Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 10 Maths - 10A Trigonometry

Graphs of Trigonometric Functions

20 practice questions 2 video lessons Theory + worked examples
Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 2 video(s)
  • Graphs of Trigonometric Functions - Video - Beautiful Trigonometry Watch
  • Graphs of Trigonometric Functions - Video - Graphing the Sine Function (using degrees) Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

The graphs of \(y = \sin x\) and \(y = \cos x\) are waves between \(-1\) and \(1\) that repeat every \(360^\circ\); \(y = \tan x\) repeats every \(180^\circ\) and has asymptotes. This Year 10A maths page covers their key features, amplitude and period, transformations such as \(y = a\sin x\), \(y = \sin(bx)\) and \(y = \cos x + c\), reading equations and inequalities from a graph, and simple models such as tides and temperatures.

Plotting \(\sin x\) for every angle \(x\) gives a wave. It starts at \(0\), reaches a maximum of \(1\) at \(90^\circ\), returns to \(0\) at \(180^\circ\), has a minimum of \(-1\) at \(270^\circ\) and is back at \(0\) at \(360^\circ\). Then it repeats.

\(y = \cos x\) has the same shape, starting at its maximum: \(1\) at \(0^\circ\), \(0\) at \(90^\circ\), \(-1\) at \(180^\circ\), \(0\) at \(270^\circ\), \(1\) at \(360^\circ\). Both have range \(-1 \le y \le 1\).

\(y = \tan x\) is \(0\) at \(0^\circ\), \(180^\circ\) and \(360^\circ\). Where \(\cos x = 0\) it is undefined, and the graph has a vertical asymptote: a dashed line the curve approaches but never meets. Its range is all real numbers.

The period is the length of one complete wave along the \(x\)-axis: \(360^\circ\) for sine and cosine, \(180^\circ\) for tangent. The amplitude is the height from the centre line of a wave to a maximum, half the distance from the minimum to the maximum. For \(y = \sin x\) and \(y = \cos x\) the amplitude is \(1\); tangent has none.

The graphs show the angle facts as shapes. The sine graph is symmetric about \(x = 90^\circ\), so \(\sin(180^\circ - x) = \sin x\). The cosine graph is the sine graph moved \(90^\circ\) left. Turning \(\cos x\) upside down gives \(\cos(180^\circ + x) = -\cos x\), and \(\tan(-x) = -\tan x\) reflects the tangent graph.

Graphs of y = sin x and y = cos x from 0 to 360 degreesTwo waves between y = -1 and y = 1. The sine curve starts at 0, peaks at 1 at 90 degrees, crosses at 180, has its minimum of -1 at 270 and returns to 0 at 360. The cosine curve starts at 1, crosses at 90, has its minimum at 180, crosses at 270 and returns to 1 at 360. x y 90° 180° 270° 360° −1 1 y = sin x y = cos x
Sine and cosine waves repeat every \(360^\circ\) and stay between \(-1\) and \(1\). The cosine graph is the sine graph shifted \(90^\circ\) to the left.
Graph of y = tan x from 0 to 360 degreesThe tangent curve passes through 0 at 0, 180 and 360 degrees and rises steeply towards dashed vertical asymptotes at 90 and 270 degrees, where tan x is undefined. It repeats every 180 degrees. x y 90° 180° 270° 360° −2 2 y = tan x
\(y = \tan x\) repeats every \(180^\circ\). It has vertical asymptotes where \(\cos x = 0\), at \(x = 90^\circ\) and \(270^\circ\).

Transformations, shown for sine (cosine and tangent work the same way):

GraphEffect on \(y = \sin x\)
\(y = a\sin x\)vertical dilation by factor \(a\): range \(-a \le y \le a\) (\(a \gt 0\))
\(y = \sin x + c\)translation \(c\) units up (down if \(c < 0\))
\(y = \sin(x - h)\)translation \(h\) to the right; \(\sin(x + h)\) moves left
\(y = \sin(bx)\)horizontal dilation by factor \(\dfrac{1}{b}\): one wave every \(\dfrac{360^\circ}{b}\)
\(y = -\sin x\)reflection in the \(x\)-axis
\[y = a\sin(bx) \quad\Rightarrow\quad \text{amplitude } a,\ \text{period } \dfrac{360^\circ}{b}\]
y=asin(bx)
Amplitude and period. The number in front changes the amplitude only: \(y = 4\cos x\) has amplitude \(4\) and period \(360^\circ\). The number multiplying \(x\) changes the period only: \(y = \sin 3x\) has amplitude \(1\) and period \(\dfrac{360^\circ}{3} = 120^\circ\). Adding a number moves the wave up or down and changes neither.
Range in one line. Start from \(-1 \le \sin x \le 1\) and apply the same operations to all three parts. For \(y = 2\sin x + 3\): \(-2 + 3 \le y \le 2 + 3\), so \(1 \le y \le 5\).
Number of solutions. A horizontal line \(y = k\) with \(-1 < k < 1\) cuts each full wave of \(y = \sin x\) or \(y = \cos x\) twice. So \(\sin x = k\) has two solutions in \(0^\circ\)–\(360^\circ\) and four in \(-360^\circ\)–\(360^\circ\).

