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Year 12 Maths Advanced (2027) Random variables

z-scores & the Standard Normal Distribution

20 practice questions 0 video lessons Theory + worked examples

Learn \(z\)-scores and the standard normal distribution for NSW Year 12 Mathematics Advanced (NESA outcome MAV-12-07). A \(z\)-score counts how many standard deviations a value sits above or below the mean, putting results from different tests or datasets on one common scale.

You will learn to calculate \(z\)-scores, compare performances fairly, use standard normal tables to find probabilities, and work backwards to an unknown mean or standard deviation — a widely used way to rank results and judge how unusual a value is.

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Theory

A z-score measures how many standard deviations a value is from the mean. This Year 12 Mathematics Advanced topic (MAV-12-07) standardises with \(z=\dfrac{x-\mu}{\sigma}\).

\(z=\dfrac{x-\mu}{\sigma}\): \(z>0\) above the mean, \(z<0\) below, \(z=0\) at the mean. Reverse with \(x=\mu+z\sigma\). \(z\)-scores let you compare values from different distributions; the standard normal is \(Z\sim N(0,1)\).

The normal curveA bell curve; about 68% of values lie within one standard deviation of the mean. μ−σ μ μ+σ 68%
A \(z\)-score locates a value on the standard normal curve.
\[z=\dfrac{x-\mu}{\sigma},\qquad x=\mu+z\sigma\]
z equals x minus mu over sigma; x equals mu plus z sigma

Method

  1. Subtract the mean, then divide by \(\sigma\).
  2. Reverse with \(x=\mu+z\sigma\) for a raw score.
  3. Compare \(z\)-scores across different distributions.
Example 1 — Find a z-score
\(X\sim N(50,10^{2})\). Find the \(z\)-score for \(x=70\).
Solution
\(z\)\(=\)\(\dfrac{70-50}{10}=2\)
Example 2 — Negative z
For the same \(X\), find the \(z\)-score for \(x=35\).
Solution
\(z\)\(=\)\(\dfrac{35-50}{10}=-1.5\)
Example 3 — Raw score
\(X\sim N(60,4^{2})\). Find the raw score with \(z=2\).
Solution
\(x\)\(=\)\(60+2(4)=68\)
Example 4 — Compare
Ali scores \(z=1.2\); Bec \(z=0.8\). Who did better relative to their group?
Solution

Ali (\(1.2>0.8\)).

Common pitfalls

Subtract the mean, then divide by \(\sigma\).
A negative \(z\) means below the mean.
Reverse with \(x=\mu+z\sigma\).

Frequently asked questions

What is a z-score?

It is the number of standard deviations a value is from the mean, found as z equals x minus mu over sigma.

How do you find a raw score from a z-score?

Use x equals mu plus z times sigma.

Why are z-scores useful?

They let you compare values from different distributions on a common scale.

What is the standard normal distribution?

A normal distribution with mean 0 and standard deviation 1.