Resources For Teachers For Tutors For Students & Parents Pricing
Year 11 Methods (Unit 1 & 2) Further Differentiation

The Chain Rule

ACCOUNT REQUIRED

Unlock all 10 questions & worked solutions

You're viewing a free preview. Create an account to access the complete question set, step-by-step solutions, and progress tracking.

All Questions

Access the full question set for every topic.

Worked Solutions

Step-by-step explanations for every answer.

Track Progress

Mark questions right or wrong and monitor your growth.

It's Free

No credit card required - sign up in under a minute.

Question 1
28372

Use the chain rule to differentiate \(y=(x^2+2)^3\)

\(\dfrac{{dy}}{{dx}} = 6x{({x^2} + 2)^2}\)

\begin{align}
&y=\left(x^{2}+2\right)^{3} \\
&\begin{aligned}
\text {Let } u &=x^{2}+2 \quad\; y=u^{3} \\
\frac{du}{dx} &=2 x \qquad \frac{dy}{du}=3 u^{2} \\
\frac{d y}{dx} &=\frac{d y}{du} \times \frac{d u}{d x} \\
&=3 u^{2} \times 2 x\\
\frac{d y}{d x} &=6 x \times u^{2} \\
&=6 x\left(x^{2}+2\right)^{2}
\end{aligned}
\end{align}

📚 Want More Questions?

There are 9 more questions available. Create your free account to access the complete question set with detailed solutions.