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Year 11 General Linear Equations And Their Graphs

Developing A Linear Equation From A Word Description

13 practice questions 2 video lessons Theory + worked examples

Theory

Many real-world problems can be solved by translating the words into a linear equation, then solving it. This page covers the four-step word-to-equation method, common phrase translations, and worked examples on number, age, cost-comparison, and average problems.

Many real-world problems can be solved by translating the words into a linear equation, then solving it. The challenge is choosing the right variable, expressing other quantities in terms of it, and writing the relationship between the two sides.

Look for the key relationship words: "total", "sum", "difference", "equals", "is the same as", "average". These tell you what the two sides of the equation are. Words like "increased by", "less than", "twice", "one-third of" tell you how to build the algebraic expressions on each side.

The most important rule: always answer the actual question at the end. The variable you chose might not be what the question is asking for — re-read the question after solving.

Four-step workflow for word problems Four steps: let x equal something, write other quantities in terms of x, form an equation, then solve and check. Words → Equation → Answer 1 Let x = unknown 2 Other quantities in terms of x 3 Form the equation 4 Solve & answer the actual question
The four-step workflow for any word problem.
Translating common phrases to algebra Common English phrases and their algebraic equivalents. Words → Algebra English Algebra a number x twice a number 2x number increased by 5 x + 5 5 less than a number x − 5 one-third of a number x / 3 next consecutive integer x + 1
Common phrases and their algebraic equivalents.

Common phrases and their algebraic translations:

WordsAlgebra
"a number"x
"twice a number"2x
"a number, increased by 5"x+5
"5 less than a number"x5
"one-third of a number"x3
"the next consecutive number"x+1
"$15 per item plus $8 flat fee"15n+8

Common relationship patterns:

quantity1+quantity2=total
q1+q2=total
costA=costB(equal-cost problems)
costA=costB
sum of valuescount=average
sumcount=average

The four-step method

  1. Let x= something specific. Choose the smallest unknown, or the one the question asks about.
  2. Write each other quantity in terms of x. Use the translation table when in doubt.
  3. Form an equation that captures a relationship from the question (often a total, a difference, or "the same as").
  4. Solve the equation, then check the answer makes sense in the original context — and answer the actual question.

Common problem types. "Find the number" — let x be the number. "Total of X items" — sum = given total. "Two consecutive integers" — use x and x+1. "When are the costs equal" — set the two cost expressions equal. "Average is ..." — sum of values divided by count equals the average.

Example 1 — "Find the Number"
Three times a number, decreased by 7, gives 20. Find the number.
Solution

Let x be the number.

3x7=20
3x=27
x=9
x=9
Example 2 — Two Related Quantities
Tom has $9 less than Jerry. Together they have $41. Find Jerry's amount.
Solution

Let j be Jerry's amount, so Tom has j9.

j+(j9)=41
2j9=41
2j=50
j=25

Jerry has $25.

j=25
Example 3 — Cost Comparison
Plan A is a flat $30 per month. Plan B is $10 plus $0.50 per text. How many texts make the plans cost the same?
Solution

Let n be the number of texts. Set the two costs equal.

30=10+0.5n
20=0.5n
n=40

At 40 texts, both plans cost $30.

n=40
Example 4 — Average
Liam scored 78, 85 and 90 on his first three tests. What does he need on the fourth to average 84?
Solution

Let x be the fourth score. The average equation is sum divided by count.

78+85+90+x4=84
253+x=336
x=83
x=83

Common pitfalls

Reversing subtraction. "5 less than a number" is x5, not 5x. The order matters. The same goes for "decreased by" and "reduced by".
Wrong unknown chosen. If the question asks for the larger of two quantities and you solved for the smaller, you still need to add the difference to get the final answer. Re-read the question after solving.
Coin and money mismatches. If the value is in dollars, keep all amounts in dollars (50c =$0.50). If in cents, multiply dollar amounts by 100. Mixing units gives nonsense.
Age "in n years time". Add n to the current age, not the other way round. If Sam is currently x years old, then in 4 years he will be x+4, not x4.

Frequently asked questions

How do I turn a word problem into an equation?

Let x equal something specific (often the smallest unknown or the quantity the question asks about). Then write every other quantity in terms of x. Finally, write an equation that captures a key relationship from the problem — usually a total, a difference, or something being equal.

What does '5 less than a number' mean as algebra?

It is x minus 5, not 5 minus x. The order matters: 5 less than a number means you start with the number and take 5 away.

How do I solve a 'when are the costs equal' problem?

Write a formula for each cost in terms of the same variable (such as number of texts or minutes). Then set the two formulas equal to each other and solve for that variable.

What goes wrong with consecutive numbers?

Use x and x plus 1 for two consecutive integers, or x, x plus 2, x plus 4 for consecutive even or odd numbers. The key is that the gap is constant. Then form an equation from the given relationship (often a sum or product).

Why do I need to answer the actual question at the end?

Because the variable you chose might not be what the question is asking for. If x equals 7 but the question asks for the larger of two numbers (which is x plus 5), the answer is 12, not 7. Always re-read the question after solving.

How do I handle 'in 4 years time' age problems?

If a person's current age is x, then in 4 years time their age is x plus 4. If they were 3 years old 6 years ago, their current age is x where x minus 6 equals 3, so x equals 9. Build the equation from how old they will be or were, not their current age.

Video Lessons

  • Writing Equations from Word Problems Watch
  • Basic linear equation word problem | 7th grade | Khan Academy Watch

Practice Questions

13 questions available.

Practice Questions