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Year 9 Maths Core Investigating Data

Comparing Data Sets

20 practice questions 1 video lesson Theory + worked examples

Comparing data sets means looking at their centres and their spreads side by side, then deciding what the difference means in context. This NSW Year 9 Core maths subtopic is Stage 5 Core content under NESA outcome MA5‑DAT‑C‑01.

You will compare means, medians, modes and ranges of two sets, read a smaller range as greater consistency, as for two batters with the same average, and spot sets with the same centre but very different spreads. You will find means from totals and from frequency tables, compare cities' temperatures and tests with dot plots, stem-and-leaf plots and histograms, use the mean and median to compare shapes, and choose between two bus companies or two bottling machines when the centre and spread point different ways. It is part of Year 9 Core Investigating Data.

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Practice questions

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Theory

Comparing data sets means comparing three things: centre, spread and shape. This Year 9 maths page shows how to compare means or medians, use the range to judge which set is more consistent, compare shapes using each set's mean and median, and make a decision in context when the centre and the spread point different ways.

To compare two data sets, look at three things in order.

Centre says which set is higher overall. Compare the two means, or the two medians. Never compare one set's mean with the other set's median.

Spread says which set is more consistent. Compare the ranges. A smaller range means the scores are closer together and more predictable. The interquartile range (IQR) also measures spread, and one extreme score disturbs it far less than the range. The standard deviation, found on a calculator, is another measure of spread.

Shape says which way each set leans. Compare each set's own mean with its own median.

Two sets can have the same mean and be nothing alike. That is when the spread decides the question. Parallel displays, such as two dot plots drawn on the same scale, let you compare all three by eye.

Two dot plots with the same centre and different spreadsTwo dot plots on the same scale from 3 to 15. Set P is bunched from 7 to 11. Set Q is spread from 3 to 15. Both are centred on 9. Set P Set Q 3 4 5 6 7 8 9 10 11 12 13 14 15
Same centre, different spread. Both sets have a mean of \(9\), but P has a range of \(4\) and Q a range of \(12\). P is far more consistent.
Two dot plots with the same spread and different centresTwo dot plots on the same scale. Set S runs from 4 to 8, centred on 6. Set T has the same shape and runs from 9 to 13, centred on 11. Set S Set T 3 4 5 6 7 8 9 10 11 12 13 14
Same spread, different centre. Both ranges are \(4\), but T sits \(5\) higher than S. Drawing both on one scale shows this at a glance.
CompareUsingIt tells you
centrethe two means, or the two medianswhich set is higher overall
spreadthe two ranges (or IQRs)which set is more consistent
shapeeach set's mean against its own medianwhich way each set leans
\[\text{mean} = \dfrac{\text{total}}{\text{number of scores}} \qquad \text{range} = \text{highest} - \text{lowest}\]
mean=totalnumber of scores
Different-sized groups. Totals cannot be compared when the groups have different sizes. Divide each total by its own count to get the means, then compare. From a frequency table, find each mean as \(\dfrac{\sum fx}{\sum f}\) using its own row.
Deciding in context. When the centre favours one option and the spread favours the other, say which matters more for the purpose. A task that must never fall below a level wants consistency; a task that wants the most overall wants the higher centre.

How to compare two data sets

  1. Find the same summary statistics for both sets: mean or median, and range.
  2. Compare the centres. Say which set is higher and by how much.
  3. Compare the spreads. Say which set is more consistent and quote both ranges.
  4. Compare the shapes if you can, using each set's mean and median.
  5. Conclude in context, with both parts: “Set \(B\) scores higher on average, but set \(A\) is more consistent.”
Example 1 — Comparing centres
Set \(A\) is \(5, 8, 11, 12\). Set \(B\) is \(7, 9, 13, 15\). By how much is \(B\)'s mean higher?
Solution

Find each mean, then subtract.

