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Year 9 Maths Advanced Investigating Data

The Shape of a Distribution

20 practice questions 1 video lesson Theory + worked examples

A distribution can be symmetrical, positively skewed with a tail to the right, or negatively skewed with a tail to the left. This NSW Year 9 Advanced maths subtopic describes shape and links it to the mean and median (NESA outcome MA5‑DAT‑C‑01).

You will describe the shape, clusters and outliers of dot plots and histograms, recognise bimodal data, and use the mean and median to predict the shape. You will see how one large score moves the mean but not the median, match histograms to their statistics, explain the shape of the heights of a mixed group, and choose a measure of centre for skewed incomes. It is part of Year 9 Advanced Investigating Data.

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Theory

The shape of a data set tells you more than any single number. Is it symmetrical, or does it have a tail on one side? One peak or two? This Year 9 Advanced maths page shows how to describe the shape from a graph, how the mean and median give it away, and which of them to trust.

A distribution is symmetrical when its two halves are mirror images about the centre.

It is positively skewed when most scores are at the low end and a tail runs to the right, towards the larger numbers. It is negatively skewed when most scores are high and the tail runs to the left. The name comes from the tail, not the peak.

The number of peaks is a separate description. Unimodal means one peak, bimodal two peaks, and uniform means every value occurs about equally often. Two peaks often mean the data mix two different groups.

An outlier is a score well apart from the rest. A cluster is where most of the scores bunch together.

The mean is pulled towards a tail or an outlier. The median is the middle score, so it hardly moves.

Three shapes of distributionThree sketches. Positively skewed: a peak on the left and a long tail to the right, with the mean to the right of the median. Negatively skewed: a peak on the right and a tail to the left, with the mean to the left of the median. Symmetrical: a central peak with the mean equal to the median. positively skewed mean median tail to the right negatively skewed mean median tail to the left symmetrical mean = median
A skew is named after its tail. The mean is pulled towards the tail; the median stays with the bulk of the data.
Unimodal, bimodal and uniformThree small histograms: unimodal with one central peak, bimodal with peaks at both ends, and uniform with all bars the same height. unimodal one peak bimodal two peaks uniform no peak
Modality counts the peaks. A full description gives the shape and the number of peaks.
CompareShapeBest measure of centre
mean \(>\) medianpositively skewed (tail right)median
mean \(=\) mediansymmetricalmean or median
mean \(<\) mediannegatively skewed (tail left)median
\[\text{mean} - \text{median} \begin{cases} > 0 & \text{positive skew} \\ = 0 & \text{symmetrical} \\ < 0 & \text{negative skew} \end{cases}\]
mean>median⇒positive skew

These are good guides for real data, not exact laws: a set with mean equal to median can still be lopsided. Always check the graph as well.

Above or below the mean? In a skewed set the mean is not the middle. With positive skew most scores are below the mean; with negative skew most scores are above it. The scores \(1, 7, 8, 8, 9\) have mean \(6.6\), so four of the five are above it.
Adding a score. New total \(=\) old mean \(\times\) old count \(+\) new score; divide by the new count. An extreme new score moves the mean a lot and the median very little, and it can turn a symmetrical set into a skewed one.
Unknown scores. Mean \(\times n\) gives the total; the range gives the largest or smallest score. Use these to find missing values, then judge the shape.

Describing a distribution

  1. Draw or read the graph. From raw data, count each value and stack the dots or draw the bars.
  2. Shape: symmetrical, or which side has the tail? Name the skew after the tail.
  3. Peaks: one, two or none (uniform). If there are two, ask what two groups are mixed.
  4. Outliers and clusters: point out any score far from the rest and where most scores bunch.
  5. Check with numbers: compare the mean and the median. They should agree with what the graph shows.

Choosing a measure of centre

  1. Symmetrical, no outliers: the mean uses every score and is fine.
  2. Skewed or with outliers: use the median, which is not dragged by the tail.
  3. Bimodal: neither describes the data well; split the groups and summarise each.
  4. Spot a misleading 'average', such as a mean salary raised by one large income.
Example 1 β€” Draw a dot plot and describe it
Fourteen students scored these marks out of \(10\) on a quiz:
\[9,\ 7,\ 10,\ 8,\ 3,\ 9,\ 10,\ 6,\ 8,\ 9,\ 7,\ 10,\ 9,\ 8\]
(i) Draw a dot plot. (ii) Describe the shape. (iii) Is there an outlier? (iv) Around what score do the data cluster?
Solution

(i) Count each score: \(3\) once, \(6\) once, \(7\) twice, \(8\) three times, \(9\) four times, \(10\) three times. Stack one dot per student.

Dot plot of 14 quiz scoresA dot plot from 2 to 10: one dot at 3, one at 6, two at 7, three at 8, four at 9 and three at 10. 2 3 4 5 6 7 8 9 10 quiz score (out of 10)

(ii) Most scores are high, with a tail running left to the low scores: the shape is negatively skewed.

(iii) Yes: \(\mathbf{3}\) sits apart, with no scores at \(4\) or \(5\).

