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Year 11 Maths - Methods Circular functions

Solution Of Trigonometric Equations

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Questions
Question 1
61837

Find all the values of \(x\) between \(0\) and \(2 \pi\) for which

i) \(\cos x = \dfrac{1}{{\sqrt 2 }}\)

ii) \(\sin x = \dfrac{1}{2}\)

Part a:
A.
\(x = \dfrac{\pi}{4},\ \dfrac{7\pi}{4}\)
Correct
B.
\(x = \dfrac{\pi}{3},\ \dfrac{5\pi}{3}\)
C.
\(x = \dfrac{\pi}{4},\ \dfrac{3\pi}{4}\)
D.
\(x = \dfrac{\pi}{4},\ \dfrac{5\pi}{4}\)
Part b:
A.
\(x = \dfrac{\pi}{6},\ \dfrac{11\pi}{6}\)
B.
\(x = \dfrac{\pi}{3},\ \dfrac{2\pi}{3}\)
C.
\(x = \dfrac{\pi}{6},\ \dfrac{7\pi}{6}\)
D.
\(x = \dfrac{\pi}{6},\ \dfrac{5\pi}{6}\)
Correct

\begin{align}
&\begin{aligned}\text{i)}\quad \cos x=\frac{1}{\sqrt{2}} \\ x=\frac{\pi}{4}, \quad x &=2 \pi-\frac{\pi}{4} \\ x &=\frac{7 \pi}{4}
\end{aligned}\\
&\begin{aligned}\text{ii)}\quad \sin x=\frac{1}{2} \\ x=\frac{\pi}{6},\quad x &=\pi-\frac{\pi}{6} \\ &=\frac{5 \pi}{6}
\end{aligned}
\end{align}

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