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Primary - Stage 3 (Year 5 & 6) Stage 3 (Year 5 & 6) Data

Interpret line graphs

20 practice questions 0 video lessons Theory + worked examples
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Theory

A line graph joins points to show how a measurement changes over time. Read up from a time to its value, follow the slope to see it rise or fall, and subtract two readings to find a change.

A line graph joins plotted points with straight lines to show how one measurement changes over time.

To read a value, find a time on the bottom axis, go straight up to the point, then across to the scale.

A line sloping up means the value is rising; sloping down means it is falling; a flat line means no change.

The steepest part is where the value changes fastest.

Line graph of temperature through a day A line graph with a vertical scale from 0 to 30 degrees marked in fives. Points at 6 am 10, 9 am 15, 12 pm 25, 3 pm 30 and 6 pm 20. The line rises to a peak at 3 pm then falls. 051015202530 Temperature (C) 6 am9 am12 pm3 pm6 pm
Reading up: \(10^\circ\) at 6 am rising to \(30^\circ\) at 3 pm, then falling to \(20^\circ\) at 6 pm. The steepest rise is from 9 am to 12 pm.

The slope of the line tells the story between the points.

BetweenChangeSlope
6 am – 9 am\(10\to15\)rising
9 am – 12 pm\(15\to25\)rising fast
3 pm – 6 pm\(30\to20\)falling
The steepest part changes fastest. The biggest jump between two points is the sharpest rise or fall.

How to interpret a line graph

  1. Find the time on the bottom axis.
  2. Read straight up to the point, then across to the scale for its value.
  3. Look at the slope: up is rising, down is falling.
  4. Subtract two readings to find how much it rose or fell.
Example 1 — Read a value
What was the temperature at 12 pm?
Solution

Read up from 12 pm to the point.

12 pm\(=\)\(25^\circ\)
Example 2 — Rise
How much did it rise from 6 am (\(10^\circ\)) to 3 pm (\(30^\circ\))?
Solution

Subtract the two readings.

\(30-10\)\(=\)\(20^\circ\)
Example 3 — Fall
The value drops from \(30^\circ\) at 3 pm to \(20^\circ\) at 6 pm. How big is the fall?
Solution

Subtract the later reading.

\(30-20\)\(=\)\(10^\circ\)
Example 4 — Steepest
Between which two times did the temperature rise fastest?
Solution

The steepest part is the biggest jump: \(15^\circ\) to \(25^\circ\).

9 am\(\to\)12 pm

Common pitfalls

Read to the point, not the peak. Go up from the time you were asked about, not to the highest point on the line.
A point between gridlines is a half. If a point sits midway between \(20\) and \(30\), the value is \(25\).
Change is a difference. To find how much it rose or fell, subtract the two readings.

Frequently asked questions

How do I read a value from a line graph?

Find the time on the bottom axis, read straight up to the point, then across to the scale. The number it lines up with is the value.

What does the slope of the line mean?

An upward slope means the value is rising, a downward slope means it is falling, and a flat line means it stays the same.

How do I find how much a value changed?

Subtract the two readings. The size of the rise or fall is the difference between the values at the two times.

Which part changes fastest?

The steepest part of the line. The biggest jump up or down between two points is where the value changes fastest.

Why use a line graph instead of a column graph?

A line graph is best for change over time, because joining the points shows how the value rises and falls between the readings.