Year 12 Maths Extension 1 (2027)
Vectors
Projectile motion – equation of path
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Questions
Question 1
183045
A projectile has position vector \(\mathbf{r}(t)=(V\cos\theta\,t)\mathbf{i}+\left(V\sin\theta\,t-\tfrac{1}{2}gt^2\right)\mathbf{j}\). The Cartesian equation of its path is found by:
eliminating \(t\) between the \(x\)- and \(y\)-components
differentiating with respect to \(t\)
setting \(y=0\)
integrating with respect to \(t\)
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