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Year 12 Maths Standard 1 (2027) Investment

Simple Interest - the Formula

20 practice questions 0 video lessons Theory + worked examples

Learn the simple interest formula for NSW Year 12 Mathematics Standard 1 (NESA outcome MST-12-S1-02). Simple interest is worked out on the original amount only, so the same interest is earned every year. The formula \(I = Prn\) uses the principal \(P\), the interest rate \(r\) per period and the number of periods \(n\).

You will work out simple interest at different rates and over different lengths of time, find the total value of an investment or the amount to repay on a loan, and compare two investments — skills for everyday decisions about savings, term deposits and borrowing money.

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Theory

Simple interest is interest worked out on the original amount only, so the same interest is earned every year and \(I=Prn\) gives the total interest. This Year 12 Standard 1 (NSW) guide shows how to substitute into the simple interest formula, find the total value of an investment or the amount to repay on a loan, and compare two investments.

Simple interest is interest worked out on the original amount only. The amount invested or borrowed is called the principal, \(P\). Because the principal never changes, every year earns the same interest, \(P\times r\).

The interest after \(n\) years is \(I=Prn\), where \(r\) is the interest rate per time period written as a decimal (usually per year, per annum: \(4\%=0.04\)) and \(n\) is the number of time periods β€” it must match the rate (a rate per annum means \(n\) is in years).

The total value of an investment, or the total to repay on a loan, is the principal plus the interest: \(A=P+I\). Because the same amount is added every year, the total value grows in a straight line when it is graphed against time (it starts at \(P\)). Compound interest gives a curve instead.

Simple interest builds up evenly2000 dollars at 6 percent per annum earns the same 120 dollars every year: 120, 240, 360, 480 n I 120 240 360 480 1 $120 2 $240 3 $360 4 $480 +$120 each year
\(\$2000\) at \(6\%\) p.a.: every year adds the same \(\$120\), so after \(4\) years \(I=\$480\).
Total value of a simple interest investmentA = 2000 + 120n rises in a straight line from 2000 dollars to 2480 dollars after 4 years n A 1 2 3 4 2000 0 2200 2400 2600 $2480 start: P = $2000
The total value starts at the principal (\(\$2000\); note the vertical axis starts at \(2000\), shown by the break) and reaches \(2000+480=\$2480\) after \(4\) years.

The simple interest earned on a principal \(P\) at rate \(r\) per year for \(n\) years is:

\[I = Prn\]
I=Prn

The total value (or amount to repay) adds the interest to the principal:

\[A = P + I\]
A=P+I
Rate as a decimal: divide the percentage by \(100\) β€” \(5\%\) is \(r=0.05\), \(4.5\%\) is \(r=0.045\). \(n\) must match the rate: a rate per annum means \(n\) is the number of years.

How to solve a simple interest problem

  1. List \(P\), \(r\) (as a decimal) and \(n\) (in years).
  2. Substitute into \(I=Prn\) and multiply to find the interest.
  3. Add the principal if the question asks for the total value or the amount to repay: \(A=P+I\).
Example 1 β€” Find the interest
Calculate the simple interest earned on \(\$3500\) invested at \(4\%\) per annum for \(5\) years.
Solution

List \(P=3500\), \(r=0.04\), \(n=5\), then substitute into \(I=Prn\).

\(I\)\(=\)\(Prn\)
\(\)\(=\)\(3500\times0.04\times5\)
\(\)\(=\)\(140\times5\)
\(\)\(=\)\(700\)
I=3500Γ—0.04Γ—5=700

The simple interest is \(\$700\).

Example 2 β€” Find the total value
Liam puts \(\$7500\) into a term deposit earning \(3\%\) per annum simple interest for \(4\) years. What is the total value of his investment after \(4\) years?
Solution

Find the interest first, then add it to the principal.

\(I\)\(=\)\(7500\times0.03\times4\)
\(\)\(=\)\(225\times4 = 900\)
\(A\)\(=\)\(P+I\)
\(\)\(=\)\(7500+900\)
\(\)\(=\)\(8400\)
A=7500+900=8400

The total value is \(\$8400\).

Example 3 β€” Interest on a loan
An apprentice in Wollongong borrows \(\$4800\) for a motorbike. The loan charges simple interest at \(9\%\) per annum for \(3\) years. (i) How much interest is charged? (ii) What is the total amount to repay?
Solution

The interest is charged on the amount borrowed.

\(\text{(i) } I\)\(=\)\(4800\times0.09\times3\)
\(\)\(=\)\(432\times3 = 1296\)
\(\text{(ii) } A\)\(=\)\(P+I\)
\(\)\(=\)\(4800+1296 = 6096\)
A=4800+1296=6096

(i) \(\$1296\) interest. (ii) \(\$6096\) to repay.

Example 4 β€” Compare two investments
Option A is \(\$6000\) at \(4.5\%\) per annum simple interest for \(3\) years. Option B is \(\$5000\) at \(5\%\) per annum simple interest for \(4\) years. Which option earns more interest?
Solution

Use \(I=Prn\) for each option, then compare.

\(\text{A: } I\)\(=\)\(6000\times0.045\times3\)
\(\)\(=\)\(270\times3 = 810\)
\(\text{B: } I\)\(=\)\(5000\times0.05\times4\)
\(\)\(=\)\(250\times4 = 1000\)
1000>810

\(1000 > 810\), so Option B earns more interest (\(\$1000\) compared with \(\$810\)).

Common pitfalls

Change the rate to a decimal first. \(5\%\) is \(r=0.05\) β€” not \(5\) and not \(0.5\).
Interest is not the total value. \(I=Prn\) gives only the interest. If the question asks for the total value or the amount to repay, add the principal: \(A=P+I\).
Use the original principal every year. Simple interest is always worked out on the original principal, so every year earns the same amount β€” do not work out the interest on the growing balance.

Frequently asked questions

What is simple interest?

Simple interest is interest worked out on the original amount invested or borrowed (the principal) only. The principal never changes, so the same amount of interest is earned every year.

What is the simple interest formula?

The simple interest formula is I equals P times r times n, where P is the principal, r is the interest rate per year written as a decimal and n is the number of years.

How do you find the total value of a simple interest investment?

Work out the interest with I equals Prn, then add it to the principal: A equals P plus I. For example, $7500 at 3% per annum for 4 years earns $900 interest, so the total value is $8400.

How do you write the interest rate as a decimal?

Divide the percentage by 100. For example, 4% is 0.04, 9% is 0.09 and 4.5% is 0.045. Using 4 or 0.4 instead of 0.04 gives an answer that is far too big.

Is simple interest worked out on the new balance each year?

No. Simple interest is always worked out on the original principal, so the interest is the same every year. Interest worked out on the growing balance is compound interest.