\(\text{mean of } A\)\(=\)\(\dfrac{5+8+11+12}{4}\)
\(\)\(=\)\(\dfrac{36}{4} = 9\)
\(\text{mean of } B\)\(=\)\(\dfrac{7+9+13+15}{4}\)
\(\)\(=\)\(\dfrac{44}{4} = 11\)
\(\text{difference}\)\(=\)\(11 - 9 = \mathbf{2}\)
11−9=2

\(B\)'s mean is \(2\) higher.

Example 2 — Same mean, different spread
Archer \(X\) scores \(3, 6, 8, 9, 9\) with five arrows. Archer \(Y\) scores \(6, 7, 7, 8, 7\). A coach needs every arrow to score at least \(6\). Which archer should the coach pick?
Solution
Dot plots of two archers' scoresArcher X scored 3, 6, 8, 9 and 9. Archer Y scored 6, 7, 7, 7 and 8. Both are drawn on the same scale from 2 to 10. Archer X Archer Y 2 3 4 5 6 7 8 9 10

Compare the centres first, then the spreads.

\(\text{mean } X\)\(=\)\(\dfrac{35}{5} = 7\)
\(\text{mean } Y\)\(=\)\(\dfrac{35}{5} = 7\)
\(\text{range } X\)\(=\)\(9 - 3 = 6\)
\(\text{range } Y\)\(=\)\(8 - 6 = 2\)
range X=6,range Y=2

The means are equal, so the spread decides. \(Y\) is far more consistent, and \(Y\)'s lowest score is \(6\), while \(X\) once scored \(3\). The coach should pick archer \(Y\).

Example 3 — Centre and spread together
Set \(C\) is \(21\), \(24\), \(26\), \(29\), \(33\). Set \(D\) is \(19\), \(25\), \(31\), \(34\), \(40\). Compare them.
Solution

Compare like with like: median with median, range with range.

\(\text{median } C\)\(=\)\(26\)
\(\text{median } D\)\(=\)\(31\)
\(\text{range } C\)\(=\)\(33 - 21 = 12\)
\(\text{range } D\)\(=\)\(40 - 19 = 21\)
median D−median C=5

\(D\)'s median is \(5\) higher, so \(D\) scores higher. But \(D\)'s range is \(9\) larger, so \(C\) is the more consistent set. A full answer gives both parts.

Example 4 — Comparing shapes
Set \(E\) has a mean of \(30\) and a median of \(30\). Set \(F\) has a mean of \(41\) and a median of \(34\). Compare their shapes.
Solution

Compare each set's own mean with its own median.

\(E\)\(:\)\(30 = 30\)
\(F\)\(:\)\(41 > 34\)
41>34

\(E\)'s mean equals its median, so \(E\) is symmetrical. \(F\)'s mean is above its median, so a tail of high values has dragged it up: \(F\) is positively skewed.

The medians, \(30\) and \(34\), are the fairer comparison of centre here, because \(F\)'s mean is pulled by its tail.

Common pitfalls

Compare like with like. Compare one set's median with the other's median, not with its mean.
A smaller range is more consistent. Range measures spread, so a low value is a good thing when consistency matters.
Equal means do not mean equal data. Always check the spread before saying two sets are alike.
Better at what? “Set \(A\) is better” is not a comparison until it says better at what, and quotes the numbers.

Frequently asked questions

How do you compare two sets of data?

Compare their centres using the means or medians, their spreads using the ranges, and their shapes using each set's mean and median. Then write a conclusion that gives both the centre and the spread, in context.

What does a smaller range mean?

The scores are closer together, so the data are more consistent and more predictable. It does not mean the scores are lower.

Can two data sets have the same mean but be different?

Yes. \(7, 8, 8, 9, 9, 9, 10, 10, 11\) and \(3, 5, 7, 8, 9, 10, 11, 13, 15\) both have a mean of \(9\), but the second set has three times the range.

Should I compare the mean or the median?

Either, as long as you compare the same measure for both sets. If one set is skewed or has an outlier, the medians give the fairer comparison.

How do you compare groups of different sizes?

Compare their means, not their totals. A bigger group can have a bigger total and still have a lower mean.