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Year 7 Maths Algebra and Equations

2 Step Equations

20 practice questions 1 video lesson Theory + worked examples
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Theory

A two-step equation needs two inverse operations to get the pronumeral on its own: undo the \(+\) or \(-\) first, then undo the \(\times\) or \(\div\). This Year 7 maths page shows the balancing and backtracking methods, negative and decimal answers, and equations from everyday stories.

Think about how the equation was built. In \(3x + 4 = 22\), \(x\) was multiplied by \(3\), then \(4\) was added.

To solve it, undo those operations in reverse order, using the inverse operation each time. Step 1. Undo adding \(4\): subtract \(4\) from both sides, giving \(3x = 18\). Step 2. Undo multiplying by \(3\): divide both sides by \(3\), giving \(x = 6\).

The balancing method does the same thing to both sides, so the equation stays balanced. The backtracking method uses a flow chart and undoes each operation in reverse order.

Check by substitution: if LHS \(=\) RHS, the answer is correct. The answer can be negative, a decimal or a fraction.

Building and undoing 3x + 4 = 22 Flow chart: x, times 3, gives 3x, add 4, gives 22. Underneath, the inverse arrows go back: subtract 4 gives 18, divide by 3 gives 6. x 3x 22 × 3 ÷ 3 + 4 − 4
Build: multiply by \(3\), then add \(4\). Undo in reverse: \(22 - 4 = 18\), then \(18 \div 3 = 6\). So \(x = 6\).

Two steps, in reverse order:

EquationStep 1Step 2Solution
\(5x + 1 = 21\)\(-\,1\)\(\div 5\)\(x = 4\)
\(2x - 9 = 3\)\(+\,9\)\(\div 2\)\(x = 6\)
\(\dfrac{x}{3} + 1 = 6\)\(-\,1\)\(\times 3\)\(x = 15\)
\(8 - 3x = -10\)\(-\,8\)\(\div (-3)\)\(x = 6\)
A fraction x term. In \(\dfrac{3x}{4} + 2 = 11\), undo the \(+\,2\) first: \(\dfrac{3x}{4} = 9\), then \(3x = 36\), then \(x = 12\).
Pronumeral on the right. Solve the same way, then write the answer with the pronumeral on the left.

How to solve a two-step equation

  1. Undo the \(+\) or \(-\): do the inverse to both sides.
  2. Undo the \(\times\) or \(\div\): do the inverse to both sides.
  3. Write one step per line.
  4. Check by substituting into the original equation.
Example 1 — Two methods
Solve \(\dfrac{x}{4} + 3 = 5\).
Solution

Balancing method: subtract \(3\) from both sides, then multiply both sides by \(4\).

\(\dfrac{x}{4} + 3 - 3\)\(=\)\(5 - 3\)
\(\dfrac{x}{4}\)\(=\)\(2\)
\(x\)\(=\)\(2 \times 4 = 8\)
x /4+3−3=5−3, x /4=2, x =8

Backtracking method: undo “\(+ 3\)” by subtracting \(3\), then undo “\(\div 4\)” by multiplying by \(4\): \(x = (5 - 3) \times 4 = 8\). Check: \(\dfrac{8}{4} + 3 = 5\).

Example 2 — Pronumeral on the right
Solve \(29 = 5x + 4\).
Solution
\(29 - 4\)\(=\)\(5x\)
\(25\)\(=\)\(5x\)
\(x\)\(=\)\(\dfrac{25}{5} = 5\)
29−4=5 x ,25=5 x , x =5

Check: \(5 \times 5 + 4 = 29\). So \(x = 5\).

Example 3 — Negative answers and dividing
Solve
(i) \(6m - 5 = -23\)
(ii) \(\dfrac{x}{4} - 2 = 5\)
Solution
\(6m\)\(=\)\(-23 + 5 = -18\)
\(m\)\(=\)\(\dfrac{-18}{6} = -3\)
\(\dfrac{x}{4}\)\(=\)\(5 + 2 = 7\)
\(x\)\(=\)\(7 \times 4 = 28\)
6 m =−18, m =−3 x /4=7, x =28

(i) \(m = -3\). Check: \(6 \times (-3) - 5 = -23\).
(ii) \(x = 28\). Check: \(7 - 2 = 5\).

Example 4 — A negative x term
Solve \(7 - 2x = 12\).
Solution

The \(x\) term is \(-2x\). Subtract \(7\) from both sides, then divide both sides by \(-2\).

\(-2x\)\(=\)\(12 - 7 = 5\)
\(x\)\(=\)\(\dfrac{5}{-2} = -2.5\)
−2 x =5, x =5/(−2)=−2.5

Check: \(7 - 2 \times (-2.5) = 7 + 5 = 12\). So \(x = -2.5\).

Example 5 — A fraction x term
Solve \(\dfrac{3x}{4} + 2 = 11\).
Solution
\(\dfrac{3x}{4}\)\(=\)\(11 - 2 = 9\)
\(3x\)\(=\)\(9 \times 4 = 36\)
\(x\)\(=\)\(\dfrac{36}{3} = 12\)
3 x /4=9,3 x =36, x =12

Check: \(\dfrac{3 \times 12}{4} + 2 = 9 + 2 = 11\). So \(x = 12\).

Example 6 — Netball fees
A netball club charges a \(\$25\) joining fee plus \(\$8\) for each game. Ava paid \(\$105\). Let \(g\) be the number of games, so \(8g + 25 = 105\). How many games did Ava play?
Solution
\(8g\)\(=\)\(105 - 25 = 80\)
\(g\)\(=\)\(\dfrac{80}{8} = 10\)
8 g =80, g =10

Ava played \(10\) games. Check: \(8 \times 10 + 25 = 105\).

Example 7 — Bike hire
Hiring a bike costs a \(\$3.50\) booking fee plus \(\$6.25\) for every hour. Leo pays \(\$28.50\). For how many hours did he hire the bike?
Solution
\(6.25h + 3.5\)\(=\)\(28.5\)
\(6.25h\)\(=\)\(25\)
\(h\)\(=\)\(25 \div 6.25 = 4\)
6.25 h +3.5=28.5,6.25 h =25, h =4

Leo hired the bike for \(4\) hours. Check: \(6.25 \times 4 + 3.50 = 28.50\).

Common pitfalls

Dividing first. In \(3x + 4 = 22\), do not start by dividing \(22\) by \(3\). Subtract \(4\) first.
Changing one side only. Subtracting \(4\) from the left only breaks the balance: \(3x = 22\) is wrong.
Losing the sign of the x term. In \(8 - 3x = -10\), the \(x\) term is \(-3x\). After subtracting \(8\), divide by \(-3\), not \(3\).
Skipping the check. Substitute the answer into the original equation every time.

Frequently asked questions

What is a two-step equation?

An equation that needs two inverse operations to solve, such as \(3x + 4 = 22\).

Which step do you undo first?

The \(+\) or \(-\) first, then the \(\times\) or \(\div\): the reverse of how the equation was built.

How do you solve 3x + 4 = 22?

Subtract \(4\) from both sides (\(3x = 18\)), then divide by \(3\): \(x = 6\).

Can the answer be a decimal?

Yes. \(7 - 2x = 12\) gives \(x = -2.5\).

How do you check a solution?

Substitute it into the original equation. Both sides must be equal.