\): \(3 \times 2 = 6\) needs \(3\) places, so the answer is \(0.006\).
Dropping end zeros too early. \(2.5 \times 0.4 = 1.00 = 1\), not \(0.1\).
Expecting a bigger answer. \(35 \times 0.6\) is less than \(35\), because \(0.6 < 1\).

Frequently asked questions

How do you multiply two decimals?

Multiply without the points, then count the decimal places in both numbers. \(1.6 \times 0.3 = 0.48\).

Why do tenths times tenths give hundredths?

On a grid, \(0.6\) by \(0.4\) covers \(24\) of the \(100\) small squares, so it is \(0.24\).

What if there are not enough digits for the point?

Write zeros in front. \(0.8 \times 0.07 = 0.056\).

Does multiplying by 0.5 make a number bigger?

No. It halves it. \(20 \times 0.5 = 10\).

How do you check a decimal product?

Estimate by rounding. \(4.8 \times 2.1 \approx 10\), so \(10.08\) makes sense.