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Year 8 Maths Congruent Figures

Congruent Triangle Proof

20 practice questions 1 video lesson Theory + worked examples
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Theory

A congruence proof is a short list: one fact per line with its reason, then the congruence statement with the test, then what follows from it, such as \(PA = PB\) (matching sides of congruent triangles). This Year 8 maths page shows how.

Three facts, then the test, then the conclusion. Give exactly three matching facts, each with its reason, name the test (SSS, SAS, AAS or RHS), then draw the conclusion asked for.

Reasons you may use without being told: common side (a side in both triangles), common angle, vertically opposite angles, alternate angles on parallel lines (“alternate angles, \(AB \parallel DC\)”), radii of a circle are equal, a midpoint cuts a segment in half, a bisector cuts an angle in half, and any property of a named shape.

Given facts come from the question or from marks on the figure: ticks for equal sides, arcs for equal angles, a square for a right angle.

The conclusion. Once the triangles are congruent, every pair of matching parts is equal: “matching (corresponding) sides of congruent triangles” or “matching angles of congruent triangles”.

Write the vertices in matching order. The conclusion is read straight off that order, so swapping letters changes what the statement says.

Midpoint and perpendicular Triangle PAB with M the midpoint of AB and PM perpendicular to AB. AM and MB have one tick each; PA and PB have two ticks each; there is a right angle at M; PM is shared by both triangles. A M B P common
Given: \(AM = BM\) (one tick each) and the right angle at \(M\). Common: \(PM\). So \(\triangle PMA \equiv \triangle PMB\) (SAS), and the two sloping sides are equal: \(PA = PB\).

A proof set out in full (the figure on the Diagrams tab):

StatementReason
\(AM = BM\)\(M\) is the midpoint of \(AB\)
\(\angle PMA = \angle PMB\)both \(90^\circ\), \(PM \perp AB\)
\(PM = PM\)common side
\(\triangle PMA \equiv \triangle PMB\)SAS
\(PA = PB\)matching sides of congruent triangles
Every line needs a reason. “They look the same” is not a reason. A length or angle you were not given, and that is not marked, cannot be used.
SSA is not a test. Two sides and an angle that is not between them prove nothing, whatever the last line calls it.

Writing a congruence proof

  1. Name the two triangles: “In \(\triangle \ldots\) and \(\triangle \ldots\):”.
  2. List three matching facts, one per line, each with a reason.
  3. Write the congruence statement with matching vertices in order, and the test in brackets.
  4. Conclude the required fact: matching sides or angles of congruent triangles.
Example 1 — Right angle, hypotenuse, side
In \(\triangle PQR\) and \(\triangle XYZ\), \(\angle Q = \angle Y = 90^\circ\), \(PR = XZ\) and \(QR = YZ\). Prove that \(\triangle PQR \equiv \triangle XYZ\).
Two right-angled triangles Two right-angled triangles PQR and XYZ, with the right angles at Q and Y. The hypotenuses PR and XZ have two ticks each; QR and YZ have one tick each. P Q R X Y Z
Solution
StatementReason
\(PR = XZ\)given (hypotenuses)
\(\angle PQR = \angle XYZ\)both \(90^\circ\) (given)
\(QR = YZ\)given
\(\triangle PQR \equiv \triangle XYZ\)RHS

\(\triangle PQR \equiv \triangle XYZ\) (RHS).

Example 2 — Vertically opposite angles
In the figure, \(PR = TR\) and \(QR = SR\). Prove that \(\triangle PRQ \equiv \triangle TRS\).
Two triangles meeting at R Segments PT and SQ cross at R, forming triangles PRQ and TRS. PR and RT have one tick each; QR and RS have two ticks each. P Q S T R
Solution
StatementReason
\(PR = TR\)given
\(QR = SR\)given
\(\angle PRQ = \angle TRS\)vertically opposite angles
\(\triangle PRQ \equiv \triangle TRS\)SAS

The angle at \(R\) is between the two given sides in each triangle, so the test is SAS.

Example 3 — A bisected angle
\(TU = TW\) and \(TV\) bisects \(\angle UTW\). Prove that \(UV = WV\).
Solution

In \(\triangle TUV\) and \(\triangle TWV\):

StatementReason
\(TU = TW\)given
\(\angle UTV = \angle WTV\)\(TV\) bisects \(\angle UTW\)
\(TV = TV\)common side
\(\triangle TUV \equiv \triangle TWV\)SAS
\(UV = WV\)matching sides of congruent triangles
Example 4 — A shared hypotenuse
In \(WXYZ\), \(\angle WXY = \angle WZY = 90^\circ\) and \(XY = ZY\). Prove that \(WX = WZ\).
Solution

\(WY\) is opposite both right angles, so it is the hypotenuse of each triangle. In \(\triangle WXY\) and \(\triangle WZY\):

StatementReason
\(\angle WXY = \angle WZY\)both \(90^\circ\)
\(WY = WY\)common side (hypotenuse)
\(XY = ZY\)given
\(\triangle WXY \equiv \triangle WZY\)RHS
\(WX = WZ\)matching sides of congruent triangles
Example 5 — Find the mistake
Jai is told \(AB = DF\), \(BC = FE\) and \(\angle ABC = \angle DFE\). He writes \(\triangle ABC \equiv \triangle DEF\) (SAS). Every fact is true, but the last line is wrong. Correct it.
Solution

The matching vertices are \(A \leftrightarrow D\), \(B \leftrightarrow F\), \(C \leftrightarrow E\).

The statement should be \(\triangle ABC \equiv \triangle DFE\) (SAS). Jai’s order would claim \(AC = DF\), which he was never given; the correct order gives \(AC = DE\).

Example 6 — Tent ropes
Four pegs \(A\), \(B\), \(C\), \(D\) lie in a straight line in that order. Ropes from the pole top \(T\) have \(TB = TC\), and \(AB = CD\). Prove that the two long ropes \(TA\) and \(TD\) are equal.
Solution

\(TB = TC\), so \(\angle TBC = \angle TCB\) (base angles of an isosceles triangle). Taking each from \(180^\circ\) gives \(\angle TBA = \angle TCD\) (angles on a straight line). In \(\triangle TBA\) and \(\triangle TCD\):

StatementReason
\(TB = TC\)given
\(\angle TBA = \angle TCD\)shown above
\(BA = CD\)given
\(\triangle TBA \equiv \triangle TCD\)SAS
\(TA = TD\)matching sides of congruent triangles

Common pitfalls

Reordering the letters. In \(\triangle PMA \equiv \triangle PMB\), \(A\) matches \(B\). Writing \(\triangle PMA \equiv \triangle BMP\) would claim different equal sides.
Using what you have to prove. Do not use the conclusion as one of the three facts.
Missing reasons. Every statement, even a common side, needs its reason.
Calling SSA “SAS”. Check that the angle is between the two sides before naming SAS.

Frequently asked questions

How do you write a congruence proof?

Name the two triangles, list three matching facts with reasons, write the congruence statement and the test, then state what follows.

What is a common side?

A side shared by both triangles; its reason is “common side”.

What reason do I give for angles where two lines cross?

Vertically opposite angles are equal.

How do I prove two sides are equal using congruence?

Prove the triangles that contain them are congruent, then use “matching sides of congruent triangles”.

Why does the order of the vertices matter in a proof?

The conclusion is read from the statement, so the matching vertices must be in the same positions.