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Year 8 Maths Rates and Ratios

Simplifying Ratios

20 practice questions 2 video lessons Theory + worked examples
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Theory

To simplify a ratio, make every term a whole number in the same unit, then divide every term by their HCF. \(18:42:48\) has HCF \(6\), so it simplifies to \(3:7:8\). This Year 8 maths page shows how, with decimals, fractions and units.

A ratio is in simplest form when every term is a whole number and the only factor they all share is \(1\). It works for any number of terms.

Finding a large HCF. Write each term as the HCF times something: \(102 = 34 \times 3\) and \(170 = 34 \times 5\), so \(102:170 = 3:5\). Two smaller steps reach the same answer: \(\div 17\) then \(\div 2\).

Decimals. The term with the most decimal places decides the multiplier: one place needs \(\times 10\), two need \(\times 100\). Multiply every term, including whole-number terms, then divide by the HCF.

Fractions. Write mixed numerals as improper fractions, multiply every term by the lowest common denominator, then divide by the HCF.

Different units. Change to the same unit first, then write the ratio without units: \(1\) km \(= 1000\) m, \(1\) m \(= 1000\) mm, \(1\) kg \(= 1000\) g, \(1\) L \(= 1000\) mL, \(1\) h \(= 60\) min, and \(\$1\) is \(100\)c.

Pronumerals. A pronumeral in every term is part of the HCF and divides out; one in only some terms stays: \(10ab:15a = 2b:3\).

Part to whole. The whole is the sum of the parts, so first add them.

50 cm compared with 1.75 m Two bars made of boxes of 25 cm each. 50 cm is 2 boxes and 1.75 m, which is 175 cm, is 7 boxes, so 50 cm : 1.75 m = 2:7. 50 cm2525 1.75 m25252525252525 each box is 25 cm: ratio 2 : 7
Same unit first: \(1.75\) m \(= 175\) cm. Each box is \(25\) cm, the HCF, so \(50:175 = 2:7\).

The term with the most decimal places decides the multiplier:

RatioMultiply bySimplest
\(0.4:1.6\)10\(1:4\)
\(0.24:1.6\)100\(3:20\)
\(2.5:1:0.75\)100\(10:4:3\)
Multiply by enough. \(0.35:0.7\) times \(10\) gives \(3.5:7\), which still has a decimal. Two decimal places need \(\times 100\): \(35:70 = 1:2\).
Finish the job. If the new terms still share a factor, divide again. The HCF of the answer must be 1.

Simplifying a ratio

  1. Units: change every quantity to the same unit.
  2. Whole numbers: multiply every term by \(10\), \(100\) or the lowest common denominator.
  3. Divide every term by the HCF.
  4. Check that the terms share no factor other than \(1\).
Example 1 — Same units first
Simplify the ratio \(70\) mm : \(2.1\) m.
Solution
\(2.1 \times 1000\)\(=\)\(2100 \text{ mm}\)
\(70:2100\)\(=\)\(1:30\)
130

\(70\) mm : \(2.1\) m \(= 1:30\) (dividing both terms by \(70\)).

Example 2 — Three terms
Simplify the ratio \(18:42:48\).
Solution

\(18 = 3 \times 6\), \(42 = 7 \times 6\), \(48 = 8 \times 6\), so the HCF is \(6\).

\(18:42:48\)\(=\)\(3:7:8\)
378

\(3:7:8\)

Example 3 — A large HCF
Simplify
(i) \(91:117:143\)
(ii) \(46:69:115:92\).
Solution

(i) \(91 = 13 \times 7\), \(117 = 13 \times 9\), \(143 = 13 \times 11\): the HCF is \(13\).
(ii) Every term is a multiple of \(23\).

