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Year 8 Maths Area and Perimeter

Perimeter

20 practice questions 2 video lessons Theory + worked examples
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Practice questions

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Theory

Perimeter is the total distance around the outside of a shape. Change every side to the same unit, then add each side once. A rhombus with sides of \(2.5\) cm has a perimeter of \(4 \times 2.5 = 10\) cm. This Year 8 maths page shows how.

Perimeter is a length, so its units are mm, cm, m or km. Change every side to the same unit before you add.

Equal sides save work. Matching marks mean equal sides. A regular polygon has \(n\) equal sides, so \(P = n \times s\). Rectangle: \(P = 2l + 2w\). Square or rhombus: \(P = 4s\). Kite or parallelogram: \(P = 2a + 2b\). A trapezium has no shortcut: add all four sides.

Composite shapes. When every corner is a right angle, the pieces along one side add up to the side opposite, so find the missing sides first. Then go round once and add.

Push the steps out. A staircase of right-angled steps has the same perimeter as the rectangle around it.

A notch makes the perimeter longer. The piece of edge removed is replaced by the new cut edges.

Pronumerals. Add the sides and collect like terms: \(x + x + 3x = 5x\). Given the perimeter, solve for \(x\). Working backwards: take the known sides off the perimeter, then share what is left between the equal sides.

Then the question goes on. A wall or a gate is not fenced; cost \(=\) length \(\times\) price per metre; lengths sold in a fixed size are rounded up.

Staircase shape A staircase shape 5 m wide and 3 m high with right-angled steps. Dashed lines push the steps out to the 5 m by 3 m rectangle, which has the same perimeter, 16 m. 5 m 3 m P = 2 × 5 + 2 × 3 = 16 m
The flat treads add up to the \(5\) m width and the uprights add up to the \(3\) m height, so the staircase has the perimeter of its rectangle.
Rectangle with a notch A 9 m by 6 m rectangle with a 2 m by 2 m notch cut from the top edge. The removed 2 m of top edge is dashed; the notch adds three new 2 m edges, so the perimeter is 34 m. 9 m 6 m 2 m 2 m P = 30 − 2 + 2 + 2 + 2 = 34 m
Cutting the notch takes \(2\) m off the top edge but adds three \(2\) m cut edges (two sides and the bottom), so the perimeter grows by \(4\) m.

Perimeter formulas:

ShapePerimeter
regular polygon with \(n\) sides of \(s\)\(P = ns\)
rectangle\(P = 2l + 2w\)
square, rhombus\(P = 4s\)
kite, parallelogram\(P = 2a + 2b\)
any other shapeadd every side once
One unit first. Sides of \(320\) mm and \(55\) cm: use \(32\) cm and \(55\) cm.
Perimeter is not area. Two shapes made from the same tiles can have the same area and different perimeters.

How to find a perimeter

  1. Change every side to the same unit.
  2. Find any missing sides (opposite pieces add up).
  3. Go round once and add every side, then answer the question asked.
Example 1 — Equal sides
(i) A rhombus has sides of \(2.5\) cm. Find its perimeter.
(ii) A parallelogram has a perimeter of \(24\) cm, and one side is twice the length of the other. Find the shorter side.
Solution

(ii) Let the shorter side be \(a\) cm, so the longer side is \(2a\) cm. Opposite sides are equal.

\(P\)\(=\)\(4 \times 2.5 = 10\)
\(a + a + 2a + 2a\)\(=\)\(24\)
\(6a\)\(=\)\(24\)
\(a\)\(=\)\(4\)
10 cm 4 cm

(i) \(10\) cm
(ii) The shorter side is \(4\) cm (and the longer side \(8\) cm).

Example 2 — Equal sides, two units
A kite-shaped flag has two short sides of \(320\) mm and two long sides of \(55\) cm. Find its perimeter in centimetres.
Solution
\(320\text{ mm}\)\(=\)\(32\text{ cm}\)
\(P\)\(=\)\(2 \times 32 + 2 \times 55\)
\(\)\(=\)\(64 + 110 = 174\)
174 cm

\(174\) cm

Example 3 — Missing sides
A stage is shaped like a T. All corners are right angles. Find its perimeter.
T-shaped stage A T-shaped stage. The top is 12 m long and 2 m deep; the stem is 4 m wide and 3 m tall; the two shoulders are marked a. 12 m 2 m 4 m 3 m a a
Solution

The two shoulders are equal and together are the top minus the stem: \(a = (12 - 4) \div 2 = 4\). The right end equals the left end, \(2\) m.

\(P\)\(=\)\(12 + 2 + 4 + 3\)
\(\)\(\)\(+ 4 + 3 + 4 + 2\)
\(\)\(=\)\(34\)
34 m

\(34\) m. Check by pushing out to a \(12\) m by \(5\) m rectangle: \(2 \times 12 + 2 \times 5 = 34\).

Example 4 — Expression, then solve
A rectangular court is \(5\) m longer than twice its width. A line painted right around it is \(52\) m long.
(i) Write a simplified expression for the perimeter.
(ii) Find the width and the length.
Solution

Let the width be \(w\) m, so the length is \((2w + 5)\) m.

\(P\)\(=\)\(2w + 2(2w + 5)\)
\(\)\(=\)\(6w + 10\)
\(6w + 10\)\(=\)\(52\)
\(w\)\(=\)\(7\)
6 w +107 m and 19 m

(i) \((6w + 10)\) m
(ii) Width \(7\) m, length \(2 \times 7 + 5 = 19\) m. Check: \(14 + 38 = 52\).

Example 5 — A border, then round up
A print \(40\) cm by \(30\) cm is set in a frame \(5\) cm wide all the way around. Timber comes in \(50\) cm lengths.
(i) Find the perimeter of the outside of the frame.
(ii) How many lengths of timber are needed?
Solution

The border adds \(5\) cm at each end of both sides: \(40 + 10 = 50\) and \(30 + 10 = 40\).

\(P\)\(=\)\(2 \times 50 + 2 \times 40 = 180\)
\(180 \div 50\)\(=\)\(3.6\)
180 cm 4 lengths

(i) \(180\) cm
(ii) Three lengths give only \(150\) cm, so round up: \(4\) lengths.

Common pitfalls

Adding sides in different units. Change \(320\) mm to \(32\) cm before adding it to \(55\) cm.
Missing an unlabelled side. Count the sides as you go round; work out every unlabelled side first.
Thinking a notch shortens the perimeter. The cut edges replace the removed edge and are longer.
Rounding a number of lengths down. \(3.6\) lengths means \(4\) must be bought.

Frequently asked questions

What is perimeter?

The total distance around the outside of a shape.

What is the perimeter of a rectangle?

\(P = 2l + 2w\): twice the length plus twice the width.

How do I find a missing side in a composite shape?

When all corners are right angles, the pieces along one side add up to the side opposite, so subtract.

What units is perimeter measured in?

Units of length, such as mm, cm, m or km.

How do I find a side from the perimeter?

Take the known sides off the perimeter, then share the rest between the equal sides. A square of perimeter \(30\) cm has sides of \(7.5\) cm.