Resources For Teachers For Tutors For Students & Parents AI New Pricing
Year 10 Maths - 10 Statistics

Review of Statistical Graphs

20 practice questions 2 video lessons Theory + worked examples
Practice 20 questions
Practice questions

Every question with a fully worked solution.

Start practising
Watch 2 video(s)
  • Review of Statistical Graphs - Video - Drawing Stem and Leaf Diagrams Watch
  • Review of Statistical Graphs - Video - How to make a dot plot Watch
Create a free accountTrack your progress and save your work as you go.
Create free account

Theory

Graphs show where most of the data sits and which way the tail goes. This Year 10 maths page revises how to read histograms, dot plots and stem-and-leaf plots, describe a distribution as symmetrical, positively skewed or negatively skewed, unimodal or bimodal, read the shape from a box plot, and explain what skew does to the mean and median. It revises Year 7–9 work.

A histogram shows numerical data: the height of each column is the frequency and the columns touch, because the horizontal axis is a number line. A dot plot shows every score as a dot above a number line. A stem-and-leaf plot keeps every score: the key tells you how to read a stem and a leaf back into a number.

A distribution is symmetrical if its left and right halves are mirror images. The mean and median are then about equal (and, with one peak, so is the mode).

A distribution is skewed if the scores bunch up on one side and trail off in a long tail on the other. It is named after the side of the tail: tail to the right (towards high values) is positively skewed; tail to the left (towards low values) is negatively skewed.

The tail pulls the mean towards it, but hardly moves the median. So in positive skew the mean is usually greater than the median, and in negative skew it is usually less. For skewed data the median is often the better measure of centre.

The number of peaks matters too: one peak is unimodal, two is bimodal, more is multimodal. Two peaks often mean the data mixes two groups.

An outlier is a score far from the rest. It can create a tail on its own.

Negatively skewed, symmetrical and positively skewed distributionsThree smooth distributions. Left: most data on the right with a tail to the left, negatively skewed, mean below the median. Middle: symmetrical, mean about equal to the median. Right: most data on the left with a tail to the right, positively skewed, mean above the median. tail tail negatively skewed symmetrical positively skewed mean < median mean β‰ˆ median mean > median
A skew is named after the side its tail is on, not the side of the peak.
Unimodal and bimodal distributionsLeft: a distribution with one peak, called unimodal. Right: a distribution with two separate peaks, called bimodal. Three or more peaks is called multimodal. unimodal: one peak bimodal: two peaks three or more peaks: multimodal
Count the peaks (modes). A bimodal shape can still be symmetrical.
ShapeGraphBox plotMean vs median
Symmetricalmirror halvesmedian in the middle of the box, whiskers equalabout equal
Positive skewpeak on the left, tail to the rightright part of box and right whisker longermean \(>\) median
Negative skewpeak on the right, tail to the leftleft part of box and left whisker longermean \(<\) median

From a five-number summary, compare the two sides:

\[\text{median} - Q_1 \ \text{ vs } \ Q_3 - \text{median}\]
\[Q_1 - \min \ \text{ vs } \ \max - Q_3\]
median−Q1 vs Q3−median
Mean of a list. \(\text{mean} = \dfrac{\text{sum of scores}}{\text{number of scores}}\). The median is the middle score in order; with an even number of scores it is halfway between the two middle ones.
Frequency tables. Running totals tell you which score is in each position, for example the 10th and 11th scores of \(20\). A long run of small values followed by a few large ones is positive skew.
A box plot hides the peaks. A perfectly balanced box plot can come from bimodal data. Use a histogram or dot plot to count peaks.
Reading a histogram. Add the column heights to get the number of scores. To count scores above a value, add the columns to its right. For the scores \(1\) to \(5\) with frequencies \(2, 5, 8, 4, 1\): there are \(20\) scores, the mode is \(3\), the range is \(5 - 1 = 4\), and the mean is \(\dfrac{1(2) + 2(5) + 3(8) + 4(4) + 5(1)}{20} = \dfrac{57}{20} = 2.85\).
Dot plots. Look for a cluster (where the dots bunch), gaps, and outliers sitting far from the rest. The data cluster around the tallest stack.
Stem-and-leaf plots. The leaves are in order, so count along to the middle. With \(n\) scores the median is in position \(\dfrac{n + 1}{2}\): the \(8\)th of \(15\) scores, or halfway between the \(8\)th and \(9\)th of \(16\).

How to describe the shape of a data set

  1. Draw or read a graph: histogram, dot plot, or a stem-and-leaf plot turned on its side.
  2. Find where most scores are (the peak or peaks).
  3. Find the tail. Tail right: positively skewed. Tail left: negatively skewed. No tail, mirror halves: symmetrical.
  4. Count the peaks: unimodal, bimodal or multimodal.
  5. Link to the centre: the mean moves towards the tail; the median stays with the bulk.

