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Year 8 Maths Algebra

Index Laws for Multiplying and Dividing

20 practice questions 2 video lessons Theory + worked examples
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Theory

When multiplying terms with the same base, the indices are added: \(a^m \times a^n = a^{m+n}\). When dividing, they are subtracted: \(a^m \div a^n = a^{m-n}\). The base can be a number or a pronumeral. This Year 8 maths page shows both laws with coefficients.

Multiplying: \(a^m \times a^n = a^{m+n}\). Keep the base, add the indices. Dividing: \(a^m \div a^n = a^{m-n}\). Keep the base, subtract the indices. Both laws need the same base.

A number or pronumeral on its own has index \(1\): \(p = p^1\), so \(p^6 \div p = p^5\).

A number in front is separate. Multiply or divide the coefficients as ordinary numbers, then use the law on the powers: \(3x^4 \times 2x^3 = (3 \times 2) \times x^{4+3} = 6x^7\), and \((5 \times 7^3) \times (2 \times 7^6) = 10 \times 7^9\). If the numbers do not divide exactly, leave a fraction.

Two different bases stay apart: group like bases and work on each one. When the bottom index is bigger, the leftover power stays on the bottom: \(\dfrac{11^2}{11^5} = \dfrac{1}{11^3}\).

Powers of 10. Large amounts written as a number times a power of \(10\) can be multiplied and divided with the laws in one step.

Why the index laws work x to the 4 times x cubed is seven x factors, x to the 7. p to the 6 divided by p squared leaves four p factors, p to the 4. x⁴ × x³ = (x·x·x·x) × (x·x·x) = x⁷ p⁶ ÷ p² = (p·p·p·p·p·p) ÷ (p·p) = p⁴
Count the factors: multiplying puts them together, so the indices add; dividing cancels them in pairs, so the indices subtract.

The index laws for multiplying and dividing:

\[ a^m \times a^n = a^{m+n} \]
a m × a n = a ( m + n )
\[ a^m \div a^n = a^{m-n} \]
a m ÷ a n = a ( m − n )
Keep the base. \(6^3 \times 6^2 = 6^5\), not \(36^5\).
The number in front is not part of the power. \(4 \times 2^3 = 32\), not \(8^3\).

How to simplify a product or quotient of powers

  1. Group the numbers in front, and each base on its own.
  2. Multiply or divide the numbers in front.
  3. Add indices when multiplying, subtract when dividing.
Example 1 — Multiplying pronumeral powers
Simplify \(3x^4 \times 2x^3\).
Solution
\(3x^4 \times 2x^3\)\(=\)\((3 \times 2) \times x^4 \times x^3\)
\(\)\(=\)\(6x^{4+3} = 6x^7\)
6 x

\(6x^7\)

Example 2 — Dividing pronumeral powers
Simplify \(12p^6 \div 4p\).
Solution
\(12p^6 \div 4p\)\(=\)\((12 \div 4) \times p^6 \div p^1\)
\(\)\(=\)\(3p^{6-1} = 3p^5\)
3 p

\(3p^5\)

Example 3 — Two laws with numbers
Write each as a single power.
(i) \(4^5 \times 4^3\)
(ii) \(12^7 \div 12^3\)
Solution
\(4^5 \times 4^3\)\(=\)\(4^8\)
\(12^7 \div 12^3\)\(=\)\(12^4\)
412

(i) \(4^8\)
(ii) \(12^4\)

Example 4 — A number in front
Simplify
(i) \((6 \times 2^5) \times (4 \times 2^3)\)
(ii) \((30 \times 8^9) \div (5 \times 8^6)\)
Solution
\(\)\(=\)\(24 \times 2^8\)
\(\)\(=\)\(6 \times 8^3 = 3072\)
24×26×8=3072

(i) \(24 \times 2^8\)
(ii) \(6 \times 8^3 = 3072\)

Example 5 — Two pronumerals
Simplify
(i) \(\dfrac{30a^7b^5}{6a^3b}\)
(ii) \(4m^3n \times 5m^2n^4 \div 10mn^3\)
Solution
\(\dfrac{30a^7b^5}{6a^3b}\)\(=\)\(5a^4b^4\)
\(20m^5n^5 \div 10mn^3\)\(=\)\(2m^4n^2\)
5 a b 2 m n

(i) \(5a^4b^4\)
(ii) Multiply first (left to right): \(2m^4n^2\)

Example 6 — Hidden index, powers of 10
(i) Find the hidden index: \((4 \times 6^{?}) \times (3 \times 6^5) = 12 \times 6^{12}\).
(ii) A plan gives \(8 \times 10^{10}\) bytes of data. A song uses \(4 \times 10^6\) bytes. How many songs is that?
Solution
\({?} + 5\)\(=\)\(12\)
\((8 \div 4) \times 10^{10-6}\)\(=\)\(2 \times 10^4\)
=720000 songs

(i) \(7\)
(ii) \(20\,000\) songs

Common pitfalls

Multiplying the bases. \(2^3 \times 2^4 = 2^7\), not \(4^7\).
Multiplying the indices. \(x^2 \times x^5 = x^7\), not \(x^{10}\).
Forgetting the coefficients. \(3a^2 \times 4a^3 = 12a^5\), not \(7a^5\).
Combining different bases. \(2^5 \times 7^3\) is not one power.

Frequently asked questions

What is the index law for multiplying?

Same base: add the indices. \(y^3 \times y^4 = y^7\).

What is the index law for dividing?

Same base: subtract the indices. \(m^8 \div m^3 = m^5\).

What do you do with the numbers in front?

Multiply or divide them normally: \(6k^5 \div 2k^2 = 3k^3\).

Can you use the laws with different bases?

No. Work on each base separately.

What index does a pronumeral on its own have?

\(1\): \(x = x^1\).