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Year 10 Maths - 10A Geometry

Congruent Triangles

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Theory

Two triangles are congruent if they are exactly the same shape and size. This Year 10A maths page covers the four congruence tests (SSS, SAS, AAS and RHS), writing a congruence statement in matching order, and using congruent triangles to find unknown sides and angles and to prove that lengths or angles are equal.

Two figures are congruent if one can be moved exactly on top of the other by translating, reflecting or rotating it. All matching sides and all matching angles are equal. The symbol is \(\equiv\).

To show two triangles are congruent you do not need all six facts. Any one of the four congruence tests is enough:

SSS β€” three pairs of equal sides. SAS β€” two pairs of equal sides and the included angle (the angle between them). AAS β€” two pairs of equal angles and a pair of matching sides. RHS β€” a right angle, the hypotenuse and one other side.

In a congruence statement such as \(\triangle PQR \equiv \triangle LMN\), the vertices are written in matching order: \(P \leftrightarrow L\), \(Q \leftrightarrow M\), \(R \leftrightarrow N\). Then \(PQ = LM\), \(\angle Q = \angle M\), and so on.

Three equal angles (AAA) is not a test: the triangles have the same shape but may be different sizes. If no test fits the information, the triangles cannot be shown to be congruent.

The four congruence testsFour pairs of matching triangles. SSS: three pairs of equal sides. SAS: two sides and the included angle. AAS: two angles and a side in the same position. RHS: a right angle, the hypotenuse and one other side. SSSSASAASRHS
Matching marks show the equal parts. The tests are SSS, SAS, AAS and RHS.
Equal angles do not make congruent trianglesA small triangle and a large triangle with the same three angles. They are the same shape but not the same size, so AAA is not a congruence test. small large same three angles, different sizes
AAA only proves the triangles are similar. Two sides and an angle that is not between them (SSA) is not a test either.
TestWhat must be equalWatch for
SSSall three pairs of sidesa common side counts as one pair
SAStwo pairs of sides and the angle between themthe angle must be between the two sides
AAStwo pairs of angles and one pair of matching sidesthe sides must be in the same position (opposite the same angle)
RHSa right angle, the hypotenuse and one other sideonly for right-angled triangles
Equal parts hidden in a diagram. A common side belongs to both triangles. Vertically opposite angles are equal. Alternate angles on parallel lines are equal. Radii of the same circle are equal. A midpoint gives two equal halves. Angles opposite equal sides of an isosceles triangle are equal. Every side of an equilateral triangle is equal and every angle is \(60^\circ\). Adding the same angle to two equal angles (or taking equal lengths from equal sides) leaves them equal.
After proving congruence. Every other pair of matching parts is now equal. Write the reason as "matching sides (or angles) of congruent triangles". This is how you prove two lines are equal, an angle is \(90^\circ\), or two lines are parallel (equal alternate angles).

How to prove two triangles are congruent

  1. Name the two triangles you are comparing.
  2. List three pairs of equal parts, one per line, each with a reason: given, common, vertically opposite, alternate angles, radii, midpoint.
  3. Name the test (SSS, SAS, AAS or RHS) that the three facts make.
  4. Write the congruence statement with the vertices in matching order.
  5. Conclude what you were asked: a side, an angle or a parallel line, using "matching parts of congruent triangles".

What a congruence proof can show

  1. Two lengths are equal, such as a point being a midpoint, or two sides of a triangle being equal (so the triangle is isosceles).
  2. Two angles are equal, such as a line bisecting an angle.
  3. A right angle: two matching angles that are equal and also make a straight line are each \(90^\circ\).
  4. Parallel lines: equal alternate (or corresponding) angles show the lines are parallel.

Finding an unknown

  1. Match the vertices from the statement or from the equal marks.
  2. Set matching sides or angles equal. If they are written with a pronumeral, solve the equation.
  3. Finish with another rule if needed: the angle sum of a triangle, Pythagoras' theorem, or adding sides for a perimeter.
Example 1 β€” Choosing the test
Which test shows that the triangles are congruent? Write the congruence statement with the vertices in matching order.
Solution
Two triangles with two sides and the included angle equalTriangle PQR has PR 6 cm, QR 10 cm and angle R 72 degrees. Triangle LMN has LN 6 cm, MN 10 cm and angle N 72 degrees. 6 cm 10 cm 72Β° 6 cm 10 cm 72Β° P Q R L M N

The \(72^\circ\) angle sits between the \(6\) cm and \(10\) cm sides in both triangles.

\(PR\)\(=\)\(LN = 6\text{ cm}\)
\(\angle PRQ\)\(=\)\(\angle LNM = 72^\circ\)
\(RQ\)\(=\)\(NM = 10\text{ cm}\)

Two sides and the included angle: SAS. Match the vertices: \(R \leftrightarrow N\) (the angle), \(P \leftrightarrow L\) (end of the \(6\) cm side), \(Q \leftrightarrow M\).

\(\triangle PQR\)\(\equiv\)\(\boldsymbol{\triangle LMN}\ \text{(SAS)}\)
△PQR≡△LMN
Example 2 β€” Using matching parts
\(\triangle KLM \equiv \triangle RST\). \(KL = (x + 3y)\) cm, \(LM = (3x - y)\) cm, \(RS = 17\) cm, \(ST = 11\) cm, \(\angle M = 38^\circ\) and \(\angle S = 74^\circ\). Find:
(i) \(x\) and \(y\)
(ii) \(\angle L\)
(iii) \(\angle R\)
Solution
Congruent triangles KLM and RSTTriangle KLM has side KL equal to x plus 3y centimetres, side LM equal to 3x minus y centimetres and angle M of 38 degrees. Triangle RST has side RS of 17 cm, side ST of 11 cm and angle S of 74 degrees. (x + 3y) cm(3x βˆ’ y) cm 38Β° ? 17 cm11 cm 74Β° K L M R S T

Read the statement in order: \(K \leftrightarrow R\), \(L \leftrightarrow S\), \(M \leftrightarrow T\). So \(KL\) matches \(RS\) and \(LM\) matches \(ST\).