From a box plot or five-number summary

  1. Measure each part: left whisker, left part of the box, right part of the box, right whisker.
  2. Compare: the longer side is the side of the tail.
Example 1 β€” Reading a histogram
The histogram shows the battery life of \(25\) phones.
(i) Describe the shape.
(ii) Is the mean likely to be more or less than the median?
Solution
Histogram of battery lifeHistogram of the battery life of 25 phones, in classes of 10 hours from 0 to 60. Frequencies: 1, 2, 3, 5, 8, 6. The tallest column is 40 to 50 hours, with a tail of short columns to the left. 02468Frequency 0102030405060Battery life (hours)

(i) The columns are tallest at \(40\)–\(50\) hours and get shorter towards the low values. The tail is on the left, so the distribution is negatively skewed. It has one peak, so it is also unimodal.

(ii) The few short battery lives in the tail pull the mean down. The mean is likely to be less than the median.

\(\text{tail on left}\)\(\Rightarrow\)\(\text{negative skew}\)
\(\)\(\Rightarrow\)\(\text{mean} < \text{median}\)
negative skew⇒mean<median
Example 2 β€” Mean, median and an extreme score
The hours worked last week by \(10\) casual staff were: \(8, 9, 10, 10, 11, 12, 12, 12, 13, 33\).
(i) Find the mean, median and mode.
(ii) Describe the shape.
(iii) Which measure best describes a typical worker?
Solution

(i) The scores are already in order.

\(\text{mean}\)\(=\)\(\dfrac{130}{10} = \mathbf{13}\)
\(\text{median}\)\(=\)\(\dfrac{11 + 12}{2} = \mathbf{11.5}\)
\(\text{mode}\)\(=\)\(\mathbf{12}\)
mean=13010=13

(ii) The \(33\) sits far above the rest and makes a tail to the right: positively skewed. The mean is pulled above the median.

(iii) Only one worker did more than \(13\) hours, so the mean overstates a typical week. The median (\(11.5\) h) is the better summary. Without the \(33\), the mean would drop to about \(10.8\) h, while the median would only move to \(11\) h.

Example 3 β€” Shape from a box plot
The five-number summary of a set of test marks is: minimum \(12\), \(Q_1 = 30\), median \(41\), \(Q_3 = 45\), maximum \(48\). Describe the shape.
Solution
Box plot of test marksBox plot with minimum 12, lower quartile 30, median 41, upper quartile 45 and maximum 48. The left whisker (18) and left part of the box (11) are much longer than the right part of the box (4) and right whisker (3). 101520253035404550Test mark 18 11 4 3

Compare the lengths on each side of the median.

\(\text{median} - Q_1\)\(=\)\(41 - 30 = 11\)
\(Q_3 - \text{median}\)\(=\)\(45 - 41 = 4\)
\(Q_1 - \min\)\(=\)\(30 - 12 = 18\)
\(\max - Q_3\)\(=\)\(48 - 45 = 3\)
median−Q1=11>Q3−median=4

The left side is much longer: the marks are bunched at the top and spread out towards the low marks. The distribution is negatively skewed.

Example 4 β€” Shape from a stem-and-leaf plot
The stem-and-leaf plot shows how long \(21\) customers waited at a cafΓ©, in minutes. Describe the shape of the distribution.
Solution
StemLeaf
12  5  7
20  3  4  6  8  9
31  5
42  4
50  1  3  6  7  8
62  4

Key: \(2 \,|\, 3 = 23\) minutes

Turn the plot on its side: each row of leaves is like a column of a histogram.

\(\text{row lengths}\)\(:\)\(3,\ 6,\ 2,\ 2,\ 6,\ 2\)
row lengths:3,6,2,2,6,2

There are two separate peaks, in the \(20\)s and the \(50\)s, with a dip between them. The distribution is bimodal. It might come from two groups, such as dine-in and takeaway customers.

Common pitfalls

Follow the tail, not the peak. A peak on the left with a long tail to the right is positively skewed. Many students name the side of the peak instead.
Mean and median under skew. The mean is pulled towards the tail. In positive skew it is usually larger than the median; in negative skew, smaller.
Symmetrical does not mean one peak. Two equal peaks placed evenly about the centre give a symmetrical, bimodal distribution.
Order the data first. The median and quartiles come from the scores in order. An unsorted list gives the wrong middle.

Frequently asked questions

What is the difference between positive and negative skew?

Positive skew has the tail on the right, towards the high values, with most scores bunched on the left. Negative skew has the tail on the left, towards the low values, with most scores bunched on the right.

Is the mean bigger than the median in positive skew?

Usually, yes. The few high scores in the right-hand tail pull the mean up, while the median stays with the middle of the data.

How do you tell the shape from a box plot?

Compare the two sides of the median. If the right part of the box and the right whisker are longer, the data is positively skewed. If the left side is longer, it is negatively skewed. If they match, it is symmetrical.

What does bimodal mean in statistics?

A bimodal distribution has two separate peaks. It often happens when the data comes from two different groups mixed together.

Which is better for skewed data, the mean or the median?

The median, because an extreme score or a long tail pulls the mean away from where most of the data lies, but barely moves the median.