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Year 10 Maths - 10A Indices and Surds

Power of a Power

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Theory

To raise a power to a power, multiply the indices: \((a^m)^n = a^{mn}\). Every factor inside a bracket is raised to the power, so \((ab)^n = a^nb^n\). This Year 10A maths page covers powers of products and fractions, negative bases, combining all the index laws, writing numbers with a common base and solving equations for an unknown index.

A power of a power such as \((a^4)^3\) means \(a^4 \times a^4 \times a^4\). That is \(3\) groups of \(4\) factors, so multiply the indices: \(a^{12}\).

A power of a product such as \((5xy^2)^2\) raises every factor inside the brackets to the power: \(5^2x^2y^4 = 25x^2y^4\). The number in front is raised to the power too.

With a negative number inside, the sign depends on the power. An even power gives a positive result; an odd power gives a negative result.

To combine the laws, remove brackets first, then multiply (add indices) and divide (subtract indices).

Numbers can be rewritten with a common base: \(4 = 2^2\), \(8 = 2^3\), \(16 = 2^4\), \(9 = 3^2\), \(27 = 3^3\), \(25 = 5^2\).

a squared, cubed, written out in fullThree groups, each holding a times a. That is 3 times 2, which is 6 factors of a, so a squared cubed equals a to the 6. (a2)3 means three lots of a2 a Γ— a Γ— a Γ— a Γ— a Γ— a 3 Γ— 2 = 6 factors of a (a2)3 = a6
A power of a power: multiply the indices, because you are repeating a group of factors.
Cube with edge 3k squaredA cube with every edge 3k squared. Its volume is 3k squared, cubed, which is 27k to the 6. 3k2 3k2 V = (3k2)3 = 27k6
Volume of a cube \(=\) edge\(^3\). Cube the \(3\) as well as the \(k^2\): \((3k^2)^3 = 3^3k^6 = 27k^6\).

For positive integers \(m\) and \(n\):

\[(a^m)^n = a^{mn} \qquad (ab)^n = a^n b^n \qquad \left(\dfrac{a}{b}\right)^n = \dfrac{a^n}{b^n}\]
(am)n=amn

With a coefficient \(p\):

\[(pa^m)^n = p^n a^{mn}\]
(pam)n=pnamn
Negative coefficients. \((-a)^{\text{even}}\) is positive and \((-a)^{\text{odd}}\) is negative: \((-3)^4 = 81\) but \((-3)^3 = -27\).
Area and volume. A square of side \(s\) has area \(s^2\); a cube of edge \(s\) has volume \(s^3\). With \(s = 3k^2\), the volume is \(27k^6\).
A missing index. If \((x^3)^n = x^{18}\), then \(3n = 18\), so \(n = 6\).
Common bases. Learn the powers: \(4 = 2^2\), \(8 = 2^3\), \(16 = 2^4\), \(32 = 2^5\), \(9 = 3^2\), \(27 = 3^3\), \(81 = 3^4\), \(25 = 5^2\), \(125 = 5^3\). Then \(8^x = (2^3)^x = 2^{3x}\).
Adding after expanding. The index laws work on products, not sums. Expand each bracket, then collect like terms only if the pronumerals and indices match: \((2x^3)^2 + 3(-x^2)^3 = 4x^6 - 3x^6 = x^6\).

How to simplify a power of a power

  1. Raise every factor inside the brackets to the power: the number, and each pronumeral.
  2. Work out the number: \(2^4 = 16\), \((-3)^2 = 9\). Check the sign for a negative number.
  3. Multiply the indices of each pronumeral.
  4. Finish any multiplying or dividing that is left, with the other index laws.

Different bases

  1. Rewrite each number as a power of the same base, such as \(2\) or \(3\).
  2. Apply the power-of-a-power law, then add or subtract indices.

Other questions

  1. Evaluate without a calculator: write each number in prime-power form, such as \(12^4 = 2^8 \times 3^4\), then cancel.
  2. Unknown index: write both sides as powers of one base and equate the indices. Two unknowns need two equations, one for each base.
  3. Single power: \(4^x \times 8^{x}\) becomes \(2^{2x} \times 2^{3x} = 2^{5x}\).
  4. In terms of another pronumeral: if \(p = 3^a\), then \(9^{a} = (3^a)^2 = p^2\).
  5. Show that questions: simplify the left side step by step until it matches the right side.
  6. Measurements: a volume or count such as \((2^4)^3\) small cubes uses the same law.
Example 1 β€” Powers of a power
Simplify:
(i) \((7^3)^4\), as a single power of \(7\)
(ii) \((2y^5)^3\)
Solution

Multiply the indices. In (ii), every factor inside the brackets is raised to the power, including the \(2\).

