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Year 10 Maths - 10 Geometry

Similar Figures

20 practice questions 1 video lesson Theory + worked examples
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Theory

Similar figures have the same shape but not necessarily the same size. This Year 10 maths page revises how to find a scale factor, use it to find unknown sides and perimeters, decide whether two figures are similar, write a similarity statement in matching order, and work with scale drawings, plans and maps.

Two figures are similar if one is an enlargement or reduction of the other. Matching angles are equal, and matching sides are all in the same ratio.

The scale factor \(k\) is the number every length is multiplied by: \(k = \dfrac{\text{image length}}{\text{original length}}\). If \(k > 1\) the figure is enlarged; if \(0 < k < 1\) it is reduced.

The symbol \(|||\) means "is similar to". In \(ABCD \,|||\, WXYZ\) the vertices are in matching order, so \(A \leftrightarrow W\), \(B \leftrightarrow X\), and side \(BC\) matches side \(XY\).

A scale drawing, plan, model or map is similar to the real object. Its scale \(1 : n\) means \(1\) unit on the drawing stands for \(n\) of the same units in real life.

The perimeter of a similar figure is also multiplied by \(k\). Area is not: work out each length first, then the area.

A figure and its enlargementA small quadrilateral with sides 4 and 2.5 and a similar quadrilateral twice as big, with matching sides 8 and 5. The angles are unchanged. 4 2.5 8 5 original image, scale factor 2
Similar figures: every length is multiplied by the same scale factor, and the angles stay the same.
Converting units for a scaleBoxes for centimetres, metres and kilometres. To go right, divide by 100 then by 1000; to go left, multiply. A scale of 1 to 25 000 means 1 cm on the map is 25 000 cm, which is 250 m or 0.25 km. cm m km ÷ 100 × 100 ÷ 1000 × 1000 Scale 1 : 25 000 1 cm on the map = 25 000 cm real = 250 m = 0.25 km
A scale ratio uses the same unit on both sides. Change units after you multiply or divide.

Scale factor from the original to the image:

\[k = \dfrac{\text{image length}}{\text{matching original length}}\]
k=image lengthoriginal length
\[\text{image length} = k \times \text{original} \qquad \text{original length} = \dfrac{\text{image}}{k}\]
image=k×original
Scale \(1 : n\)Rule
drawing \(\to\) realmultiply by \(n\), then change units
real \(\to\) drawingchange to the drawing unit (usually cm), then divide by \(n\)
finding \(n\)same units, then real \(\div\) drawing
units\(1\text{ m} = 100\text{ cm}\), \(1\text{ km} = 1000\text{ m} = 100\,000\text{ cm}\)
Ratios such as \(1 : 2\). A flag with height : length \(= 2 : 3\) and length \(1.5\) m has height \(1.5 \times \dfrac{2}{3} = 1\) m.
Two scale factors in a row. An enlargement by \(1.2\) followed by a reduction by \(0.75\) is one scale factor of \(1.2 \times 0.75 = 0.9\).
Are the figures similar? Compare every pair of matching sides, shortest with shortest and longest with longest. A \(6 \times 9 \times 15\) cm box and an \(8 \times 12 \times 21\) cm box are not similar: \(\dfrac{8}{6} = \dfrac{12}{9} = \dfrac{4}{3}\), but \(\dfrac{21}{15} = \dfrac{7}{5}\). For the boxes to be similar, the last length would need to be \(15 \times \dfrac{4}{3} = 20\) cm.
Sides written with a pronumeral. If a \((x + 3)\) by \((2x + 1)\) rectangle is similar to a \(3\) by \(5\) rectangle, with the shorter sides matching, then \(\dfrac{x + 3}{2x + 1} = \dfrac{3}{5}\). Cross-multiply: \(5x + 15 = 6x + 3\), so \(x = 12\) and the rectangle is \(15\) by \(25\).
Areas on a plan. Change each real length to a plan length first, then multiply. Do not divide the real area by \(n\).

How to find an unknown side in similar figures

  1. Match the sides, using the similarity statement, the angles or the position in the diagram. Turned or flipped figures need care.
  2. Find the scale factor from one pair of matching sides where both lengths are known.
  3. Multiply by \(k\) to go to the image, or divide by \(k\) to go back to the original.
  4. Check that the larger figure has the larger answer.

How to decide whether figures are similar

  1. Order the sides of each figure from shortest to longest (or use the angles to match them).
  2. Divide each side of one figure by the matching side of the other.
  3. Compare: if every ratio is the same (and the angles match), the figures are similar. One different ratio means they are not.

How to use a scale \(1 : n\)

  1. Decide the direction: drawing to real (multiply) or real to drawing (divide).
  2. Keep the same unit until the multiplying or dividing is done.
  3. Convert to the unit asked for, such as m or km.
Example 1 — Scale factor and missing sides
\(ABCD \,|||\, WXYZ\). \(AB = 5\) cm, \(BC = 6\) cm, \(WX = 7\) cm and \(ZW = 9.8\) cm. Find:
(i) the scale factor
(ii) \(XY\)
(iii) \(DA\)
Solution
Similar quadrilaterals ABCD and WXYZQuadrilateral ABCD with AB 5 and BC 6. A larger similar quadrilateral WXYZ with WX 7 and ZW 9.8. XY and DA are unknown. Not to scale. A B C D W X Y Z 5 6 DA 7 XY 9.8

The letters match in order: \(AB \leftrightarrow WX\), \(BC \leftrightarrow XY\), \(DA \leftrightarrow ZW\).

