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Year 9 Maths Core Congruence and Similar Figures

Properties of Similar Figures

20 practice questions 1 video lesson Theory + worked examples

The scale factor between similar figures is the number every length is multiplied by, found as a new length divided by the matching old length. This NSW Year 9 Core maths subtopic uses it to find unknown sides, and is Stage 5 Core content under NESA outcome MA5‑GEO‑C‑01.

You will find scale factors for enlargements and reductions, match sides correctly even when one figure has been turned, and find unknown sides, as when a \(5\) cm by \(7\) cm rectangle is enlarged so the \(5\) cm side becomes \(15\) cm. You will apply scale factors to circles, find sides in similar triangles formed by a parallel line or a bow-tie shape, resize a photograph, find a flagpole's height from its shadow, and find the perimeter of a scaled triangle. It is part of Year 9 Core Congruence and Similar Figures.

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Theory

The scale factor is the number every length of a figure is multiplied by to give a similar figure. This Year 9 maths page shows how to find the scale factor from a pair of matching sides, use it to find an unknown side, and spot similar triangles made by a parallel line, two triangles meeting point to point, and shadows.

When a figure is enlarged or reduced, every length is multiplied by the same number. That number is the scale factor, \(k\).

Find \(k\) from a pair of matching sides whose lengths you both know. Divide the length on the new figure by its partner on the old figure: new over old.

If \(k > 1\) the figure is an enlargement. If \(k < 1\) it is a reduction. If \(k = 1\) the figures are congruent.

Angles do not change. Only lengths are multiplied by \(k\), and that includes the perimeter, the radius, the diameter and the circumference.

Similar triangles often hide inside a diagram. A line parallel to one side of a triangle cuts off a smaller similar triangle. Two triangles meeting point to point, with parallel outer sides, are similar too.

An enlargement and a reductionA small house-shaped pentagon in navy is the original. To its right a red copy twice as big is labelled k equals 2, an enlargement. To its left a red copy half as big is labelled k equals 0.5, a reduction. original k = 2 k = 0.5 enlargement reduction
Every length is multiplied by the scale factor \(k\). \(k > 1\) enlarges, \(k < 1\) reduces, and \(k = 1\) gives a congruent copy.
Two circles with radii 2 cm and 5 cmA small navy circle of radius 2 cm and a large red circle of radius 5 cm. Any two circles are similar; here the scale factor is 2.5. radius 2 cm radius 5 cm
Any two circles are similar. Here \(k = \dfrac{5}{2} = 2.5\), and the diameter and circumference are also multiplied by \(2.5\).
\[k = \dfrac{\text{new length}}{\text{old length}} \qquad \text{new} = \text{old} \times k \qquad \text{old} = \dfrac{\text{new}}{k}\]
k=new lengthold length
What you wantWhat to do
the scale factordivide a new length by its old partner
a length on the new figuremultiply the old length by \(k\)
a length on the originaldivide the new length by \(k\)
Direction matters. “The scale factor from the larger figure to the smaller” means smaller over larger, which is less than \(1\). Check \(k\) against the picture before using it.
Shadows. At one moment the Sun's rays hit everything at the same angle. So any object and its shadow form a triangle similar to any other object and its shadow. Match height with height and shadow with shadow.

How to find an unknown side in similar figures

  1. Match the figures: use the similarity statement, or longest with longest and shortest with shortest.
  2. Choose a pair of matching sides with both lengths known.
  3. Divide to get \(k\), new over old. Check it is bigger than \(1\) for an enlargement and smaller for a reduction.
  4. Multiply the old side by \(k\) to get the new side, or divide a new side by \(k\) to get the old side.
  5. Check that the new answer gives the same ratio.
Example 1 — Scale factor and an unknown side
Two rectangles are similar. The smaller is \(12\) cm by \(8\) cm. On the larger, the side matching the \(8\) cm side is \(20\) cm. Find the other side of the larger rectangle.
Solution
Rectangles 12 by 8 and the similar 20 by xA navy rectangle 12 cm long and 8 cm high, and a larger red rectangle whose height is 20 cm and whose length is unknown. 12 cm 8 cm ? 20 cm

Use the pair with both lengths known to find \(k\), new over old. Then multiply the other old side by \(k\).

