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Year 4 Maths Area

Area of rectangles using a grid

20 practice questions 0 video lessons Theory + worked examples
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Theory

Area of rectangles using a grid is a Year 4 measurement skill: finding how many unit squares cover a rectangle. This page shows how to count squares on a centimetre grid, how rows of squares times the squares in each row links to multiplication, and how area is measured in square centimetres and square metres. Curriculum: VC2M4M02 / AC9M4M02.

Area is the amount of surface a shape covers. We measure it in square units. On a 1 cm grid, every small square is one square centimetre, written \(1\text{ cm}^2\).

To find the area of a rectangle on a grid, count the unit squares inside it. The squares sit in equal rows, so instead of counting one by one you can multiply: the number of rows times the number of squares in each row. This is the same as length times width.

A rectangle with 4 rows of 7 squares covers \(4 \times 7 = 28\) squares, so its area is \(28\text{ cm}^2\). On a metre grid each square is \(1\text{ m}^2\), and the counting works the same way.

Rectangle on a grid with 4 rows and 7 columns A rectangle drawn on a centimetre grid, made of 4 rows and 7 columns of 1 cm squares. Counting gives 28 squares, so the area is 28 square centimetres. 7 columns 4 rows Area = 4 × 7 = 28 cm²
Count the squares: 4 rows of 7 make 28 unit squares.
Rectangle 7 cm by 5 cm on a grid showing length times width A rectangle 7 columns wide and 5 rows tall on a centimetre grid. The length is 7 cm and the width is 5 cm, so the area is 7 times 5, which is 35 square centimetres. Area = 7 × 5 = 35 cm² width = 5 cm length = 7 cm
Length times width gives the same count: \(7 \times 5 = 35\).

Finding the area of a rectangle uses one simple rule, written two ways.

\[ \text{Area} = \text{length} \times \text{width} \]
Area=length×width
\[ \text{Area} = \text{rows} \times \text{squares in each row} \]
Area=rows×squares in each row
\[ \text{Square: } \text{Area} = \text{side} \times \text{side} \]
Square: Area=side×side
\[ 1\text{ cm} \times 1\text{ cm} = 1\text{ cm}^2 \]
1 cm×1 cm=1 cm2
Rows times columns is the same as length times width. Both count the unit squares that cover the rectangle. Always give the answer in square units, such as \(\text{cm}^2\) or \(\text{m}^2\).

How to find the area of a rectangle on a grid

  1. Count the rows. Look at the rectangle on the grid and count how many rows of squares it has.
  2. Count each row. Count how many squares are in one row. Every row has the same number.
  3. Multiply. Times the number of rows by the squares in each row. Write the answer in square units, like \(\text{cm}^2\) or \(\text{m}^2\).
  4. Check. Counting every square, adding the rows (\(7 + 7 + 7 + 7\)) and multiplying (\(4 \times 7\)) all give the same answer.

If you know the area and one side, work backwards: ask what number times the side gives the area, or divide the area by the side.

Example 1 β€” Count the squares
The rectangle is drawn on a \(1\text{ cm}\) grid. What is its area?
Rectangle on a grid with 3 rows and 9 columns A rectangle on a centimetre grid made of 3 rows and 9 columns of 1 cm squares, 27 squares in total. 9 columns 3 rows 27 squares
Solution
\(9 + 9 + 9\)\(=\)\(27\)
\(3 \times 9\)\(=\)\(27\)
3×9=27

Adding the rows or multiplying gives the same count. The area is \(27\text{ cm}^2\).

Example 2 β€” Rows times columns
Find the area of a rectangle that is \(9\text{ cm}\) long and \(4\text{ cm}\) wide.
Rectangle 9 cm by 4 cm on a grid with 4 rows and 9 columns A rectangle on a centimetre grid made of 4 rows and 9 columns of 1 cm squares, 36 squares in total. 9 columns 4 rows 36 squares
Solution
\(\text{length} \times \text{width}\)\(=\)\(9 \times 4\)
\(9 \times 4\)\(=\)\(36\)
9×4=36

The area is \(36\text{ cm}^2\).

Example 3 β€” Tiles on a floor
A floor is covered with tiles that are each \(1\text{ m}\) by \(1\text{ m}\). The floor is \(8\text{ m}\) long and \(5\text{ m}\) wide. What is its area?
Solution
\(5\text{ rows of }8\text{ tiles}\)\(=\)\(8 \times 5\)
\(8 \times 5\)\(=\)\(40\)
8×5=40

The area is \(40\text{ m}^2\). Adding \(8 + 5 = 13\) would not count the tiles.

