Linearly Related Variables, Linear Equations and Inequations
Unlock all 5 questions & worked solutions
You're viewing a free preview. Create an account to access the complete question set, step-by-step solutions, and progress tracking.
All Questions
Access the full question set for every topic.
Worked Solutions
Step-by-step explanations for every answer.
Track Progress
Mark questions right or wrong and monitor your growth.
It's Free
No credit card required - sign up in under a minute.
The solution to \(\dfrac{{x + 2}}{3} - \dfrac{x}{2} + \dfrac{{x + 1}}{4} = 1\) is?
\begin{aligned}
\frac{x+2}{3}-\frac{x}{2}+\frac{x+1}{4}&=1 \\
\textcolor{red}{12} \times \frac{x+2}{3}-\textcolor{red}{12} \times \frac{x}{2}+\textcolor{red}{12} \times \frac{x+1}{4}&=\textcolor{red}{12} \times 1 \\
4(x+2)-6 x+3(x+1)&=12 \\
4 x+8-6 x+3 x+3&=12 \\
x+11&=12 \\
x&=1
\end{aligned}
📚 Want More Questions?
There are 4 more questions available. Create your free account to access the complete question set with detailed solutions.