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Year 9 Maths Advanced Indices and Scientific Notation

Scientific Notation

20 practice questions 2 video lessons Theory + worked examples

Scientific notation writes very large and very small numbers as a number from \(1\) up to \(10\) times a power of \(10\), such as \(4.5 \times 10^{-8}\). This NSW Year 9 Advanced maths subtopic uses it for measurements of any size (NESA outcome MA5‑MAG‑C‑01).

You will convert between decimals and scientific notation, read a calculator display such as 2.7E-4, order measurements, and multiply, divide and square numbers in scientific notation using the index laws. You will estimate a product, compare a raindrop with a grain of sand, find how long sunlight takes to reach Earth, and work out how many photos fit on a hard drive. It is part of Year 9 Advanced Indices and Scientific Notation.

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Theory

Scientific notation writes a number as \(a \times 10^n\), with \(1 \le a \lt 10\) and \(n\) an integer. This Year 9 Advanced maths page covers converting both ways, ordering, calculator displays, calculating with the index laws and real problems with very large and very small measurements.

A number is in scientific notation (also called standard form) when it is written as \(a \times 10^n\), where \(a\) is at least \(1\) and less than \(10\), and \(n\) is an integer. So there is exactly one non-zero digit in front of the decimal point.

The index says how many places the decimal point moves. A positive index is for numbers \(10\) or more; a negative index is for numbers less than \(1\); \(10^0 = 1\) is for numbers from \(1\) to \(10\).

Scientific notation makes very large and very small measurements readable: the distance to the Moon is about \(3.84 \times 10^8\) m and a dust grain about \(5 \times 10^{-5}\) m.

To compare two numbers in scientific notation, compare the powers of 10 first. Only when the indices are equal do you compare the numbers in front.

A calculator shows scientific notation with an E: 5.2E-7 means \(5.2 \times 10^{-7}\).

Writing 4.6 times 10 to the 5 as an ordinary numberThe digits 4 and 6 followed by four zeros. The decimal point starts after the 4 and hops five places to the right, so 4.6 times 10 to the 5 equals 460 000. 4.6 Γ— 105 : point moves 5 places right 4 6 0 0 0 0 = 460 000 grey zeros fill the empty places
A positive index moves the decimal point right: the number is 10 or more.
Writing 0.00038 in scientific notationIn 0.00038 the decimal point starts after the first zero and hops four places right to sit after the 3, giving 3.8. Because the number is less than 1, the index is negative: 3.8 times 10 to the minus 4. 0.000 38 β†’ 3.8 Γ— 10βˆ’4 0 0 0 0 3 8 point moves 4 places right β†’ index βˆ’4 small number (less than 1) β†’ negative index
For a number less than \(1\), the point moves right to sit after the first non-zero digit, and the index is negative.
\[a \times 10^{n}, \quad 1 \le a \lt 10, \quad n \text{ an integer}\]
a×10n,1≤a<10
Ordinary numberScientific notationPoint moves
\(52\,900\)\(5.29 \times 10^{4}\)\(4\) left
\(6.1\)\(6.1 \times 10^{0}\)none
\(0.61\)\(6.1 \times 10^{-1}\)\(1\) right
\(0.000\,009\,3\)\(9.3 \times 10^{-6}\)\(6\) right
Calculating. \((a \times 10^m) \times (b \times 10^n)\) \(= (a \times b) \times 10^{m+n}\) and \(\dfrac{a \times 10^m}{b \times 10^n}\) \(= \dfrac{a}{b} \times 10^{m-n}\). Powers: \((a \times 10^m)^k = a^k \times 10^{mk}\). Then re-write the front number between \(1\) and \(10\).
Re-normalising. \(56 \times 10^{3} = 5.6 \times 10^{4}\) (front number down, index up). \(0.56 \times 10^{3} = 5.6 \times 10^{2}\) (front number up, index down).

Converting

  1. To scientific notation: place the point after the first non-zero digit. Count how many places it moved. Large number: positive index. Number less than \(1\): negative index.
  2. To an ordinary number: move the point right for a positive index and left for a negative one, filling gaps with zeros.
  3. Is it in scientific notation? Check that the front number is from \(1\) up to, but not including, \(10\). \(23.7 \times 10^{3}\) and \(0.4 \times 10^{2}\) are not.

Calculating and applying

  1. Multiply or divide: work on the front numbers and the powers of \(10\) separately, then re-normalise (Example 2).
  2. Estimate: round each front number to one significant figure first, then calculate.
  3. Units first: change to the same unit before dividing (Example 3). Speed, distance and time: \(t = \dfrac{d}{s}\).
  4. How many times larger: divide the larger by the smaller. A percentage is the fraction \(\times 100\).
  5. Whole objects: if the answer counts whole things that must fit, round down.
  6. Missing index: simplify, re-normalise, then match indices (Example 4).
Example 1 β€” Converting both ways

(i) Write \(3.016 \times 10^{6}\) as an ordinary number.
(ii) Write \(0.000\,704\) in scientific notation.
Solution

(i) The index is \(6\), so move the point \(6\) places right, filling with zeros.

