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Year 10 Maths Advanced Logarithms and Polynomials

Polynomials

20 practice questions 1 video lesson Theory + worked examples

A polynomial is an expression such as \(3x^4-x^2+7x-2\), with only whole-number powers of \(x\). Its degree is the highest power, the leading coefficient multiplies that power, and \(P(c)\) means its value when \(x=c\). In NSW Year 10 Advanced maths you name the parts of a polynomial, evaluate it, and add and subtract polynomials (NESA outcome MA5‑POL‑P‑01).

You will decide whether an expression is a polynomial, monic, cubic or quartic, and state degrees, leading coefficients and constant terms, even for factorised forms. You will evaluate \(P(c)\), add and subtract polynomials, find one coefficient of a product without expanding fully, and find unknown coefficients. Harder questions show why a sum of even powers plus a positive number is always positive, and model an open box. It is part of Year 10 Advanced Logarithms and Polynomials.

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Theory

A polynomial is a sum of terms \(ax^n\) where every power \(n\) is a whole number. This Year 10 Advanced maths page covers the degree, leading coefficient, constant term and monic polynomials, \(P(x)\) notation, operations on polynomials and finding unknown coefficients.

A polynomial in \(x\) has the form \(a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0\), where the powers are whole numbers \(0, 1, 2, \ldots\) and the coefficients \(a_n, \ldots, a_0\) are real numbers.

The degree is the highest power of \(x\). The term with that power is the leading term, and its coefficient is the leading coefficient. A polynomial with leading coefficient \(1\) is monic. The constant term \(a_0\) has no \(x\).

Degrees \(1\), \(2\), \(3\) and \(4\) are called linear, quadratic, cubic and quartic.

\(P(x)\) notation names a polynomial; \(P(c)\) is its value when \(x = c\).

This comes up if you are heading for Advanced or Extension maths in Years 11 and 12.

The parts of a polynomialThe polynomial 3x to the 4 minus 2x squared plus 7x minus 5. The leading term is 3x to the 4, so the degree is 4 and the leading coefficient is 3. The constant term is minus 5. 3x4 βˆ’ 2x2 + 7x βˆ’ 5 leading term degree 4 leading coefficient 3 constant term βˆ’5 Written in descending powers of x.
Find the term with the highest power first. It gives the degree and the leading coefficient.
Polynomial or notFive expressions. x to the 5 minus 4x plus 1 and root 2 x squared plus pi x are polynomials: whole-number powers, any real coefficients. x squared plus 3 over x, 4 root x minus 1 and 3 to the x plus x squared are not, because of a negative power, a fractional power and x in the index. x5 βˆ’ 4x + 1 βœ“ whole-number powers √2 x2 + Ο€x βœ“ any real coefficients x2 + 3/x βœ— 3/x = 3xβˆ’1 4√x βˆ’ 1 βœ— √x = x1/2 3x + x2 βœ— x in the index
Every power of \(x\) must be a whole number \(0, 1, 2, \ldots\). The coefficients can be any real numbers.
\[P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0, \qquad a_n \ne 0\]
P(x)=anxn+⋯+a1x+a0
To findUse
constant term\(P(0)\)
sum of the coefficients\(P(1)\)
leading term of a productmultiply the leading terms only
degree of \(P(x)\,Q(x)\)\(\deg P + \deg Q\)
degree of \([P(x)]^k\)\(k \times \deg P\)
degree of \(P(x) + Q(x)\)at most the larger degree (equal unless the leading terms cancel)
Coefficient of one power in a product. List the pairs of terms, one from each bracket, whose powers add to the power you want. Multiply each pair and add the results.
Always positive. Even powers are never negative: \(x^2 \ge 0\) and \(x^4 \ge 0\). So a sum like \(2x^4 + x^2 + 3\) is at least \(3\) for every \(x\), with its least value at \(x = 0\).

How to describe a polynomial

  1. Check every power of \(x\) is a whole number. Rewrite \(\dfrac1x\), \(\sqrt x\) and roots as powers first. A pronumeral in the index (\(2^x\)) is not allowed.
  2. Expand or simplify if needed, at least enough to find the highest power. Like terms may cancel: \(5x^3 - 5x^3 + x\) has degree \(1\).
  3. Read off the degree, leading coefficient and constant term. Monic means the leading coefficient is exactly \(1\).

Working with P(x)

  1. Substitute with brackets around negative numbers: \(-3(-2)^2 = -12\).
  2. Add or subtract by collecting like terms. Multiply out \(2Q(x)\) before subtracting, and change every sign of the polynomial being subtracted.
  3. Unknown coefficients: each given value \(P(c) = k\) gives one equation. Solve the equations simultaneously; \(P(0)\) often gives the constant straight away.
  4. Models: build the polynomial from the situation (for example volume \(= x(40 - 2x)(25 - 2x)\) for an open box), expand, then substitute.
Example 1 β€” Describing a polynomial
For each expression, decide whether it is a polynomial. If it is, state its degree, leading coefficient and constant term, and whether it is monic.
(i) \(4 - x^3 + 2x^5\)
(ii) \((1 - 2x)^2(x + 4)\)
(iii) \(x + \dfrac{3}{x^2}\)
Solution

(i) Rearrange in descending powers: \(2x^5 - x^3 + 4\).

\(\text{degree}\)\(=\)\(\mathbf{5}\)
\(\text{leading coefficient}\)\(=\)\(\mathbf{2}\)
\(\text{constant term}\)\(=\)\(\mathbf{4}\)
2x5−x3+4

The leading coefficient is \(2\), not \(1\), so it is not monic.

