Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 8 Maths Graphing Linear Equations

The Number Plane

20 practice questions 1 video lesson Theory + worked examples
Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 1 video(s)
  • The Number Plane - Video - Identify the Quadrant of a Point on the Coordinate Plane Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Every point on the number plane has coordinates \((x, y)\): \(x\) is how far right or left of the origin, \(y\) how far up or down. The axes cut the plane into four quadrants, and the signs of \(x\) and \(y\) tell you which one: \((-1, 3)\) is in the 2nd. This Year 8 maths page shows how.

Reading and plotting. Start at the origin \(O(0, 0)\). Go across first: positive \(x\) is right, negative \(x\) is left. Then positive \(y\) is up, negative \(y\) is down.

Quadrants are numbered anticlockwise from the top right. For a point \(P(x, y)\): \(x > 0, y > 0\) is the 1st (I); \(x < 0, y > 0\) the 2nd (II); \(x < 0, y < 0\) the 3rd (III); \(x > 0, y < 0\) the 4th (IV). Only the signs decide, so \((-9.8, 8)\) is in the 2nd.

On an axis. A point on an axis is in no quadrant: on the \(x\)-axis \(y = 0\), on the \(y\)-axis \(x = 0\).

Between grid lines. A point halfway between two grid lines has a coordinate ending in \(.5\), such as \(-1.5\). The distance from the \(y\)-axis is the size of \(x\); from the \(x\)-axis, the size of \(y\).

Lengths. Two points with the same \(y\) lie on a horizontal line; two with the same \(x\) lie on a vertical line. The length is the larger coordinate minus the smaller, even across an axis: \(4 - (-3) = 7\) units.

Shapes. Once the side lengths are known, use the area formulas, such as \(A = \dfrac{1}{2}(a + b)h\) for a trapezium and \(A = \dfrac{1}{2}xy\) for a kite or rhombus with diagonals \(x\) and \(y\). Areas are in square units. Where a horizontal and a vertical path meet at a right angle, Pythagoras’ theorem gives the straight-line distance between their far ends.

The four quadrants A number plane from -6 to 6 on both axes. The quadrants are labelled 1st (top right), 2nd (top left), 3rd (bottom left) and 4th (bottom right). Points: A(2.5, 3) in the 1st, B(-4, 2) in the 2nd, C(-3, -4) in the 3rd, D(3, -1) in the 4th, and E(-5, 0) on the x-axis. xy −6−4−2246−6−4−22460 A B C D E 1st2nd3rd4th
To reach \(A(2.5, 3)\), go \(2.5\) across, then \(3\) up. \(E(-5, 0)\) is on the \(x\)-axis, so it is in no quadrant.

The signs in each quadrant:

Quadrant\(x\)\(y\)Example
1st (I)++\((2, 5)\)
2nd (II)−+\((-1, 3)\)
3rd (III)−−\((-1, -2)\)
4th (IV)+−\((6, -3)\)
Order matters. \((-2, 5)\) is in the 2nd quadrant and \((5, -2)\) is in the 4th.
A distance is never negative. From \(x = -4\) to \(x = 3\) is \(3 - (-4) = 7\) units, not \(-1\).

Plotting a point (x, y)

  1. Start at the origin.
  2. Move across \(x\) units: right if positive, left if negative.
  3. Move up or down \(y\) units: up if positive, down if negative.
  4. Mark the point and label it.

Finding a horizontal or vertical length

  1. Check which coordinate is the same (same \(y\): horizontal; same \(x\): vertical).
  2. Subtract the smaller other coordinate from the larger one.
Example 1 — Which quadrant? (1)
In which quadrant does each point lie?
(i) \(P(-1, 3)\)
(ii) \(Q(2, 5)\)
Solution

(i) \(x < 0\) and \(y > 0\), so the 2nd quadrant (II).
(ii) \(x > 0\) and \(y > 0\), so the 1st quadrant (I).

Example 2 — Which quadrant? (2)
In which quadrant does each point lie?
(i) \(L(-1, -2)\)
(ii) \(M(6, -3)\)
Solution

(i) \(x < 0\) and \(y < 0\), so the 3rd quadrant (III).
(ii) \(x > 0\) and \(y < 0\), so the 4th quadrant (IV).