(i) Two pairs of matching sides give two equations. Solve them simultaneously.

\(x + 3y\)\(=\)\(17\)
\(3x - y\)\(=\)\(11\)

From the second equation, \(y = 3x - 11\). Substitute into the first.

\(x + 3(3x - 11)\)\(=\)\(17\)
\(10x - 33\)\(=\)\(17\)
\(x\)\(=\)\(\mathbf{5}\)
\(y\)\(=\)\(3 \times 5 - 11 = \mathbf{4}\)

Check: \(KL = 5 + 12 = 17\) and \(LM = 15 - 4 = 11\).

(ii) \(\angle L\) matches \(\angle S\).

\(\angle L\)\(=\)\(\mathbf{74^\circ}\)

(iii) \(\angle R\) matches \(\angle K\). Use the angle sum of \(\triangle KLM\).

\(\angle K\)\(=\)\(180^\circ - 74^\circ - 38^\circ = 68^\circ\)
\(\angle R\)\(=\)\(\mathbf{68^\circ}\)
x+3y=17,3x−y=11,x=5,y=4
Example 3 β€” Proving congruence
\(X\) is the midpoint of \(PQ\). \(PA \parallel QB\), and \(AB\) passes through \(X\). Prove that \(\triangle PXA \equiv \triangle QXB\), and hence that \(X\) is also the midpoint of \(AB\).
Solution
Two triangles meeting at the midpoint XPQ and AB cross at X, the midpoint of PQ. PA is parallel to QB. Equal alternate angles are marked at P and Q, and vertically opposite angles at X. P Q X A B

Write one fact per line, each with its reason.

\(\angle APX\)\(=\)\(\angle BQX\ \text{(alternate, } PA \parallel QB)\)
\(\angle PXA\)\(=\)\(\angle QXB\ \text{(vertically opposite)}\)
\(PX\)\(=\)\(QX\ \text{(}X\text{ is the midpoint)}\)

Two angles and a matching side: \(\therefore\ \triangle PXA \equiv \triangle QXB\) (AAS).

\(AX\)\(=\)\(BX\) (matching sides of congruent triangles)
AX=BX

So \(X\) is the midpoint of \(AB\). The side \(PX\) is opposite the angle at \(A\) in one triangle and \(QX\) is opposite the angle at \(B\) in the other, so the sides really do match.

Example 4 β€” RHS, then Pythagoras
A tent's cross-section is triangle \(TAB\) with \(TA = TB = 3.4\) m. The pole \(TM\) is \(3\) m tall and perpendicular to the floor \(AB\). Show that \(M\) is the midpoint of \(AB\), then find the width \(AB\).
Solution
Tent cross-section with a centre poleAn isosceles triangle TAB with TA and TB each 3.4 m. A pole TM, 3 m tall, is perpendicular to the floor AB at M. 3.4 m 3.4 m 3 m ? ? T A B M
\(\angle TMA\)\(=\)\(\angle TMB = 90^\circ\ \text{(given)}\)
\(TA\)\(=\)\(TB\ \text{(hypotenuses, given)}\)
\(TM\)\(\)\(\text{is common}\)

\(\therefore\ \triangle TMA \equiv \triangle TMB\) (RHS), so \(AM = BM\) (matching sides) and \(M\) is the midpoint.

\(AM^2\)\(=\)\(3.4^2 - 3^2\)
\(\)\(=\)\(11.56 - 9 = 2.56\)
\(AM\)\(=\)\(\sqrt{2.56} = 1.6\text{ m}\)
\(AB\)\(=\)\(2 \times 1.6 = \mathbf{3.2}\text{ m}\)
AM=3.42−32=1.6

Common pitfalls

The angle must be included. For SAS the equal angle has to sit between the two equal sides. Two sides and a different angle (SSA) is not a test.
AAA is not a test. Equal angles give the same shape, not the same size. The triangles are similar, not necessarily congruent.
Write the vertices in matching order. If \(\triangle ABC \equiv \triangle XZY\), then \(B\) matches \(Z\) and \(C\) matches \(Y\), so \(BC = ZY\) and \(\angle B = \angle Z\). Reading the letters in the wrong order gives the wrong pairs.
Choosing the missing fact. If you know one pair of sides and one pair of angles, the third fact must complete SAS (the other side next to the angle) or AAS (another angle). A side opposite the known angle gives only SSA, which is not a test.
Do not assume from the picture. Use only marks, given facts and reasons. Two lines that look equal or parallel are not equal or parallel unless you can say why.

Frequently asked questions

What are the 4 congruence tests for triangles?

SSS (three sides), SAS (two sides and the included angle), AAS (two angles and a matching side) and RHS (right angle, hypotenuse and one side).

Why is AAA not a congruence test?

Triangles with the same three angles have the same shape but can be different sizes, like a small and a large equilateral triangle. AAA proves the triangles are similar, not congruent.

What is the difference between SAS and SSA?

In SAS the equal angle is between the two equal sides, and it proves congruence. In SSA the angle is not between them, and two different triangles can be made, so it is not a test.

How do you write a congruence statement?

Write the two triangle names with the vertices in matching order, joined by \(\equiv\). If \(P\), \(Q\), \(R\) match \(L\), \(M\), \(N\), write \(\triangle PQR \equiv \triangle LMN\).

What does a common side mean in a congruence proof?

It is a side shared by both triangles, such as a diagonal of a kite. It is equal to itself, so it gives one pair of equal sides with the reason "common".