Resources for Classifying Triangles
-
Questions
10
With Worked SolutionClick Here -
Video Tutorials
2
Click Here
Classifying Triangles Theory
![A triangle with:\\ \textbf{i)} No sides equal to each other is classified as scalene.\\ \begin{center} \begin{tikzpicture}[scale=0.8] \coordinate (O) at (0,0); \coordinate (A) at (60:2cm); \coordinate (B) at (right:3cm); \draw[line width=1pt] (O)--(B)--(A)--(O); \end{tikzpicture} \end{center} \textbf{ii)} Two sides equal and corresponding angles equal to each other is classified as isosceles.\\ It has one axis of symmetry.\\ \begin{center} \begin{tikzpicture}[scale=0.8] \coordinate (O) at (0,0); \coordinate (A) at (2,2); \coordinate (B) at (4,0); \coordinate (D) at ($(O)!(A)!(B)$); \draw[line width=1pt,dashed,shorten >=-10pt,shorten <=-10pt] (A)--(D); \draw[line width=1pt] (O)--(B)--(A)node[midway,sloped]{|}--(O)node[midway,sloped]{|}; \pic [draw=black,line width=1pt,angle radius=0.6cm,angle eccentricity=1.6,""] {angle=B--O--A}; \pic [draw=black,line width=1pt,angle radius=0.6cm,angle eccentricity=1,""] {angle=A--B--O}; \begin{scope}[shift=(B)] \path (135:0.75) arc (135:180:0.75) node[midway,sloped] {\(\|\)}; \end{scope} \begin{scope}[shift=(O)] \path (0:0.75) arc (0:45:0.75) node[midway,sloped] {\(\|\)}; \end{scope} \end{tikzpicture} \end{center} \textbf{iii)} Three sides equal and corresponding angles equal to each other is classified as equilateral.\\ It has three axes of symmetry and rotational symmetry of order 3.\\ \begin{center} \begin{tikzpicture}[scale=0.8] \coordinate (O) at (0,0); \coordinate (A) at (2,2.83); \coordinate (B) at (4,0); \coordinate (C) at ($(O)!(A)!(B)$); \coordinate (D) at ($(A)!0.5!(B)$); \coordinate (E) at ($(O)!0.5!(A)$); \draw[line width=1pt,dashed,shorten >=-10pt,shorten <=-10pt] (A)--(C); \draw[line width=1pt,dashed,shorten >=-10pt,shorten <=-10pt] (O)--(D); \draw[line width=1pt,dashed,shorten >=-10pt,shorten <=-10pt] (B)--(E); \draw[line width=1pt] (O)--(B)node[pos=0.45,sloped]{|}--(A)node[pos=0.45,sloped]{|}--(O)node[pos=0.45,sloped]{|}; \pic [draw=black,line width=1pt,angle radius=0.6cm,angle eccentricity=1.6,""] {angle=B--O--A}; \pic [draw=black,line width=1pt,angle radius=0.6cm,angle eccentricity=1,""] {angle=A--B--O}; \begin{scope}[shift=(B)] \draw (125:0.75) arc (125:180:0.75) node[pos=0.5,sloped] {\(\|\)}; \end{scope} \begin{scope}[shift=(O)] \draw (0:0.75) arc (0:55:0.75) node[pos=0.5,sloped] {\(\|\)}; \end{scope} \pic [draw=black,line width=1pt,angle radius=0.6cm,angle eccentricity=1,""] {angle=O--A--B}; \begin{scope}[shift=(A)] \draw (245:0.75) arc (245:305:0.75) node[pos=0.5,sloped] {\(\|\)}; \end{scope} \end{tikzpicture} \end{center} \textbf{iv)} A triangle that contains a \(90^{\circ}\) angle is classified as right-angled.\\ \begin{center} \begin{tikzpicture}[scale=0.8] \coordinate (O) at (0,0); \coordinate (A) at (0,3); \coordinate (B) at (3,0); \draw[line width=1pt] (O)--(B)--(A)--(O); \pic [draw=black,line width=1pt,angle radius=0.4cm,angle eccentricity=1.6,""] {right angle=B--O--A}; \end{tikzpicture} \end{center}](/media/5j4fk3xg/9214.png)
NSW Y8 Maths Geometry Classifying Triangles
Videos
Videos relating to Classifying Triangles.
-
Classifying Triangles - Video - Classifying Triangles 1
You must be logged in to access this resource -
Classifying Triangles - Video - Classifying Triangles 2
You must be logged in to access this resource
Plans & Pricing
With all subscriptions, you will receive the below benefits and unlock all answers and fully worked solutions.
-
Teachers TutorsFeaturesFreeProAll ContentAll courses, all topicsQuestionsAnswersWorked SolutionsSystemYour own personal portalQuizbuilderClass ResultsStudent ResultsExam RevisionRevision by TopicPractise ExamsAnswersWorked SolutionsAwesome StudentsFeaturesFreeProContentAny course, any topicQuestionsAnswersWorked SolutionsSystemYour own personal portalBasic ResultsAnalyticsStudy RecommendationsExam RevisionRevision by TopicPractise ExamsAnswersWorked Solutions