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Year 9 Maths Advanced Equations

Changing the Subject of a Formula

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Questions
Question 1
49303

Make \(y\) the subject of \(x=y^{2}+1\)

\(y=\pm \sqrt{x-1}\)

\(\begin{aligned}
x&=y^{2}+1 \\
y^{2}+1&=x \\
y^{2}+1-1&=x-1 \\
y^{2}&=x-1 \\
y&=\pm \sqrt{x-1}
\end{aligned}\)

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