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Year 9 Maths Linear and Simultaneous Equations

Inequalities

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Theory

A linear inequality such as \(3x - 1 < 11\) has a whole range of solutions, not just one. This Year 9 maths page shows how to solve inequalities, graph the solution on a number line, and when to reverse the inequality sign.

An inequality compares two quantities that may not be equal. The signs are \(<\) (less than), \(>\) (greater than), \(\le\) (less than or equal to) and \(\ge\) (greater than or equal to).

The solution of an inequality is every number that makes it true. \(x > 4\) includes \(4.1\), \(5\), \(100\) and infinitely many other numbers, but not \(4\) itself.

Show a solution on a number line. An open circle means the end number is not included (\(<\) or \(>\)). A closed circle means it is included (\(\le\) or \(\ge\)). Shade the line in the direction of the solutions.

Solve an inequality like an equation, with one extra rule: when you multiply or divide both sides by a negative number, reverse the inequality sign. Adding, subtracting, and multiplying or dividing by a positive number do not change the sign.

Graphing inequalities on a number lineTop: x greater than 2, an open circle at 2 with the line shaded to the right. Bottom: x less than or equal to minus 1, a filled circle at minus 1 with the line shaded to the left. βˆ’4βˆ’3βˆ’2βˆ’1012345 x > 2 βˆ’4βˆ’3βˆ’2βˆ’1012345 x ≀ βˆ’1
Open circle for \(<\) or \(>\): the end value is not included. Filled circle for \(\le\) or \(\ge\): it is included.
Multiplying by minus 1 reverses the orderNavy dots at 2 and 5, with 2 less than 5. Multiplying by minus 1 reflects them through zero to the red dots at minus 2 and minus 5, where minus 2 is greater than minus 5. βˆ’6βˆ’5βˆ’4βˆ’3βˆ’2βˆ’10123456 2 < 5 βˆ’2 > βˆ’5 multiply both by βˆ’1
Multiplying or dividing by a negative number flips the numbers through zero, so the inequality sign must be reversed.

For any numbers \(a\) and \(b\), and a positive number \(k\):

\[a < b \;\Rightarrow\; ka < kb \qquad\qquad a < b \;\Rightarrow\; -ka > -kb\]
a<b⇒−ka>−kb
InequalityIn wordsCircleShade
\(x > a\)greater than \(a\)openright
\(x \ge a\)greater than or equal to \(a\)closedright
\(x < a\)less than \(a\)openleft
\(x \le a\)less than or equal to \(a\)closedleft
A negative denominator. Multiplying by a negative also reverses the sign: \(\dfrac{x - 4}{-2} \le 3\) gives \(x - 4 \ge -6\), so \(x \ge -2\).
Words to signs. "At most" and "no more than" mean \(\le\). "At least" and "no less than" mean \(\ge\).

How to solve a linear inequality

  1. Clear fractions and expand brackets, as for an equation.
  2. Collect the pronumeral terms on one side and the numbers on the other.
  3. Divide by the coefficient. If it is negative, reverse the sign.
  4. Read the answer with the pronumeral first: \(-3 < x\) is \(x > -3\).
  5. Check with one number inside the solution and one outside.

Whole-number answers

  1. Greatest whole number: from \(n \le 38.53\ldots\), round down to \(38\).
  2. Smallest whole number: from \(4n + 3 > 25\) you get \(n > 5.5\), so the answer is \(6\). With \(n > 6\) exactly, the answer would be \(7\), because \(6\) is not included.
Example 1 β€” Solve and graph
Solve \(5x - 2 > 13\) and graph the solution on a number line.
Solution

Solve it like an equation. Adding and dividing by a positive number leave the sign unchanged.

\(5x - 2\)\(>\)\(13\)
\(5x\)\(>\)\(15\)
\(\therefore\ x\)\(>\)\(\boldsymbol{3}\)
x>3

\(3\) itself is not a solution, so use an open circle.