Example 3 — Reading points
Give the coordinates of \(P\), \(Q\), \(R\) and \(S\), and the quadrants of \(P\) and \(Q\).
Points P, Q, R and S A number plane from -5 to 5. P is 4 left and 2.5 up; Q is 3 right and 4 down; R is on the x-axis 2 to the left; S is on the y-axis 4 up. xy −5−4−3−2−112345−5−4−3−2−1123450 P Q R S
Solution

\(P(-4, 2.5)\), 2nd quadrant
\(Q(3, -4)\), 4th quadrant
\(R(-2, 0)\) and \(S(0, 4)\) are on the axes, so they are in no quadrant.

Example 4 — Locating a point
\(V\) is in the 3rd quadrant, \(4\) units from the \(y\)-axis and \(1.5\) units from the \(x\)-axis.
(i) Give the coordinates of \(V\).
(ii) \(W\) is \(6\) units right of \(V\). Give \(W\) and its quadrant.
Solution

In the 3rd quadrant both coordinates are negative. Moving right adds to \(x\) and leaves \(y\) alone.

(i) \(V(-4, -1.5)\)
(ii) \(-4 + 6 = 2\), so \(W(2, -1.5)\), in the 4th quadrant.

Example 5 — A shape from a table
A garden bed has corners \(A(-5, -1)\), \(B(2, -1)\), \(C(1, 3)\) and \(D(-3, 3)\). Each unit is \(1\) m. Find its area.
Solution

\(AB\) and \(DC\) are both horizontal, so they are the parallel sides of a trapezium.

\(AB\)\(=\)\(2 - (-5) = 7\)
\(DC\)\(=\)\(1 - (-3) = 4\)
\(h\)\(=\)\(3 - (-1) = 4\)
\(A\)\(=\)\(\dfrac{1}{2} \times (7 + 4) \times 4 = 22\)
22 square metres

The bed has an area of \(22\) m\(^2\).

Example 6 — A kite and a walk
(i) A kite has vertices \((0, 5)\), \((2, 0)\), \((0, -3)\) and \((-2, 0)\). Find its area.
(ii) On a map with \(1\) unit \(= 1\) km, Sam walks from \((-4, 3)\) to \((5, 3)\), then to \((5, -9)\), then straight back. How far does he walk?
Solution

(i) The diagonals are \(5 - (-3) = 8\) and \(2 - (-2) = 4\).
(ii) The legs are \(5 - (-4) = 9\) km and \(3 - (-9) = 12\) km, at right angles.

\(A\)\(=\)\(\dfrac{1}{2} \times 8 \times 4 = 16\)
\(\text{Back}\)\(=\)\(\sqrt{9^2 + 12^2} = 15\)
\(\text{Total}\)\(=\)\(9 + 12 + 15 = 36\)
16 square units 36 km

(i) \(16\) square units
(ii) \(36\) km

Example 7 — Reasoning with signs
\(M(p, q)\) is in the 2nd quadrant.
(i) What are the signs of \(p\) and \(q\)?
(ii) In which quadrant is \((q, p)\)?
(iii) In which quadrant is \((p, -q)\)?
Solution

(i) \(p\) is negative and \(q\) is positive.
(ii) \((q, p)\) is \((+, -)\): the 4th quadrant.
(iii) \((p, -q)\) is \((-, -)\): the 3rd quadrant. Test: \(M(-3, 5)\) gives \((5, -3)\) and \((-3, -5)\).

Common pitfalls

Going up first. \((3, 1)\) is \(3\) across and \(1\) up, not \(3\) up.
Putting an axis point in a quadrant. \((0, -4)\) is on the \(y\)-axis, not in the 3rd or 4th quadrant.
Subtracting the wrong way across an axis. From \(-3\) to \(4\) is \(4 - (-3) = 7\), not \(4 - 3 = 1\).
Reading a half as a whole. A point halfway between \(-1\) and \(-2\) is at \(-1.5\).

Frequently asked questions

What are coordinates?

A pair of numbers (x, y) that give the position of a point: x across from the origin, then y up or down.

How are the quadrants numbered?

Anticlockwise from the top right: 1st top right, 2nd top left, 3rd bottom left, 4th bottom right.

Which quadrant is a point with a negative x and a positive y in?

The 2nd quadrant.

Which quadrant is the point (0, 3) in?

None. It is on the y-axis.

How do I find the distance between (βˆ’4, 2) and (3, 2)?

They have the same y, so the line is horizontal. Subtract the x-values: 3 βˆ’ (βˆ’4) = 7 units.