The velocity \(v\,{\rm{ m}}{{\rm{s}}^{ - 1}}\) at time t seconds \(\left( {t \ge 0} \right)\) of a body moving in a straight line is given by

\(v =2{t^2} + 2t - 12\). The acceleration when the velocity is zero is?

The displacement \(x\) m at time \(t\) seconds \(\left( {t \ge 0} \right)\) of a body moving in a straight line is given by \(x = 2{t^3} - 12{t^2} + 6\). The velocity when the acceleration is zero is?

A particle is moving along the \(x\) - axis. After \(t\) seconds its displacement \(x\) cm is given by \(x = t + 2 + \dfrac{1}{{t + 2}}\). The expression for its acceleration after \(t\) seconds is given by:

The displacement \(x\) m at time \(t\) seconds \(\left( {t \ge 0} \right)\) of a body moving in a straight line is given by \(x = 2{t^3} - 4{t^2} + 6t + 4\). The initial acceleration is?

An object moves in a straight line with velocity given by \(v(t) = 8{t^3} - 3{t^2}\) \(\text{ms}^{ - 1}\), where \(t\) is in seconds, \(t \ge 0\).

i) Find the acceleration function \(v'(t)\)

ii) Find the instaneous acceleration at 4 seconds.

The velocity function \(v(t)\) in \(\text{ms}^{ - 1}\) of a particle after \(t\) seconds is given by \(v(t) = {t^3} - 4{t^2} + 3t\). Fine the acceleration of the particle when \(t=2\).

Consider the adjacent velocity-time graph. (\(v(t)\) in \(cms^{−1}\)) From the graph find the instantaneous acceleration of the object for \(t = 2\) seconds.

The velocity function \(v(t)\) in \(ms^{−1}\) of a particle after \(t\) seconds is given by \(v(t) = \sqrt{16 − t^2}\). Find the acceleration of the particle when \(t = 2\).

An object moves in a straight line with a velocity given by; \(v(t) = 4{t^3} - 2{t^2}{\rm{ m}}{{\rm{s}}^{ - 1}}\), where \(t\) is in seconds,\(t \ge 0\).

The instantaneous acceleration after 2 seconds is?

An object moves in a straight line with a velocity given by; \(v(t) = {t^3} - {t^2} + t - 1{\rm{ m}}{{\rm{s}}^{ - 1}}\), where t is in seconds, \(t \ge 0\). The instantaneous acceleration after 1 second is?