\(\textbf{26 g i)}\)
\begin{aligned}\text{By measurement}&\text{ AG is 8cm long}\\8 \text{ cm}&=24\text{ m} \\\therefore 1 \text{ cm}&= 3\text{ m}\end{aligned}
\(\textbf{26 g ii)}\)
\begin{aligned}\text{By measurement BA}&=3 \text{ cm}\\\therefore \text{Actual length} &=3 \times 3 \text{ m}=9 \text{ m}\\\text{By measurement BF} &=6 \text{ cm}\\\therefore \text{Actual length} &=6 \times 3 \text{ m}=18 \text{ m}\\\text{Area of ABFG}&= \frac{1}{2}\times 9 (18+24)\\&=189\text{ m}^2\\\text{Fertilizer }&= 189\times 26.5 \text{ g/m$^2$}\\&= 5008.5 \text{ g}\\&= 5.0085 \text{ kg}\\&= 5 \text{ kg}\end{aligned}