\(91:117:143\)\(=\)\(7:9:11\)
\(46:69:115:92\)\(=\)\(2:3:5:4\)
79112354

(i) \(7:9:11\)
(ii) \(2:3:5:4\)

Example 4 — Decimal terms
Simplify
(i) \(0.36:0.96\)
(ii) \(2.5:1:0.75\).
Solution

Both have two decimal places somewhere, so multiply every term by \(100\), including the \(1\).

\(0.36:0.96\)\(=\)\(36:96\)
\(\)\(=\)\(3:8\)
\(2.5:1:0.75\)\(=\)\(250:100:75\)
\(\)\(=\)\(10:4:3\)
381043

(i) \(3:8\) \((\div 12)\)
(ii) \(10:4:3\) \((\div 25)\)

Example 5 — Fractions and mixed numerals
Simplify
(i) \(\dfrac{3}{8}:\dfrac{5}{6}\)
(ii) \(2\dfrac{1}{2}:1\dfrac{1}{4}\).
Solution

(i) The lowest common denominator of \(8\) and \(6\) is \(24\).
(ii) \(2\dfrac{1}{2} = \dfrac{5}{2}\) and \(1\dfrac{1}{4} = \dfrac{5}{4}\); multiply both by \(4\).

\(\dfrac{3}{8} \times 24\)\(=\)\(9\)
\(\dfrac{5}{6} \times 24\)\(=\)\(20\)
\(\dfrac{5}{2} \times 4\)\(=\)\(10\)
\(\dfrac{5}{4} \times 4\)\(=\)\(5\)
92021

(i) \(9:20\)
(ii) \(10:5 = 2:1\)

Example 6 — Units and part of the whole
On Saturday Priya spends \(45\) minutes on maths, \(1\) hour on reading and \(30\) minutes on music.
(i) Write maths : reading : music in simplest form.
(ii) Write music : total time in simplest form.
Solution

Use minutes: \(1\) h \(= 60\) min. The HCF of \(45\), \(60\) and \(30\) is \(15\).

\(45:60:30\)\(=\)\(3:4:2\)
\(45 + 60 + 30\)\(=\)\(135\)
\(30:135\)\(=\)\(2:9\)
34229

(i) \(3:4:2\)
(ii) \(2:9\)

Example 7 — Money, pronumerals and a rectangle
Simplify
(i) \(90\)c : \(\$2.70\)
(ii) \(10ab:15a\)
(iii) length : width : perimeter for a rectangle \(1.2\) m long and \(40\) cm wide.
Solution

(i) \(\$2.70\) is \(270\)c.
(ii) The HCF is \(5a\).
(iii) Use cm: \(120\) and \(40\); perimeter \(= 2 \times (120 + 40) = 320\).

\(90:270\)\(=\)\(1:3\)
\(10ab:15a\)\(=\)\(2b:3\)
\(120:40:320\)\(=\)\(3:1:8\)
132 b 3318

(i) \(1:3\)
(ii) \(2b:3\)
(iii) \(3:1:8\) \((\div 40)\)

Common pitfalls

Comparing different units. \(1\) km : \(400\) m is \(1000:400 = 5:2\), not \(1:400\).
Converting with the wrong factor. \(2.1\) m is \(2100\) mm (\(\times 1000\)), not \(210\) mm.
Not multiplying every term. In \(2.5:1:0.75\), the \(1\) must become \(100\) too.
Stopping too early. \(24:160\) still shares \(8\); it simplifies to \(3:20\).

Frequently asked questions

What does simplest form mean for a ratio?

Every term is a whole number and the terms have no common factor other than 1.

How do I simplify a ratio with decimals?

Multiply every term by 10 or 100 to make whole numbers, then divide by the HCF.

How do I simplify a ratio of fractions?

Multiply every term by the lowest common denominator, then divide by the HCF.

Why must the units be the same?

A ratio compares amounts of the same kind. 500 g : 2 kg is 500 : 2000 = 1 : 4, not 500 : 2.

Can a ratio have more than two terms?

Yes. Divide every term by the HCF of all of them, such as 18:42:48 = 3:7:8.