\(k\)\(=\)\(\dfrac{\text{image}}{\text{original}} = \dfrac{WX}{AB} = \dfrac{7}{5} = \mathbf{1.4}\)
\(XY\)\(=\)\(6 \times 1.4 = \mathbf{8.4}\text{ cm}\)
\(DA\)\(=\)\(9.8 \div 1.4 = \mathbf{7}\text{ cm}\)
k=75=1.4

Going to the larger figure, multiply. Going back to the smaller figure, divide.

Example 2 — Map scales
A map has a scale of \(1 : 25\,000\).
(i) A track measures \(9.2\) cm on the map. How long is the real track, in km?
(ii) Two huts are \(1.5\) km apart. How far apart are they on the map?
Solution
Map with a walking track and a scaleA map showing a dashed track from a car park to a lookout, measuring 9.2 cm. The scale is 1 to 25 000, and a scale bar shows 0, 0.5 km and 1 km. car park lookout 9.2 cm on the map 0 0.5 km 1 km 1 : 25 000

(i) Map to real: multiply by \(25\,000\), then change units.

\(9.2 \times 25\,000\)\(=\)\(230\,000\text{ cm}\)
\(\)\(=\)\(2300\text{ m}\)
\(\)\(=\)\(\mathbf{2.3}\text{ km}\)

(ii) Real to map: change to cm first, then divide by \(25\,000\).

\(1.5\text{ km}\)\(=\)\(150\,000\text{ cm}\)
\(150\,000 \div 25\,000\)\(=\)\(\mathbf{6}\text{ cm}\)
9.2×25000=230000cm=2.3km
Example 3 — Finding the scale
On a floor plan, a wall that is really \(12\) m long is drawn \(8\) cm long.
(i) Write the scale as \(1 : n\).
(ii) A doorway is \(0.6\) cm wide on the plan. How wide is the real doorway?
Solution
A floor plan with a wall and a doorwayA rectangular room on a plan. The long wall is 8 cm on the plan and 12 m in real life. A doorway on the plan is 0.6 cm wide. door 0.6 cm 8 cm on the plan = 12 m real

(i) Write both lengths in the same unit, then divide by the plan length.

\(12\text{ m}\)\(=\)\(1200\text{ cm}\)
\(8 : 1200\)\(=\)\(1 : 150\)
\(\text{scale}\)\(=\)\(\mathbf{1 : 150}\)

(ii) Plan to real: multiply.

\(0.6 \times 150\)\(=\)\(\mathbf{90}\text{ cm} = 0.9\text{ m}\)
0.6×150=90
Example 4 — Working from the perimeter
A triangle has sides \(4\) cm, \(6\) cm and \(8\) cm. A similar triangle has a perimeter of \(45\) cm. Find its side lengths.
Solution
Similar triangles with perimeters 18 cm and 45 cmA small triangle with sides 4, 6 and 8 cm, perimeter 18 cm, and a similar larger triangle with perimeter 45 cm. 8 4 6 P = 18 cm P = 45 cm

Every side is multiplied by \(k\), so the perimeter is multiplied by \(k\) too.

\(P_{\text{small}}\)\(=\)\(4 + 6 + 8 = 18\text{ cm}\)
\(k\)\(=\)\(\dfrac{45}{18} = 2.5\)
\(\text{sides}\)\(=\)\(4 \times 2.5,\ 6 \times 2.5,\ 8 \times 2.5\)
\(\)\(=\)\(\mathbf{10},\ \mathbf{15},\ \mathbf{20}\text{ cm}\)
k=4518=2.5

Check: \(10 + 15 + 20 = 45\).

Common pitfalls

Image over original. The scale factor is image \(\div\) original. Dividing the other way gives \(\dfrac{1}{k}\), which shrinks when it should grow.
Match the right sides. When a figure is turned, the bottom side of one may match a slanted side of the other. Follow the vertex letters or the equal angles, not the position on the page.
Do not add the difference. If a \(3\) cm side becomes \(6\) cm, a \(5\) cm side becomes \(10\) cm (multiply by \(2\)), not \(8\) cm (add \(3\)).
Same units in a scale. \(1 : 25\,000\) means \(1\) cm to \(25\,000\) cm, not \(25\,000\) m. Convert to m or km at the end.

Frequently asked questions

What makes two shapes similar?

Two shapes are similar if their matching angles are equal and their matching sides are all in the same ratio. One is an enlargement or reduction of the other.

How do you find the scale factor of similar figures?

Divide a length on the image by the matching length on the original. If a \(5\) cm side becomes \(7\) cm, \(k = \dfrac{7}{5} = 1.4\).

How do you find a missing side of a similar shape?

Find the scale factor from a pair of matching sides, then multiply the matching side by it to go to the larger figure, or divide by it to go to the smaller figure.

What does a scale of 1 to 25000 mean?

One unit on the map stands for \(25\,000\) of the same units in real life. \(1\) cm on the map is \(25\,000\) cm, which is \(250\) m.

Does the perimeter change by the scale factor?

Yes. Every side is multiplied by the scale factor, so the perimeter is too. Area is different, so find the new lengths before working out an area.