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Curve Sketching - Revision Quiz 1
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Curve Sketching - Revision Quiz 1
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Curve Sketching - Revision Quiz 1
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Previewing
Curve Sketching - Revision Quiz 1
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Curve Sketching - Revision Quiz 1
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Curve Sketching - Revision Quiz 1
Question 6 of 13For the function \(y=x^4-2x^3\)
(i) Find the coordinates of the points where the curve crosses the axes
(ii) Find the coordinates of the stationary points and determine their nature
(iii) Find the coordinates of the points of inflection
(iv) Sketch the graph of \(f(x)\) clearly indicating the intercepts, stationary points, and points of inflection
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Curve Sketching - Revision Quiz 1
Question 7 of 13Consider the curve \(y = {x^4} - 8{x^2} + 16\)
(i) Show that \(\dfrac{{dy}}{{dx}} = 4x(x - 2)(x + 2)\)
(ii) Find the stationary points on the curve and determine their nature
(iii) Sketch the curve showing all intercepts on the axes and stationary points
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Curve Sketching - Revision Quiz 1
Question 8 of 13For the function \(p(x) = (x - 2)({x^2} + 1)\)
(i) find the coordinates of the turning points of \(p(x)\) and state their nature
(ii) Draw a sketch of \(y = p(x)\) in the domain \(0 \le x \le 3\)
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Curve Sketching - Revision Quiz 1
Question 9 of 13Consider the curve given by \(y = 3{x^4} - 12{x^3} + 12{x^2} + 2\)
(i) Find the coordinates of the stationary points
(ii) Find all values of \(x\) for which \(\dfrac{{{d^2}y}}{{d{x^2}}} = 0\)
(iii) Determine the nature of the stationary points
(iv) Sketch the curve in the domain \( - 1 \le x \le 3\)
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Curve Sketching - Revision Quiz 1
Question 10 of 13The adjacent diagram shows the sketch of \(y = {x^3} + 4{x^2} - 8\). The co-ordinates of the local maximum are?
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Curve Sketching - Revision Quiz 1
Question 11 of 13The adjacent diagram shows the sketch of \(y = 3{x^4} + 4{x^3} - 12{x^2} - 24x\). The co ordinates of the local maximum are ?
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Curve Sketching - Revision Quiz 1
Question 12 of 13The adjacent diagram shows the sketch of \(y = - {x^3} - {x^2} + 4x\). The co-ordinates of the point of inflection are?
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Curve Sketching - Revision Quiz 1
Question 13 of 13The gradient function of a curve is given by \(f^{\prime}(x)=3(x+1)(x-3)\) and the curve \(y=f(x)\) passes through the point \((0,12)\)
i) Find the equation of the curve \(y=f(x)\).
ii) Sketch the curve \(y=f(x)\), clearly labeling turning points and the \(y\) intercept.
iii) Assuming there is a point of inflexion at \(x=1\), determine the values of \(x\) for which the curve is concave up?
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