Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 7 Maths Integers

Order of Operations

20 practice questions 1 video lesson Theory + worked examples
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

The order of operations is the agreed order for working out an expression, so that everyone gets the same answer. This Year 7 maths page explains BODMAS (brackets, orders, division and multiplication, addition and subtraction) and uses it with negative numbers, fraction bars, powers and missing numbers.

Use BODMAS to remember the order:

LetterStep
BBrackets first (and other grouping symbols, such as a fraction bar)
OOrders: powers and square roots
DMDivision and Multiplication, working from left to right
ASAddition and Subtraction, working from left to right

A fraction bar is a grouping symbol: work out the whole top and the whole bottom, then divide.

Use the integer rules at every step. Subtracting a negative is the same as adding: \(-(-4) = +4\).

Order of operations, one step per line Five lines of working for 2 minus 12 divided by the bracket 1 minus 4. Brackets give minus 3, dividing gives minus 4, minus minus 4 becomes plus 4, and the answer is 6. 2 − 12 ÷ (1 − 4)start = 2 − 12 ÷ (−3)brackets = 2 − (−4)divide = 2 + 4double sign = 6subtract last
The brackets come first, then the division. The subtraction is done last, even though it is written first.

The order, from first to last:

\[ \text{B} \;\to\; \text{O} \;\to\; \text{DM} \;\to\; \text{AS} \]
B then O then DM then AS
\[ 1 + 5 \times (-3) = 1 + (-15) = -14 \]
1+5×(−3)=1+(−15)=−14
\[ 24 \div 4 \times 2 = 6 \times 2 = 12 \]
24÷4×2=6×2=12
\[ (-4)^2 = 16, \quad -4^2 = -16 \]
(−4)2=16,−42=−16
Equal partners. \(\times\) and \(\div\) have equal priority, and so do \(+\) and \(-\). Do whichever comes first from the left.
Words to brackets. “The product of \(-2\) and the sum of \(7\) and \(-10\)” puts the sum in brackets: \(-2 \times (7 + (-10)) = -2 \times (-3) = 6\).

How to evaluate an expression

  1. Brackets and other grouping symbols first.
  2. Powers next.
  3. Multiply and divide from left to right.
  4. Add and subtract from left to right. Write one step per line.

How to find a missing number

  1. Simplify every part you can.
  2. Undo the operations in reverse order, doing the same to both sides.
  3. Check by putting the number back in.
Example 1 — Multiply before adding
Work out \(6 + 7 \times (-2) - 4 \div 2\).
Solution

Multiply and divide first, then add and subtract from left to right.

\(7 \times (-2)\)\(=\)\(-14\)
\(4 \div 2\)\(=\)\(2\)
\(6 - 14 - 2\)\(=\)\(-8 - 2\)
\(\)\(=\)\(-10\)
6+7×(−2)−4÷2=6−14−2=−10

\(-10\)

Example 2 — Grouping symbols
Work out
(i) \(-4 \times (3 - 9)\)
(ii) \(3 - \dfrac{14 - 2}{1 - 5}\)
Solution
\(-4 \times (3 - 9)\)\(=\)\(-4 \times (-6) = 24\)
\(3 - \dfrac{14 - 2}{1 - 5}\)\(=\)\(3 - \dfrac{12}{-4}\)
\(\)\(=\)\(3 - (-3) = 6\)
−4×(3−9)=24,3−(12/−4)=6

(i) \(24\)
(ii) \(6\)

Example 3 — Powers
Work out
(i) \((-5)^2 - 30\)
(ii) \(-2^2 + 3 \times (-2)\)
Solution
\((-5)^2 - 30\)\(=\)\(25 - 30\)
\(\)\(=\)\(-5\)
\(-2^2 + 3 \times (-2)\)\(=\)\(-4 + (-6)\)
\(\)\(=\)\(-10\)
(−5)2−30=−5,−22+3×(−2)=−10

(i) \(-5\)
(ii) Only the \(2\) is squared: \(-10\)

Example 4 — Missing number
Find the missing number: \(4 \times \square - 3 \times (2 + 5) - 8 = 3\).
Solution
\(4 \times \square - 21 - 8\)\(=\)\(3\)
\(4 \times \square - 29\)\(=\)\(3\)
\(4 \times \square\)\(=\)\(32\)
\(\square\)\(=\)\(8\)
4×−29=3,4×=32,=8

Check: \(4 \times 8 - 21 - 8 = 3\). The missing number is \(8\).

Example 5 — Missing number in a game
A green square scores \(+3\) and a red square scores \(-2\). Leo landed on \(5\) green squares and his total was \(-7\). How many red squares did he land on?
Solution

Green squares: \(5 \times 3 = 15\). Then undo the operations.

\(15 + \square \times (-2)\)\(=\)\(-7\)
\(\square \times (-2)\)\(=\)\(-22\)
\(\square\)\(=\)\(11\)
15+×(−2)=−7,×(−2)=−22,=11

Check: \(5 \times 3 + 11 \times (-2)\) \(= 15 - 22 = -7\). He landed on \(11\) red squares.

Example 6 — Words to an expression
Write each as an expression and evaluate it.
(i) The product of \(-3\) and the sum of \(5\) and \(-8\).
(ii) The sum of \(-3 \times 5\) and \(-8\).
Solution
\(-3 \times (5 + (-8))\)\(=\)\(-3 \times (-3)\)
\(\)\(=\)\(9\)
\(-3 \times 5 + (-8)\)\(=\)\(-15 + (-8)\)
\(\)\(=\)\(-23\)
−3×(5+(−8))=9,−3×5+(−8)=−23

(i) \(9\)
(ii) \(-23\)

Common pitfalls

Just going left to right. \(1 + 5 \times (-3) = -14\). Adding first gives \(-18\), which is wrong.
Multiplying before dividing. \(24 \div 4 \times 2 = 12\), not \(24 \div 8 = 3\). Go left to right.
Brackets on powers. \((-4)^2 = 16\), but \(-4^2 = -16\).
Ignoring the fraction bar. In \(\dfrac{14 - 2}{1 - 5}\) work out the whole top and the whole bottom before dividing.

Frequently asked questions

What does BODMAS stand for?

Brackets, Orders (powers and roots), Division and Multiplication, Addition and Subtraction.

Do you always multiply before dividing?

No. Multiplication and division have equal priority. Work from left to right.

Is a fraction bar like brackets?

Yes. Work out the top and the bottom first, then divide.

What is -3 squared?

Without brackets, \(-3^2 = -9\). With brackets, \((-3)^2 = 9\).

Why do we need an order of operations?

So that everyone works out the same expression in the same way and gets the same answer.