How to sketch a transformed trig graph

  1. Start with the five key points of the basic graph: \(0^\circ\), \(90^\circ\), \(180^\circ\), \(270^\circ\), \(360^\circ\).
  2. Apply each change: multiply \(y\) by \(a\), add \(c\) to \(y\), move \(x\) by \(h\), or divide \(x\) by \(b\).
  3. Join the points with a smooth wave, add asymptotes for tangent, and check the range and intercepts.

Reading information from a graph

  1. Maximum and minimum: read the highest and lowest \(y\)-values and where they occur.
  2. \(x\)-intercepts: set \(y = 0\) and solve, or read where the curve crosses the axis.
  3. Which graph is it? Make a table of values at \(0^\circ\), \(90^\circ\), \(180^\circ\), \(270^\circ\), \(360^\circ\) (or every \(45^\circ\) for \(\sin 2x\)) and match it.
  4. Finding \(a\) and \(b\) in \(y = a\sin(bx)\): \(a\) is the maximum value; \(b\) is the number of full waves in \(360^\circ\).
  5. Where two graphs meet: solve the equation, e.g. \(\sin x = \cos x\) gives \(\tan x = 1\).
  6. Inequalities: solve the equation for the boundary, then read from the graph where the curve is above or below the line (Example 3).
  7. Models: the largest and smallest values come from \(\sin\) or \(\cos\) being \(1\) or \(-1\); solve for the time (Example 4).
Example 1 — Stretch and shift
For \(y = 3\cos x + 1\), \(0^\circ \le x \le 360^\circ\):
(i) describe the graph as transformations of \(y = \cos x\)
(ii) find the range
(iii) find the \(x\)-intercepts, correct to one decimal place.
Solution

(i) Multiply every \(y\)-value by \(3\) (a vertical dilation by factor \(3\)), then add \(1\) (a translation \(1\) unit up).

(ii) Start from \(-1 \le \cos x \le 1\) and do the same to each part:

\(-3 \le 3\cos x\)\(\le\)\(3\)
\(-2 \le 3\cos x + 1\)\(\le\)\(4\)

The range is \(\mathbf{-2 \le y \le 4}\).

(iii) Let \(y = 0\). Cosine is negative in quadrants 2 and 3.

\(\cos x\)\(=\)\(-\dfrac{1}{3}\)
\(\alpha\)\(=\)\(\cos^{-1}\left(\dfrac{1}{3}\right) = 70.528\ldots^\circ\)
\(x\)\(=\)\(180^\circ - \alpha \approx \mathbf{109.5^\circ}\)
\(\text{or } x\)\(=\)\(180^\circ + \alpha \approx \mathbf{250.5^\circ}\)
Graph of y = 3 cos x + 1The graph of y = 3 cos x + 1 from 0 to 360 degrees, with the graph of y = cos x shown faintly. It has a maximum of 4 at 0 and 360 degrees and a minimum of -2 at 180 degrees, and crosses the x-axis at about 109.5 and 250.5 degrees, marked with red dots. x y 90° 180° 270° 360° −2 1 4 y = 3 cos x + 1
y=3cosx+1,−2≤y≤4
Example 2 — A horizontal shift
Describe the graph of \(y = \cos(x + 30^\circ)\) as a transformation of \(y = \cos x\), and state its \(x\)-intercepts and the \(x\)-values of its maximum and minimum for \(0^\circ \le x \le 360^\circ\).
Solution

Replacing \(x\) by \(x + 30^\circ\) moves the graph \(30^\circ\) to the left. Every key point of \(y = \cos x\) moves back \(30^\circ\).

\(x\)-intercepts\(:\)\(90^\circ - 30^\circ = \mathbf{60^\circ}\),
\(270^\circ - 30^\circ = \mathbf{240^\circ}\)
minimum \((-1)\)\(:\)\(180^\circ - 30^\circ = \mathbf{150^\circ}\)
maximum \((1)\)\(:\)\(360^\circ - 30^\circ = \mathbf{330^\circ}\)
Graph of y = cos(x + 30 degrees) compared with y = cos xThe graph of y = cos of x plus 30 degrees, which is the cosine graph moved 30 degrees to the left. It crosses the x-axis at 60 and 240 degrees, has its minimum of -1 at 150 degrees and its maximum of 1 at 330 degrees. The graph of y = cos x is shown faintly. x y 90° 180° 270° 360° −1 1 y = cos(x + 30°)

The maximum at \(0^\circ\) moves to \(-30^\circ\), outside the domain, so the next one, at \(330^\circ\), is used. Check: \(\cos(330^\circ + 30^\circ) = \cos 360^\circ = 1\).

y=cos(x+30°)
Example 3 — Reading an inequality from a graph
Use the graph of \(y = \tan x\) to find the values of \(x\), \(0^\circ \le x \le 360^\circ\), for which \(\tan x > 1\).
Solution

First find where the curve meets the line \(y = 1\): \(\tan x = 1\) gives \(x = 45^\circ\) or \(180^\circ + 45^\circ = 225^\circ\).