Solution x greater than 3Number line with an open circle at 3 and the line shaded to the right. βˆ’1012345678
Example 2 β€” Dividing by a negative
Solve \(5 - 2x > 12\) and graph the solution.
Solution

Subtract \(5\) from both sides. Then divide by \(-2\): dividing by a negative number reverses the sign.

\(5 - 2x\)\(>\)\(12\)
\(-2x\)\(>\)\(7\)
\(x\)\(<\)\(\dfrac{7}{-2}\)
\(\therefore\ x\)\(<\)\(\boldsymbol{-3.5}\)
x<−3.5
Solution x less than minus 3.5Number line with an open circle at minus 3.5, halfway between minus 4 and minus 3, and the line shaded to the left. βˆ’7βˆ’6βˆ’5βˆ’4βˆ’3βˆ’2βˆ’1012

Check with \(x = -4\), which is in the solution: \(5 - 2(-4) = 13\), and \(13 > 12\) is true.

Example 3 β€” Fractions and reading backwards
Solve:
(i) \(\dfrac{2x - 1}{3} \ge x - 2\)
(ii) \(4 < \dfrac{x + 6}{2}\)
Solution

(i) Multiply both sides by \(3\). Then collect the \(x\) terms; the last step divides by \(-1\), so the sign reverses.

\(2x - 1\)\(\ge\)\(3(x - 2)\)
\(2x - 1\)\(\ge\)\(3x - 6\)
\(-x\)\(\ge\)\(-5\)
\(\therefore\ x\)\(\le\)\(\boldsymbol{5}\)
x≤5

(ii) Multiply both sides by \(2\), subtract \(6\), then read the result from the \(x\) side.

\(8\)\(<\)\(x + 6\)
\(2\)\(<\)\(x\)
\(\therefore\ x\)\(>\)\(\boldsymbol{2}\)
x>2

\(2 < x\) and \(x > 2\) say the same thing. Turning the statement around turns the sign around.

Example 4 β€” A money problem
Zoe has $80. She buys a phone case for $14.50 and then downloads songs at $1.70 each. Write an inequality for the number of songs, \(n\), and find the greatest number she can buy.
Solution

The total spent must be less than or equal to $80.

\(14.50 + 1.70n\)\(\le\)\(80\)
\(1.70n\)\(\le\)\(65.50\)
\(n\)\(\le\)\(38.53\ldots\)
14.50+1.70n≤80

\(n\) must be a whole number, so round down. She can buy at most \(\boldsymbol{38}\) songs. Check: \(38\) songs cost $64.60, so $79.10 in total; \(39\) songs would bring the total to $80.80.

Common pitfalls

Reverse the sign for negatives. From \(-3x < 12\) you get \(x > -4\), not \(x < -4\). Only multiplying or dividing by a negative does this; subtracting a number never does.
Open or closed? \(x < 2\) uses an open circle, because \(2\) is not a solution. \(x \le 2\) uses a closed circle.
Round in the sensible direction. For the greatest number of items you can afford, round down, even if the decimal is \(.9\). Rounding up would go over budget.
Keep brackets when clearing fractions. In \(\dfrac{2x - 1}{3} \ge x - 2\), the right side becomes \(3(x - 2) = 3x - 6\), not \(3x - 2\).

Frequently asked questions

When do you flip the inequality sign?

Only when you multiply or divide both sides by a negative number. Adding or subtracting any number, or multiplying or dividing by a positive number, leaves the sign as it is.

What is the difference between an open and a closed circle on a number line?

An open circle means the end number is not part of the solution, for \(<\) or \(>\). A closed circle means it is included, for \(\le\) or \(\ge\).

How many solutions does an inequality have?

Usually infinitely many. \(x > 3\) is true for every number bigger than \(3\), including decimals. In a word problem the context may limit it to whole numbers.

Why does the sign change when you divide by a negative?

Because multiplying by \(-1\) flips numbers through zero. \(2 < 5\), but \(-2 > -5\), so the order of the two sides is reversed.

How do you write at most and at least as inequalities?

At most means \(\le\). At least means \(\ge\). For example, spending at most $80 is \(\text{total} \le 80\).