Cosine Rule
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In \(\triangle ABC\), the sides \(a\), \(b\) and \(c\) are opposite the angles \(A\), \(B\) and \(C\) respectively.
Which of the following is a correct form of the cosine rule?
\(\cos B=\dfrac{a^2+b^2-c^2}{2ab}\)
\(\cos B=\dfrac{b^2+c^2-a^2}{2bc}\)
\(\cos B=\dfrac{a^2+c^2-b^2}{2b}\)
\(\cos B=\dfrac{a^2+c^2-b^2}{2ac}\)
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