\(k\)\(=\)\(\dfrac{20}{8} = 2.5\)
\(\text{other side}\)\(=\)\(12 \times 2.5\)
\(\)\(=\)\(\mathbf{30} \text{ cm}\)
k=208=2.5,12×2.5=30

Check: \(\dfrac{30}{12} = 2.5\), the same factor.

Example 2 — A reduction
A rectangle \(30\) cm by \(20\) cm is reduced to a similar rectangle whose longer side is \(12\) cm. Find its shorter side.
Solution
Rectangle 30 by 20 reduced to 12 by xA navy rectangle 30 cm by 20 cm and a smaller red rectangle 12 cm long with an unknown height. 30 cm 20 cm 12 cm ?

Match longer side with longer side.

\(k\)\(=\)\(\dfrac{12}{30} = 0.4\)
\(\text{shorter side}\)\(=\)\(20 \times 0.4\)
\(\)\(=\)\(\mathbf{8} \text{ cm}\)
k=0.4,20×0.4=8

The scale factor is less than \(1\), which is what a reduction should give.

Example 3 — A line parallel to one side
In \(\triangle ABC\), \(DE \parallel BC\). \(AD = 4\), \(DB = 6\) and \(DE = 3\). Find \(BC\).
Solution
Triangle ABC cut by DE parallel to BCTriangle ABC with D on AB and E on AC, and DE parallel to BC. AD is 4, DB is 6, DE is 3 and BC is unknown. A B C D E 4 6 3 ?

\(\angle A\) is shared, and \(\angle ADE = \angle ABC\) (corresponding angles, \(DE \parallel BC\)). So \(\triangle ADE \sim \triangle ABC\). \(AD\) matches the whole side \(AB\), not just \(DB\).

\(AB\)\(=\)\(4 + 6 = 10\)
\(k\)\(=\)\(\dfrac{AB}{AD} = \dfrac{10}{4} = 2.5\)
\(BC\)\(=\)\(3 \times 2.5\)
\(\)\(=\)\(\mathbf{7.5}\)
BC=3×2.5=7.5
Example 4 — Triangles meeting point to point
\(\triangle ABC \sim \triangle EDC\), meeting at \(C\) with \(AB \parallel DE\). \(AC = 3\), \(BC = 4\), \(AB = 5\) and \(CE = 4.5\). Find \(CD\) and \(DE\).
Solution
Two triangles meeting at CTriangles ABC and EDC meet point to point at C, with AB parallel to DE. AC is 3, BC is 4, AB is 5 and CE is 4.5. CD is unknown. A B C E D 3 4 5 4.5 ?

Read the matching off the statement: \(A \leftrightarrow E\), \(B \leftrightarrow D\), \(C \leftrightarrow C\). So \(AC\) matches \(EC\), and \(BC\) matches \(DC\).

\(k\)\(=\)\(\dfrac{CE}{CA} = \dfrac{4.5}{3} = 1.5\)
\(CD\)\(=\)\(4 \times 1.5 = \mathbf{6}\)
\(DE\)\(=\)\(5 \times 1.5 = \mathbf{7.5}\)
CD=6,DE=7.5

Common pitfalls

New over old, not the other way round. Getting \(k\) upside down turns every enlargement into a reduction.
Use the whole side of the big triangle. When \(DE \parallel BC\), \(AD\) pairs with \(AB = AD + DB\), not with \(DB\).
Match before you divide. Longest with longest and shortest with shortest, whichever way the figures are turned.
Scale the radius, then double it. For a circle, multiply the radius by \(k\) first. A diameter is twice the new radius.

Frequently asked questions

How do you find the scale factor of similar figures?

Pick a pair of matching sides whose lengths you both know. Divide the length on the new figure by the length on the original. For a \(4\) cm side that becomes \(10\) cm, \(k = \dfrac{10}{4} = 2.5\).

How do you find a missing side in similar shapes?

Find the scale factor from a matching pair, then multiply the matching side of the original by it. To go back from the new figure to the original, divide by the scale factor instead.

What does a scale factor less than 1 mean?

The figure has been reduced: every length on the new figure is shorter than on the original.

How do you use shadows to find the height of a tree?

Measure a post and its shadow at the same time as the tree's shadow. The triangles are similar, so multiply the post's height by the ratio of the shadows. A \(1.5\) m post with a \(2\) m shadow and a tree with a \(14\) m shadow give \(k = 7\), so the tree is \(10.5\) m tall.

Does the perimeter change by the scale factor?

Yes. Every side is multiplied by the scale factor, so the perimeter is too.