\((7^3)^4\)\(=\)\(7^{3 \times 4} = \boldsymbol{7^{12}}\)
\((2y^5)^3\)\(=\)\(2^3 \times y^{5 \times 3}\)
\(\)\(=\)\(\boldsymbol{8y^{15}}\)
(2y5)3=8y15

\(2^3 = 8\), not \(6\).

Example 2 β€” A fraction to an odd power
Simplify \(\left(-\dfrac{2a^3}{3b^2}\right)^3\).
Solution

Raise the numerator and the denominator to the power. An odd power of a negative is negative.

\(\left(-\dfrac{2a^3}{3b^2}\right)^3\)\(=\)\(-\dfrac{2^3(a^3)^3}{3^3(b^2)^3}\)
\(\)\(=\)\(\boldsymbol{-\dfrac{8a^9}{27b^6}}\)
−8a927b6

With an even power, such as \(4\), the answer would be positive.

Example 3 β€” Brackets first
Simplify \(\dfrac{(-3x^3y)^2 \times (2xy^4)^3}{12x^5y^9}\).
Solution

Raise every factor in each bracket to the power, including the number and its sign.

\((-3x^3y)^2\)\(=\)\(9x^6y^2\)
\((2xy^4)^3\)\(=\)\(8x^3y^{12}\)
\(\text{numerator}\)\(=\)\(72x^9y^{14}\)
\(\dfrac{72x^9y^{14}}{12x^5y^9}\)\(=\)\(\boldsymbol{6x^4y^5}\)
72x9y1412x5y9=6x4y5

\((-3)^2 = 9\) is positive because the power is even.

Example 4 β€” Find the index
Find \(n\) if \(9^3 \times 27^n \div 3 = 9^{13}\).
Solution

Write every number as a power of \(3\), using the power-of-a-power law.

\(9^3\)\(=\)\((3^2)^3 = 3^6\)
\(27^n\)\(=\)\((3^3)^n = 3^{3n}\)
\(9^{13}\)\(=\)\((3^2)^{13} = 3^{26}\)
\(3^{6 + 3n - 1}\)\(=\)\(3^{26}\)
\(3n + 5\)\(=\)\(26\)
\(n\)\(=\)\(\boldsymbol{7}\)
3n+5=26,n=7

Common pitfalls

Multiply, do not add. \((x^4)^3 = x^{12}\), not \(x^7\). Adding indices is for \(x^4 \times x^3\).
Raise the number too. \((3y^2)^3 = 27y^6\), not \(3y^6\) or \(9y^6\). The \(3\) is cubed: \(3 \times 3 \times 3 = 27\).
Powers are not multiplication. \(4^3\) is \(64\), not \(12\). Work out the coefficient by repeated multiplication.
Watch the sign. \((-a^2)^3 = -a^6\) because the power is odd; \((-a^2)^4 = a^8\) because it is even.
Not across + or βˆ’. \((x + 3)^2 \ne x^2 + 9\). The power laws only work on products and quotients.

Frequently asked questions

What is the power of a power rule?

When a power is raised to another power, multiply the indices: \((a^m)^n = a^{mn}\). For example, \((x^4)^3 = x^{12}\).

Do you add or multiply the indices?

Add them when multiplying two powers of the same base, such as \(x^2 \times x^3 = x^5\). Multiply them when a power is raised to another power, such as \((x^2)^3 = x^6\).

What happens to the number in front when you raise brackets to a power?

The number is raised to the power as well: \((2y^5)^3 = 2^3y^{15} = 8y^{15}\).

Is a negative number to an even power positive?

Yes. Pairs of negatives multiply to give positives, so an even power is positive and an odd power is negative: \((-2)^4 = 16\) but \((-2)^3 = -8\).

How do you write 49 cubed as a power of 7?

Write \(49\) as \(7^2\), then multiply the indices: \((7^2)^3 = 7^6\).

How do you solve an equation like 4 to the x equals 2 to the 10?

Write both sides with the same base: \(4^x = 2^{2x}\). Then \(2x = 10\), so \(x = 5\).