Example 4 β€” Same area, new sides
A rectangle is \(2\text{ cm}\) by \(14\text{ cm}\). Find a different rectangle with the same area.
Solution
\(2 \times 14\)\(=\)\(28\text{ cm}^2\)
\(4 \times 7\)\(=\)\(28\text{ cm}^2\)
4×7=28

A \(4\text{ cm}\) by \(7\text{ cm}\) rectangle has the same area, \(28\text{ cm}^2\). So does \(1\text{ cm}\) by \(28\text{ cm}\).

Example 5 β€” Find the missing side
A rectangle on a centimetre grid has an area of \(32\text{ cm}^2\). It is \(8\text{ cm}\) long. How wide is it?
Solution
\(8 \times \square\)\(=\)\(32\)
\(32 \div 8\)\(=\)\(4\)
\(\text{width}\)\(=\)\(4\text{ cm}\)
32 / 8 = 4 cm

Ask: \(8\) times what makes \(32\)? The rectangle is \(4\text{ cm}\) wide. Check: \(8 \times 4 = 32\).

Example 6 β€” Which bed is bigger?
Bed P is \(11\) m long and \(2\) m wide. Bed Q is \(7\) m long and \(4\) m wide. Which bed has the larger area, and by how much?
Solution
\(P\)\(=\)\(11 \times 2 = 22\text{ m}^2\)
\(Q\)\(=\)\(7 \times 4 = 28\text{ m}^2\)
\(28 - 22\)\(=\)\(6\text{ m}^2\)
P 22 m2, Q 28 m2, difference 6 m2

Find both areas, then subtract. Bed Q is larger by \(6\text{ m}^2\), even though Bed P is longer.

Example 7 β€” A square
A square tile has sides of \(6\) cm. What is its area?
Solution
\(\text{area}\)\(=\)\(6 \times 6\)
\(6 \times 6\)\(=\)\(36\text{ cm}^2\)
6 x 6 = 36 cm2

A square is a rectangle with equal sides, so multiply the side by itself. The area is \(36\text{ cm}^2\).

Example 8 β€” A large floor
A hall floor is \(9\) m long and \(6\) m wide. What is its area?
Solution
\(9 \times 6\)\(=\)\(54\)
\(\text{area}\)\(=\)\(54\text{ m}^2\)
9 x 6 = 54 m2

Think of \(6\) rows of \(9\) square metres. The area is \(54\text{ m}^2\).

Common pitfalls

Do not add the sides. Watch out for adding length and width. That gives the perimeter (the distance around), not the area. For \(4\) by \(7\) the area is \(4 \times 7 = 28\), not \(4 + 7 = 11\).
Use square units. Area is written in \(\text{cm}^2\) or \(\text{m}^2\), never plain \(\text{cm}\). The small \(2\) tells everyone you counted squares.
Keep the rows equal. Before you multiply, check that every row has the same number of squares. If a row is missing squares, count carefully instead.

Frequently asked questions

How do you find the area of a rectangle on a grid?

Count the unit squares that cover the rectangle. The squares line up in equal rows, so you can multiply the number of rows by the number of squares in each row. For 4 rows of 7 squares the area is \(4 \times 7 = 28\text{ cm}^2\).

What is a square centimetre?

A square centimetre is a square that is 1 cm long and 1 cm wide. Its area is \(1\text{ cm}^2\). We find area by counting how many of these squares fit inside a shape.

What is the difference between area and perimeter?

Area is the number of squares that cover a shape, measured in square units. Perimeter is the distance all the way around. You add the sides for perimeter, but you multiply the rows by the columns for area.

Why do you multiply length by width to find area?

Because the unit squares sit in equal rows. Multiplying the number of rows by the number of squares in each row counts every square quickly, which is the same as length times width.

What units are used to measure area?

Area is measured in square units, such as square centimetres \((\text{cm}^2)\) or square metres \((\text{m}^2)\). Area is never written in plain centimetres.

Can two rectangles have the same area but different side lengths?

Yes. A \(3\) by \(12\) rectangle and a \(4\) by \(9\) rectangle both cover \(36\) squares, so both have an area of \(36\text{ cm}^2\) even though their side lengths are different.