Year 11 (2025) Maths Advanced
Calculus
Standard Derivative Applied to Negative Indices
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Questions
Question 1
12446
Given that \(f(x) =\dfrac{1}{x} + \dfrac{1}{{{x^2}}}\) then \(f'(x) =\)
\( - \dfrac{1}{{{x^2}}} - \dfrac{2}{{{x^3}}}\)
\( - \dfrac{1}{{{x^2}}} + \dfrac{1}{{{x^3}}}\)
\(\dfrac{1}{{{x^2}}} - \dfrac{2}{{{x^3}}}\)
\( - \dfrac{1}{{{x^2}}} + \dfrac{1}{{{x^3}}}\)
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