Resources for Venn Diagrams
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Questions
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Video Tutorials
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Venn Diagrams Theory
![\textbf{Example}\\ Group A represents the number of people who play netball. which is \(8+3=11\)\\[3pt] Group B represents the number of people who play hockey. which is \(3+7=10\)\\[3pt] The number of people who play netball and hockey is 3.\\ There are 2 people who do not play netball or hockey.\\ The total number of people is \(8+3+7+2=20\)\\ \begin{center} \resizebox{0.3\textwidth}{!}{ \begin{tikzpicture}[very thick] \draw (2.7,-1.5) rectangle (-1.5,1.5) node[below right] {%$\bm{U}$ }; \draw (0,0) circle (1) node[above,shift={(-1,0.7)}] {A}; \draw (1.2,0) circle (1) node[above,shift={(1,0.7)}] {B}; \node at (.6,0) {3}; \node at (1.5,0) {7}; \node at (-.5,0) {8}; \node at (2.2,-1.2) {2}; \end{tikzpicture} } \end{center} \textbf{i)} Find the probability of randomly selecting a person who plays only netball.\\ \textbf{ii)} Find the probability of randomly selecting a person who plays netball and hockey\\ \textbf{iii)} Find the probability of randomly selecting a person who plays neither netball or hockey\\ \textbf{Example solution}\\ \textbf{i)} \(P(\text { only netball })=\dfrac{8}{20}=\dfrac{2}{5}\)\\[4pt] \textbf{ii)} \(P(\text { both })=\dfrac{3}{20}\)\\ \textbf{iii)} \(P(\text { neither })=\dfrac{2}{20}=\dfrac{1}{10}\)](/media/jhnbn4ki/9244.png)
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With Worked Solution2
Videos relating to Venn Diagrams.
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