\(3.016 \times 10^6\)\(=\)\(\mathbf{3\,016\,000}\)

The zero between the \(3\) and the \(1\) is part of the number and stays.

(ii) Put the point after the first non-zero digit, \(7\), and count the moves: \(4\) places right.

\(0.000\,704\)\(=\)\(\mathbf{7.04 \times 10^{-4}}\)
0.000704=7.04×10−4

Check by undoing it: \(7.04 \div 10\,000 = 0.000\,704\).

Example 2 β€” Calculating without a calculator
Give each answer in scientific notation:
(i) \((5 \times 10^{-3}) \times (8 \times 10^{7})\)
(ii) \(\dfrac{1.2 \times 10^{5}}{4 \times 10^{-3}}\).
Solution

Work on the numbers in front and the powers of \(10\) separately, then fix the front number so it is from \(1\) up to \(10\).

(i)

\(5 \times 8\)\(=\)\(40\)
\(10^{-3} \times 10^{7}\)\(=\)\(10^{4}\)
\(40 \times 10^{4}\)\(=\)\(4 \times 10^{1} \times 10^{4}\)
\(\)\(=\)\(\mathbf{4 \times 10^{5}}\)

(ii)

\(1.2 \div 4\)\(=\)\(0.3\)
\(10^{5} \div 10^{-3}\)\(=\)\(10^{5-(-3)} = 10^{8}\)
\(0.3 \times 10^{8}\)\(=\)\(3 \times 10^{-1} \times 10^{8}\)
\(\)\(=\)\(\mathbf{3 \times 10^{7}}\)
3×107

\(40\) and \(0.3\) are not allowed in front. Shifting the point one place changes the index by one.

Example 3 β€” How many fit?
A red blood cell is about \(7.5 \times 10^{-6}\) m wide. About how many cells would fit side by side across a \(3\) cm gap?
Solution

Use the same unit for both lengths: \(3\text{ cm}\) \(= 0.03\text{ m}\) \(= 3 \times 10^{-2}\) m. Then divide.

\(\dfrac{3 \times 10^{-2}}{7.5 \times 10^{-6}}\)\(=\)\(\dfrac{3}{7.5} \times 10^{-2-(-6)}\)
\(\)\(=\)\(0.4 \times 10^{4}\)
\(\)\(=\)\(4 \times 10^{3}\)
\(\)\(=\)\(\mathbf{4000}\)
3×10−27.5×10−6=4000

About \(4000\) cells. "How many fit" or "how many times larger" always means divide.

Example 4 β€” Finding a missing index
Find \(n\) if \(\dfrac{6.4 \times 10^{n}}{8 \times 10^{-3}}\) \(= 8 \times 10^{9}\).
Solution

Simplify the left side in terms of \(n\), then put it in scientific notation before matching.

\(6.4 \div 8\)\(=\)\(0.8\)
\(10^{n} \div 10^{-3}\)\(=\)\(10^{n+3}\)
\(0.8 \times 10^{n+3}\)\(=\)\(8 \times 10^{n+2}\)
\(n + 2\)\(=\)\(9\)
\(n\)\(=\)\(\mathbf{7}\)
n=7

Matching \(n + 3 = 9\) before fixing \(0.8\) gives the wrong answer \(n = 6\).

Common pitfalls

Only one digit in front of the point. \(34 \times 10^{5}\) is not scientific notation; it is \(3.4 \times 10^{6}\).
A negative index means a small number, not a negative one. \(2 \times 10^{-3} = 0.002\), which is positive.
Count the moves, not the zeros. \(0.000\,5 = 5 \times 10^{-4}\): four moves, though there are only three zeros after the point.
Compare the indices first. \(1.1 \times 10^{8}\) is larger than \(9.9 \times 10^{7}\), because \(10^8 > 10^7\).
Re-normalise after calculating. \((6 \times 10^{4}) \times (5 \times 10^{2})\) \(= 30 \times 10^{6}\) \(= 3 \times 10^{7}\).
Keep zeros inside the number. \(5.03 \times 10^{4} = 50\,300\), not \(53\,000\).

Frequently asked questions

What is scientific notation?

It writes a number as \(a \times 10^n\) with \(1 \le a \lt 10\). For example \(52\,900 = 5.29 \times 10^{4}\) and \(0.0061 = 6.1 \times 10^{-3}\).

How do you know if the index is positive or negative?

If the number is \(10\) or more, the index is positive. If it is less than \(1\), the index is negative. If it is from \(1\) up to \(10\), the index is \(0\).

How do you multiply numbers in scientific notation?

Multiply the front numbers, add the indices of the powers of \(10\), then adjust so the front number is between \(1\) and \(10\), changing the index to match.

What does E mean on a calculator?

E means \(\times 10\) to the power of the number after it: 5.2E-7 means \(5.2 \times 10^{-7}\).

How do you order numbers in scientific notation?

Compare the powers of \(10\) first: a bigger index means a bigger number for positive values. Only if the indices are equal, compare the front numbers.