(iv) The tallest column is at \(9\): the data cluster around \(\mathbf{8}\) to \(\mathbf{10}\).

tail to the left⇒negatively skewed
Example 2 β€” Shape from the mean and the median
The histogram shows the number of people in each of \(34\) cars passing a checkpoint.
People in each carA histogram of the number of people in 34 cars: 1 person 14 cars, 2 people 9, 3 people 5, 4 people 3, 5 people 2, 6 people 1. 0 2 4 6 8 10 12 14 1 2 3 4 5 6 people in the car Cars
(i) Find the mean, correct to \(2\) decimal places, and the median. (ii) Use them to describe the shape, and check it against the graph. (iii) Which measure better describes a typical car?
Solution

(i) Multiply each value by its frequency.

\(\sum fx\)\(=\)\(14 + 18 + 15 + 12 + 10 + 6 = 75\)
\(\bar{x}\)\(=\)\(\dfrac{75}{34} = 2.2058\ldots \approx \mathbf{2.21}\)

The median is halfway between the \(17\)th and \(18\)th. Running totals: \(14\), \(23\). Both are in the bar for \(2\).

\(\text{median}\)\(=\)\(\mathbf{2}\)

(ii) Mean \(>\) median, so the data are positively skewed. The graph agrees: the peak is at \(1\) and the tail runs right.

2.21>2⇒positively skewed

(iii) The median. The few full cars drag the mean up; the median stays with the bulk of the cars.

Example 3 β€” The effect of an outlier
Eleven teenagers at a party are aged \(15, 15, 16, 16, 16, 17, 17, 17, 17, 18\) and \(18\). A parent aged \(52\) joins them.
(i) Find the mean and median age of all \(12\) people.
(ii) Find the mean and median of the teenagers only.
(iii) Describe the effect of the parent on the shape and on each measure.
Solution

(i) Teenagers' total: \(182\). Add \(52\).

\(\bar{x}\)\(=\)\(\dfrac{182 + 52}{12} = \dfrac{234}{12} = \mathbf{19.5}\)
\(\text{median}\)\(=\)\(\dfrac{6\text{th} + 7\text{th}}{2} = \dfrac{17 + 17}{2} = \mathbf{17}\)

(ii) Eleven ages: the median is the \(6\)th.

\(\bar{x}\)\(=\)\(\dfrac{182}{11} = 16.545\ldots \approx \mathbf{16.55}\)
\(\text{median}\)\(=\)\(\mathbf{17}\)
x¯=23412=19.5

(iii) The teenagers' ages are close to symmetrical. The single age of \(52\) is an outlier that makes a long tail to the right, so the data become positively skewed. It drags the mean up by about \(3\) years, to an age that nobody at the party is, while the median does not move.

Example 4 β€” Two peaks
The histogram shows the finishing times of the \(27\) people in a \(5\) km event that was open to runners and walkers.
Times in a 5 km eventA grouped histogram of finishing times in whole minutes: 20 to 24 minutes 3 people, 25 to 29 minutes 7, 30 to 34 minutes 4, 35 to 39 minutes 1, 40 to 44 minutes 2, 45 to 49 minutes 6, 50 to 54 minutes 4. 0 2 4 6 8 20 25 30 35 40 45 50 55 time (minutes); classes 20–24, 25–29, … People
(i) Describe the shape. (ii) Give a reason for it. (iii) Use class centres (\(22, 27, 32, \ldots\)) to estimate the mean, to \(1\) decimal place, and explain why it is a poor summary.
Solution

(i) There are two clear peaks, at \(25\)–\(29\) and \(45\)–\(49\) minutes, with a gap between them: the distribution is bimodal.

(ii) The data mix two groups. The runners make the faster peak and the walkers make the slower one.

(iii) Class centre \(\times\) frequency:

\(\sum fx\)\(=\)\(3(22) + 7(27) + 4(32) + 1(37)\)
\(\)\(\)\(+\ 2(42) + 6(47) + 4(52) = 994\)
\(\bar{x}\)\(\approx\)\(\dfrac{994}{27} = 36.81\ldots \approx \mathbf{36.8}~\text{min}\)
x¯≈99427≈36.8

The mean lands in the \(35\)–\(39\) class, the valley between the peaks, where only one person finished. It describes neither group: summarise the runners and the walkers separately.

Common pitfalls

Name the skew after the tail. A peak on the right with a tail to the left is negatively skewed, even though the bulk of the data is high.
Shape and peaks are separate. A distribution can be symmetrical and bimodal at the same time, with peaks at both ends.
Do not assume half the scores are below the mean. That is true of the median, not the mean. In a skewed set the split can be very uneven.
One outlier can change the shape. A single extreme score adds a tail and drags the mean towards it.
Read the scale, not just the picture. Bars at \(0\)–\(9\) and \(90\)–\(99\) are at opposite ends; check where the tail really points on the number line.

Frequently asked questions

What does positively skewed mean?

Most of the scores are at the low end and a tail of a few larger scores runs to the right. The mean is usually bigger than the median.

How can you tell the shape from the mean and median?

If the mean is greater than the median the data are usually positively skewed; if it is less, negatively skewed; if they are equal, roughly symmetrical. Check the graph too.

Which measure of centre should I use for skewed data?

The median. The tail pulls the mean away from where most of the data are, but the median stays in the middle of the ordered scores.

What does bimodal mean?

A bimodal distribution has two peaks. It often means two different groups have been measured together, such as runners and walkers.

What is an outlier?

An outlier is a score that lies well away from the rest of the data, with a gap before it. It pulls the mean towards it but barely changes the median.

What is a uniform distribution?

Every value occurs about equally often, so the graph is flat with no peak.