(ii) No need to expand fully. Multiply the highest-power terms for the leading term, and substitute \(x = 0\) for the constant.

\(\text{leading term}\)\(=\)\((-2x)^2 \times x = 4x^3\)
\(\text{constant}\)\(=\)\((1 - 0)^2(0 + 4) = 4\)
(−2x)2×x=4x3

Degree \(\mathbf{3}\) (a cubic), leading coefficient \(\mathbf{4}\), constant term \(\mathbf{4}\), not monic.

(iii) \(\dfrac{3}{x^2} = 3x^{-2}\). A negative power is not allowed, so this is not a polynomial.

Example 2 β€” Using P(x) notation
\(P(x) = x^3 - 4x^2 + 2x + 5\). Find:
(i) \(P(-1)\)
(ii) \(P(2) - P(-1)\)
(iii) the sum of the coefficients of \(P(x)\).
Solution

(i) Replace every \(x\) with \((-1)\), in brackets.

\(P(-1)\)\(=\)\((-1)^3 - 4(-1)^2 + 2(-1) + 5\)
\(\)\(=\)\(-1 - 4 - 2 + 5\)
\(\)\(=\)\(\mathbf{-2}\)
P(−1)=−2

(ii) Find \(P(2)\) first.

\(P(2)\)\(=\)\(8 - 16 + 4 + 5 = 1\)
\(P(2) - P(-1)\)\(=\)\(1 - (-2)\)
\(\)\(=\)\(\mathbf{3}\)
P(2)−P(−1)=3

(iii) Every power of \(1\) is \(1\), so \(P(1)\) adds up the coefficients.

\(P(1)\)\(=\)\(1 - 4 + 2 + 5\)
\(\)\(=\)\(\mathbf{4}\)
P(1)=4
Example 3 β€” Adding, subtracting and multiplying
\(A(x) = x^3 + 2x^2 - 5\) and \(B(x) = 3x^3 - x + 4\).
(i) Find \(3A(x) - B(x)\) and state its degree.
(ii) For the product \(A(x)\,B(x)\), state the degree and leading coefficient, and find the coefficient of \(x^2\) without expanding fully.
Solution

(i) Multiply every term of \(A(x)\) by \(3\), then subtract every term of \(B(x)\).

\(3A(x) - B(x)\)\(=\)\(3x^3 + 6x^2 - 15 - 3x^3 + x - 4\)
\(\)\(=\)\(\boldsymbol{6x^2 + x - 19}\)
3A(x)−B(x)=6x2+x−19

The \(x^3\) terms cancel, so the degree drops to \(\mathbf{2}\).

(ii) Leading term: \(x^3 \times 3x^3 = 3x^6\). Degree \(\mathbf{6}\), leading coefficient \(\mathbf{3}\).

For \(x^2\), list the pairs (one term from each bracket) whose powers add to \(2\).

\(2x^2 \times 4\)\(=\)\(8x^2\)
\(-5 \times (\text{an } x^2 \text{ term})\)\(\)\(\text{none: } B \text{ has no } x^2 \text{ term}\)
2x2×4=8x2

The \(x^3\) term of \(A\) can only give powers of \(3\) or more. The coefficient of \(x^2\) is \(\mathbf{8}\).

Example 4 β€” Finding unknown coefficients
\(P(x) = x^3 + ax^2 + bx + 4\). Given \(P(1) = 0\) and \(P(2) = 6\), find \(a\) and \(b\).
Solution

Each fact gives one equation in \(a\) and \(b\).

\(P(1) = 1 + a + b + 4\)\(=\)\(0\)
\(a + b\)\(=\)\(-5\)
\(P(2) = 8 + 4a + 2b + 4\)\(=\)\(6\)
\(2a + b\)\(=\)\(-3\)
a+b=−5,2a+b=−3

Subtract the first equation from the second.

\(a\)\(=\)\(\mathbf{2}\)
\(b\)\(=\)\(-5 - 2 = \mathbf{-7}\)
a=2,b=−7

Check: \(P(x) = x^3 + 2x^2 - 7x + 4\) gives \(P(1) = 1 + 2 - 7 + 4 = 0\) and \(P(2) = 8 + 8 - 14 + 4 = 6\).

Common pitfalls

Degree means the highest power after simplifying. \(x(x^3 + 1)\) is a quartic, not a cubic. Expand or multiply the leading terms before deciding.
Negative numbers need brackets. \(P(-2)\) for \(x^2\) is \((-2)^2 = 4\). Typing \(-2^2\) gives \(-4\).
Subtract every term. \(P(x) - Q(x)\) changes the sign of every term of \(Q(x)\), not just the first.
Coefficients can be anything real. \(\sqrt3 x^2 - \dfrac{1}{2} x\) is still a polynomial. Only the powers of \(x\) are restricted.

Frequently asked questions

What makes something a polynomial?

Every power of the variable must be a whole number: 0, 1, 2 and so on. Negative powers like 1 over x, fractional powers like the square root of x, and x in an index are not allowed. The coefficients can be any real numbers.

What is the degree of a polynomial?

The highest power of \(x\) after the polynomial has been simplified. For example \(2x^5 - x + 1\) has degree \(5\).

What is a monic polynomial?

A polynomial whose leading coefficient is \(1\), such as \(x^3 - 4x + 2\). \(2x^3 + 1\) is not monic.

What does P(2) mean?

It is the value of the polynomial \(P(x)\) when \(x = 2\). Replace every \(x\) with \(2\) and evaluate.

How do you find the degree of a product of polynomials?

Add the degrees. A cubic times a quadratic has degree 5, because the leading terms multiply to give x to the 5.