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Year 12 Maths - Methods (Unit 3 & Unit 4) Algebra and equations

Solution of trigonometric equations

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Question 1
198699

Solve \(\sin x=\dfrac{1}{2}\) for \(x\in[0,2\pi]\).

(i) State the first-quadrant solution.
(ii) Hence state the other solution in \([0,2\pi]\).
Part a:
A.
\(\dfrac{\pi}{6}\)
Correct
B.
\(\dfrac{5\pi}{6}\)
C.
\(\dfrac{\pi}{3}\)
D.
\(30^\circ\)
Part b:
A.
\(\dfrac{7\pi}{6}\)
B.
\(\dfrac{5\pi}{6}\)
Correct
C.
\(\dfrac{11\pi}{6}\)
D.
\(\dfrac{\pi}{3}\)

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