Graph of y = tan x with the line y = 1The graph of y = tan x from 0 to 360 degrees with asymptotes at 90 and 270 degrees and the dashed red line y = 1. The curve is above the line between 45 and 90 degrees and between 225 and 270 degrees; these strips are shaded. x y 90° 180° 270° 360° −2 1 2 y = 1

The curve is above the line from each meeting point up to the next asymptote, where \(\tan x\) is undefined:

\(\)\(\)\(\mathbf{45^\circ} < x < \mathbf{90^\circ}\)
or \(\mathbf{225^\circ} < x < \mathbf{270^\circ}\)
45<x<90,225<x<270

The ends are not included: \(\tan x = 1\) there, and \(90^\circ\) and \(270^\circ\) have no value at all.

Example 4 — A trig model
The temperature in a greenhouse is modelled by \(T = 18 - 6\cos(15t)^\circ\) degrees Celsius, where \(t\) is the time in hours after midnight, \(0 \le t \le 24\).
(i) Find the lowest and highest temperatures and when they occur.
(ii) Between which times is the temperature at least \(21^\circ\)C?
Solution

(i) \(-1 \le \cos(15t)^\circ \le 1\), so \(T\) runs from \(18 - 6 = 12\) to \(18 + 6 = 24\).

lowest \(\mathbf{12^\circ}\)C\(:\)\(\cos(15t)^\circ = 1\),
\(15t = 0,\ t = 0\) (midnight)
highest \(\mathbf{24^\circ}\)C\(:\)\(\cos(15t)^\circ = -1\),
\(15t = 180,\ t = 12\) (noon)

(ii) Solve \(T = 21\) first.

\(18 - 6\cos(15t)^\circ\)\(=\)\(21\)
\(\cos(15t)^\circ\)\(=\)\(-\dfrac{1}{2}\)
\(15t\)\(=\)\(120 \text{ or } 240\)
\(t\)\(=\)\(8 \text{ or } 16\)
Temperature model T = 18 - 6 cos(15t) over 24 hoursA wave for the temperature from t = 0 to t = 24 hours. It starts at a minimum of 12 degrees at midnight, rises to a maximum of 24 at t = 12 and falls back to 12 at t = 24. A dashed red line at T = 21 meets the curve at t = 8 and t = 16, and the strip between is shaded. t T 4 8 12 16 20 24 12 18 21 24

The graph is above \(T = 21\) between these times: from \(\mathbf{8}\) am to \(\mathbf{4}\) pm.

T=18−6cos(15t)

Common pitfalls

Plus moves left. \(y = \cos(x + 30^\circ)\) moves the graph \(30^\circ\) to the left, not the right. Check by asking where the bracket equals \(0^\circ\).
Asymptotes are not part of the graph. \(\tan x\) has no value at \(90^\circ\) and \(270^\circ\). Do not join the branches across them, and do not include them in an inequality.
Range uses all three parts. From \(-1 \le \cos x \le 1\), multiply and add across the whole inequality. A negative multiplier flips the signs.
Include end points carefully. For \(\cos x < 0\) the zeros at \(90^\circ\) and \(270^\circ\) are not included; for \(\cos x \le 0\) they are.
A sine wave has two crossings per cycle. Find all solutions in the domain, not just the one the calculator gives.

Frequently asked questions

What does the graph of y = sin x look like?

It is a smooth wave between -1 and 1 that repeats every 360 degrees. It starts at 0, peaks at 1 at 90 degrees, crosses the axis at 180 degrees, dips to -1 at 270 degrees and returns to 0 at 360 degrees.

What is the difference between the sine and cosine graphs?

They have the same wave shape and range, but the cosine graph is shifted 90 degrees to the left. Cosine starts at its maximum of 1 when x is 0, while sine starts at 0.

Why does tan x have asymptotes?

tan x equals sin x divided by cos x. Where cos x is 0, at 90 and 270 degrees, the division is undefined and the graph shoots off to very large positive or negative values, so it has vertical asymptotes there.

What does a do in y = a sin x?

It stretches the graph vertically by a factor of a, so the maximum becomes a and the minimum becomes -a. The x-intercepts do not move.

What does b do in y = sin bx?

It squashes the graph horizontally, so there are b full waves in 360 degrees. Each wave is 360 divided by b degrees long.

What are the amplitude and period of a trig graph?

The period is the length of one full wave: \(360^\circ\) for \(y = \sin x\) and \(y = \cos x\), and \(\dfrac{360^\circ}{b}\) for \(y = \sin bx\). The amplitude is the height from the centre line to a maximum, which is \(a\) for \(y = a\sin x\).