Resources for The Number Plane
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Questions
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The Number Plane Theory
![\begin{minipage}[c]{9cm} If \(x\) is positive and \(y\) is positive then the point \(P(x, y)\) lies in the first quadrant (I)\\ If \(x\) is negative and \(y\) is positive then the point \(P(-x, y)\) lies in the second quadrant (II)\\ Th \(x\) is negative and \(y\) is negative then the point \(P(-x,-y)\) lies in the third quadrant (III)\\ If \(x\) is positive and \(y\) is negative then the point \(P(x,-y)\) lies in the fourth quadrant (IV) \end{minipage}\qquad \quad \begin{minipage}[c]{3cm} \begin{tikzpicture}[scale=0.8] \def \xmax{10} \def \xmin{-10} \def \ymax{10} \def \ymin{-10} \def \xlabel{x} \def \ylabel{y} \begin{axis}[ axis lines=middle, axis line style={shorten >=-10pt, shorten <=-10pt,very thick,Stealth-Stealth}, %grid=both, %major, major grid style={line width=1pt,draw=black!70}, minor x tick num=4, minor y tick num=4, ylabel = $y$, xlabel = $x$, width=3in, height=3in, ymin=\ymin, ymax=\ymax, xmin=\xmin, xmax=\xmax, axis on top=false, axis line style = thick, major tick style = thick, xtick distance = 1, xlabel style={at={(ticklabel* cs:1.05)},anchor=west}, x grid style={thin, opacity=1}, ytick distance = 1, ylabel style={at={(ticklabel* cs:1.05)},anchor=south}, y grid style={thin, opacity=1}, axis on top=false, minor xtick={-11,-10,...,10,11}, minor ytick={-11,-10,...,10,11}, xtick={-11,-10,-5,5,10,11}, ytick={-11,-10,-5,5,10,11}, nodes near coords style={ anchor=center, inner sep=0, color=black, font=,}, ] \addplot[ color=red, mark=*, mark size=0, only marks, nodes near coords, point meta=explicit symbolic, visualization depends on={value \thisrow{label} \as \label}, ] table[meta=label] { x y label -6 7 {2nd Quadrant} 6 7 {1st Quadrant} -6 -7 {3rd Quadrant} 6 -7 {4th Quadrant} }; \end{axis} \end{tikzpicture} \end{minipage} \begin{multicols}{2} \textbf{Example 1}\\ In which quadrants do the points lie\\ \textbf{i)} \(P(-1,3)\)\\ \textbf{ii)} \(Q(2,5)\)\\ \textbf{Example 1 solution}\\ \textbf{i)} \(x<0\) and \(y>0 \quad \therefore\) II\\ \textbf{ii)} \(x>0\) and \(y>0 \quad \therefore I\) \columnbreak \textbf{Example 2}\\ In which quadrants do the points lie\\ \textbf{i)} \(L(-1,-2)\)\\ \textbf{ii)} \(M(6,-3)\)\\ \textbf{Example 2 solution}\\ \textbf{i)} \(x<0\) and \(y<0 \quad \therefore\) III\\ \textbf{ii)} \(x>0\) and \(y<0 \quad \therefore\) IV \end{multicols}](/media/50tfrtrx/9860.png)
13
With Worked Solution1
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