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NSW HSC Maths - Standard 1

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Reverse Chain Rule

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Topics covered

  • Q 1 Integration (Year 12) - Reverse Chain Rule

    Year: 2019   Question: 11e
    References:

  • Q 2 Integration (Year 12) - Reverse Chain Rule

    Year: 2017   Question: 11b
    References:

  • Q 3 Integration (Year 12) - Reverse Chain Rule

    Year: 2016   Question: 11d
    References:
Question 1
HSC 2019 - Question 11e (External Link) Show Question
Answer

\(\frac{1}{{10}}\)

Worked Solution

\begin{aligned}\int_{0}^{1}(3 x+2)^{-2} d x &=\left[\frac{(3 x+2)^{-1}}{-1 \times 3}\right]_{0}^{1} \\&=\frac{1}{3}\left[\frac{1}{(3 x+2)}\right]_{1}^{0} \\&=\frac{1}{3}\left[\frac{1}{2}-\frac{1}{5}\right] \\&=\frac{1}{10}\end{aligned}

Question 2
HSC 2017 - Question 11b (External Link) Show Question
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Question 3
HSC 2016 - Question 11d (External Link) Show Question
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